ITT: everything physics.

REMEMBER: INSTEAD OF CREATING A NEW THREAD JUST FOR YOUR QUESTION - ASK IT HERE. Single question threads drown in like a day anyway.


I'll start.

I just began going through my undergrad nuclear physics course.
Am I right in understanding that:

> nuclei to the right of the maximum (pic related) have lower B/A because at that point Coulomb potential is very high so nucleus can be split into various combinations of ("strongest") nuclei with a limited loss of nuclear force potential since it's limited range, but with a big loss of net Coulomb potential, which makes it energetically economical
> nuclei to the left of the maximum have lower B/A since for nucleons closer to the surface there are less other nucleons to strongly interact with due to higher curvature?
> nuclei with minimal A numbers have lowest B/A due to some quantum stuff (what is it?)

> nuclear force between same nucleons is bigger than between different ones

> there are separate shells of stability for neutrons and protons in the nucleus?