>>10217530Through squeeze theorem, |sin1/x|<=1
Should 1/x converge from 0 to 1, so should | sin 1/x|
Therefore:
Integral of 0 to 1 of 1/x equals -lnx + C |(1 to 0), which equals limit when x approaches 0
-ln b (when b equals 0), it goes to an infinity.
It diverges, through Squeeze.
