/sci/ - Science & Math » Thread #10097359

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I solved P vs. NP

Anonymous Fri 26 Oct 17:08:20 2018 No.10097359 View Reply Original Report

Quoted By: >>10097363 >>10097405 >>10097443 >>10097462

> show that all functions can be represented by taylor series
> therefore all functions are polynomials
> NP is in P
Prove me wrong.

Anonymous

Anonymous Fri 26 Oct 2018 17:12:14 No.10097363 Report

Quoted By: >>10097371

>>10097359
yeah but weierstraB showed that there are functions that don't have derivatives so maybe if those are in NP we can't make a taylor series

Anonymous

Anonymous Fri 26 Oct 2018 17:14:28 No.10097371 Report

Quoted By:

>>10097363
So then instead of P vs. NP, it would be Derivable vs non-derivable?

Anonymous

Anonymous Fri 26 Oct 2018 17:33:18 No.10097397 Report

Quoted By: >>10097430 >>10097549 >>10098472

>P = NP
>1 = N*(P/P)
>1 = N
>Therefore P=P
Where is my Nobel pls

Anonymous

Anonymous Fri 26 Oct 2018 17:40:41 No.10097405 Report

Quoted By: >>10098906

>>10097359
The kth term of the Taylor series for exponential is x^k/k! So the Taylor series is a polynomial. But exp(x) is not a polynomial. Feelsbadman

Anonymous

Anonymous Fri 26 Oct 2018 18:05:23 No.10097430 Report

Quoted By:

>>10097397
Math shitposting = best shitposting

Anonymous

Anonymous Fri 26 Oct 2018 18:13:54 No.10097443 Report

Quoted By:

>>10097359
A Taylor series isn't a polynomial.

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Miniature Spacecraft Fri 26 Oct 2018 18:23:03 No.10097462 Report

Quoted By:

>>10097359
>I solved P vs. NP

Anonymous

Anonymous Fri 26 Oct 2018 19:12:53 No.10097549 Report

Quoted By:

>>10097397
$ \left\{ \begin{array}{l} P = NP\\ N = 1 \end{array} \implies P=P \right. $
check mate, atheists

Anonymous

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Anonymous Fri 26 Oct 2018 19:22:03 No.10097568 Report

Quoted By:

dumb frogposter, the problem has already been solved.

Anonymous

Anonymous Sat 27 Oct 2018 03:56:15 No.10098472 Report

Quoted By:

>>10097397
It baffles me how /sci/ still gets this joke proof wrong after 8 years.

Anonymous

Anonymous Sat 27 Oct 2018 08:38:43 No.10098806 Report

Quoted By: >>10098813

I don't know what P = NP is and I'm too lazy to look at the wikipedia page but is it related to the P-complete problems?

Anonymous

Anonymous Sat 27 Oct 2018 08:49:23 No.10098813 Report

Quoted By:

>>10098806
Yup.

Anonymous

Anonymous Sat 27 Oct 2018 10:12:56 No.10098906 Report

Quoted By:

>>10097405
U dumb? Exp(x) is literally an infinite polynomial.

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