## I solved P vs. NP

No.10097359 ViewReplyOriginalReport
Quoted By: >>10097363 >>10097405 >>10097443 >>10097462

> show that all functions can be represented by taylor series

> therefore all functions are polynomials

> NP is in P

Prove me wrong.

> therefore all functions are polynomials

> NP is in P

Prove me wrong.