/sci/ - Science & Math » Thread #14384196

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Any ideas?

Anonymous Mon 11 Apr 01:35:40 2022 No.14384196 View Reply Original Report

Quoted By: >>14384211 >>14384213 >>14384507

Anonymous

Anonymous Mon 11 Apr 2022 01:42:10 No.14384211 Report

Quoted By: >>14384237

>>14384196
you should have already seen it solved in a lecture.

Anonymous

Anonymous Mon 11 Apr 2022 01:42:15 No.14384213 Report

Quoted By: >>14384237

>>14384196
Your mom is a whore who doesnt love you.

$a^(-bx^2) = (a^b)^(-x^2)$

Make a^b similar to e^(nigger)

Use feynman's method
https://www.youtube.com/watch?v=Uv-4rZgmdXk&ab_channel=DrPeyam

Anonymous

Anonymous Mon 11 Apr 2022 01:42:43 No.14384216 Report

Quoted By: >>14384237

table of (gaussian) integrals. you'll find one with a quadratic exponent.

Anonymous

Anonymous Mon 11 Apr 2022 01:48:06 No.14384237 Report

Quoted By: >>14384287 >>14384500

>>14384211
>>14384213
>>14384216
dumb morons. it clearly doesn't converge for many values of a and b

Anonymous

Anonymous Mon 11 Apr 2022 02:04:30 No.14384287 Report

Quoted By: >>14384297

>>14384237
Your Mom is still a whore.

Anonymous

Anonymous Mon 11 Apr 2022 02:07:21 No.14384296 Report

Quoted By: >>14384308 >>14384357

$\sqrt{\frac{\pi}{b\log a}}$

Anonymous

Anonymous Mon 11 Apr 2022 02:07:42 No.14384297 Report

Quoted By: >>14384310

>>14384287
Your words are worthless since you've proven to be a dumbfuck. I'm also not OP, so you got even that wrong you fuckwit

Anonymous

Anonymous Mon 11 Apr 2022 02:09:53 No.14384308 Report

Quoted By: >>14384311

>>14384296
how?

Anonymous

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Anonymous Mon 11 Apr 2022 02:10:19 No.14384310 Report

Quoted By:

>>14384297
Ok nigger, lol.

Cope and seethe.

Anonymous

Anonymous Mon 11 Apr 2022 02:11:11 No.14384311 Report

Quoted By: >>14384314

>>14384308
a brain

Anonymous

Anonymous Mon 11 Apr 2022 02:12:31 No.14384314 Report

Quoted By:

>>14384311
I'll go buy a brain

Anonymous

Anonymous Mon 11 Apr 2022 02:32:35 No.14384357 Report

Quoted By: >>14384368 >>14384430 >>14384600

>>14384296
that only works for positive values of b & a

Anonymous

Anonymous Mon 11 Apr 2022 02:35:16 No.14384368 Report

Quoted By: >>14384399

>>14384357
Still a solution. Keep being a faggot

Anonymous

Anonymous Mon 11 Apr 2022 02:46:31 No.14384399 Report

Quoted By: >>14384406

>>14384368
not a solution, as the question clearly specifies that a and b are elements of R
"0" is not a solution to this problem, even though it works for specific values of a, and b

Anonymous

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Anonymous Mon 11 Apr 2022 02:49:49 No.14384406 Report

Quoted By: >>14384426

>>14384399
Dont care, you're still a faggot

>NO ITS NOT A SOLUTION, IT SAID ELEMENTS OF R YOU CANT DO THATTTTT

Anonymous

Anonymous Mon 11 Apr 2022 02:59:47 No.14384426 Report

Quoted By: >>14384438 >>14384461

>>14384406
>question clearly specifies domain
>give solution that only works for subset of this domain
>NO ITS STILL A SOLUTION!1!! IT DOESNT MATTER WHAT THE QUESTION ASKED

Anonymous

Anonymous Mon 11 Apr 2022 03:01:05 No.14384430 Report

Quoted By:

>>14384357
because the integral doesn't converge otherwise. obviously

Anonymous

Anonymous Mon 11 Apr 2022 03:02:52 No.14384438 Report

Quoted By:

>>14384426
>14384426
The question is dumb.

Riddle me this, nigger. What happens when a or b is 0, or negative? You get an integral of 0^0, imaginary numbers, or 2^x from 0 to infinity. It is impossible. Youre just being retarded.

Anonymous

Anonymous Mon 11 Apr 2022 03:15:45 No.14384461 Report

Quoted By: >>14384584

>>14384426
But if he wrote the solution as a union of constrained sets, you wouldn't have anything to bitch about.

Anonymous

Anonymous Mon 11 Apr 2022 03:54:34 No.14384500 Report

Quoted By:

>>14384237
>calls people morons
>doesn't even know the exact (AND OBVIOUS) cases it does not converge
lmao, kys. As long as the real part of the exponent's prefactor is negative, it converges. Cope, seethe, dilate.

Anonymous

Anonymous Mon 11 Apr 2022 03:59:12 No.14384507 Report

Quoted By:

>>14384196
$\int_{-\infty}^{\infty} \exp(-b\ln(a)x^2) dx$
Converges for all $\mathrm{Re}(b\ln(a)) > 0$ .

Anonymous

Anonymous Mon 11 Apr 2022 05:11:09 No.14384584 Report

Quoted By: >>14384600

>>14384461
I wouldn't, in fact that is how I would write up a solution to the problem.
But they didn't.

Anonymous

Anonymous Mon 11 Apr 2022 05:26:18 No.14384600 Report

Quoted By:

>>14384584
>>14384357
>that only works for positive values of b & a
That isn't even correct. You're a pedant, yet too stupid to even correctly assert the matter you are trying to be pedandic about. Pathetic.

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