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its not like you can prove your matr*x is correct

Anonymous Fri 02 Jul 15:58:27 2021 No.13351107 View Reply Original Report

Quoted By: >>13351120 >>13352320

i have a screen made of two variable, UV and a 3d space array of XYZ coordinates. i need to create a decent projection on UV screen based on XYZ coordinates to make a feel of perspective, either orthographic, isometric, as long as the 3d space is shown correctly.

How is the equation written and how do you come up with it? matrix or algebra, how do you infer your variabels, operands and data from to construct the correct projection?

Anonymous

Anonymous Fri 02 Jul 2021 16:01:33 No.13351120 Report

Quoted By: >>13351138

>>13351107
>How is the equation written and how do you come up with it? matrix or algebra, how do you infer your variabels, operands and data from to construct the correct projection?
how do you convert a 2d image into 3d? I mean, theres a limitless number of ways to do this

Anonymous

Anonymous Fri 02 Jul 2021 16:05:39 No.13351134 Report

Quoted By: >>13351139 >>13351144

https://en.wikipedia.org/wiki/3D_projection

or just map the XY to UV :^)

Anonymous

Anonymous Fri 02 Jul 2021 16:06:28 No.13351138 Report

Quoted By:

>>13351120
Wait yer asking me back?
>limitless
We should start somewhere basic i guess. Not a book. cuz thats big.

Anonymous

Anonymous Fri 02 Jul 2021 16:07:30 No.13351139 Report

Quoted By: >>13351172

>>13351134
>link
thats advanced but i keep it.
>map Xy to UV
explain "map to"

Anonymous

Anonymous Fri 02 Jul 2021 16:08:34 No.13351144 Report

Quoted By: >>13351167

>>13351134
wait XY to UV? what about the Z then?

Anonymous

Anonymous Fri 02 Jul 2021 16:12:52 No.13351160 Report

Quoted By:

the thread is gona be slow because brainlet takes ages to process actual problems

Anonymous

Anonymous Fri 02 Jul 2021 16:14:24 No.13351167 Report

Quoted By: >>13351174 >>13351329

>>13351144
well it would be an orthographic projection and you lose the z information, so don't worry about z ;^)

Anonymous

Anonymous Fri 02 Jul 2021 16:17:05 No.13351172 Report

Quoted By:

>>13351139
>explain "map to"
if you don't understand what this means you have no chance of making it. Seriously what are you even doing that you need to know this stuff and are asking questions like this?

re-read the wiki a few times and click some of the links to other pages when you find a topic or something else you don't understand. Also consider looking up tutorials on computer graphics from scratch.

Anonymous

Anonymous Fri 02 Jul 2021 16:17:23 No.13351174 Report

Quoted By:

>>13351167
...ah shit i mistook orthographic i guess.

Anonymous

Anonymous Fri 02 Jul 2021 16:27:20 No.13351198 Report

Quoted By: >>13351235

dude you ve been asking this for awhile you should at least know how much of brainlets 4chans are lol

Anonymous

Anonymous Fri 02 Jul 2021 16:39:29 No.13351235 Report

Quoted By:

>>13351198
heh, well i got no better ideas anyway

Anonymous

Anonymous Fri 02 Jul 2021 17:20:49 No.13351329 Report

Quoted By: >>13351380

>>13351167
what about perspective projection then? or oblique? how do you form the matrices from?

Anonymous

Anonymous Fri 02 Jul 2021 17:40:21 No.13351380 Report

Quoted By: >>13351393

>>13351329
check the wiki link ;^o

Anonymous

Anonymous Fri 02 Jul 2021 17:45:37 No.13351393 Report

Quoted By:

>>13351380
..there are formulations but i am not sure i catch how they are built. seems like theyve been pre defined from something...

Anonymous

Anonymous Fri 02 Jul 2021 17:54:39 No.13351416 Report

Quoted By: >>13351434 >>13351486 >>13351514 >>13351521

Take a look at "Burgers vectors" in crystallography.
I remember doing something similar in my Materials engineering classes

Anonymous

Anonymous Fri 02 Jul 2021 18:01:01 No.13351434 Report

Quoted By:

>>13351416
this? https://en.m.wikipedia.org/wiki/Burgers_vector

the image make sense but the whole mathemathics are just... completely foreign

Anonymous

Anonymous Fri 02 Jul 2021 18:13:36 No.13351486 Report

Quoted By:

>>13351416
its completely useless to this

Anonymous

Anonymous Fri 02 Jul 2021 18:19:59 No.13351514 Report

Quoted By: >>13351521

>>13351416
It's really impressive how he'll take a problem with tons of material, ignore said material, and then post an image relating to an entirely different field of study whilst saying he doesn't get it.

Anonymous

Anonymous Fri 02 Jul 2021 18:22:08 No.13351521 Report

Quoted By:

>>13351416
>>13351514
you two arent making much sense
is this a prank
cuz if it is its a fuckin waste of time

Anonymous

Anonymous Fri 02 Jul 2021 22:13:44 No.13352320 Report

Quoted By: >>13352329 >>13352412 >>13352624 >>13352682

>>13351107
To project an XYZ coordinate onto UV coordinates in 3D, you have to represent them as column vectors and multiply the column vector you want to project by three different 4x4 matrices (NOT commutative, see bellow).
$\begin{pmatrix} u\\ v\\ w \\ 1 \end{pmatrix} = M_\text{projection}\cdot M_\text{view}\cdot M_\text{model} \cdot \begin{pmatrix}x\\ y\\ z\\ 1\end{pmatrix}$

Now listen carefully you STUPID FAGGOT because I need you to learn how to multiply a matrix with a column vector.
Do you see this?
$ \begin{pmatrix} u\\ v\\ w\\ q \end{pmatrix} = \begin{pmatrix} a & b & c & d\\ e & f & g & h\\ i & j & k & l\\ m & n & o & p \end{pmatrix} \begin{pmatrix}x\\ y\\ z\\ t\end{pmatrix} $
That means this:
$u = ax + by + cz + dt\\ v = ex + fy + gz + ht\\ w = ix + jy + kz + lt\\ q = mx + ny + oz + pt$
How do you obtain this? Simple. You take $(x, y, z, t)$ and you attach it on every row in the matrix. For example, $(x, y, z, t)$ and $(a, b, c, d)$ would make $ax + by + cz + dt$ . This operation is called a linear combination and doing so on every row is called matrix multiplication.
NOTE: We don't give a shit about w and q, only u and v.
NOTE: A lot of elements in the matrix are going to be 0 so A LOT of stuff is going to cancel.
NOTE: Matrix multiplication is associative but NOT commutative. If you have U = A*B*C*X, it doesn't matter what you multiply first and what second but order matters you CANNOT permute it like say U = B*A*C*X.

1/?

Anonymous

Anonymous Fri 02 Jul 2021 22:14:41 No.13352329 Report

Quoted By: >>13352333 >>13352412 >>13352682

>>13352320
>What is an identity matrix????
An identity matrix $I$ is what you start with. An identity matrix is the one with 0s every where, except on the diagonal which has 1s.
When you multiply this matrix with something nothing changes. Why? Take a look:
$ \begin{pmatrix} x'\\ y'\\ z'\\ t' \end{pmatrix} = \begin{pmatrix} 1 & 0 & 0 & 0\\ 0 & 1 & 0 & 0\\ 0 & 0 & 1 & 0\\ 0 & 0 & 0 & 1 \end{pmatrix} \cdot \begin{pmatrix}x\\ y\\ z\\ t\end{pmatrix} $
This results in:
$ \begin{align*} x' &= 1\cdot x + 0\cdot y + 0\cdot z + 0\cdot t\\ y' &= 0\cdot x + 1\cdot y + 0\cdot z + 0\cdot t\\ z' &= 0\cdot x + 0\cdot y + 1\cdot z + 0\cdot t\\ t' &= 0\cdot x + 0\cdot y + 0\cdot z + 1\cdot t \end{align*} $
Which means x'=x y'=y z'=z t'=t therefore:
$ \begin{pmatrix} x'\\ y'\\ z'\\ t' \end{pmatrix} = \begin{pmatrix} x\\ y\\ z\\ t \end{pmatrix} $
So nothing happened, as if you never multiplied it with an identity matrix at all.
Loading an identity matrix with glLoadItentity() means you clear everything (all types of projections, view transformations, translations, rotations, scalings etc.) and start a transformation anew.

2/?

Anonymous

Anonymous Fri 02 Jul 2021 22:15:08 No.13352333 Report

Quoted By: >>13352345 >>13352412 >>13352682

>>13352329
>What is a projection matrix????
There are two types of projections you can yourself with: Orthographic and Perspective.
Their OpenGL functions are:
glOrtho(left, right, top, bottom, near, far)
gluPerspective(aspect, fov, near, far)

In gluPerspective:
>Fov is your field of view, e.g. 60 degrees (or pi/3 in radians).
>Aspect ratio is (idealy) your Screen width / Screen height.
>Near and Far can be something like 1 and 1000 respectively.
>Near should be small but NOT zero
>Far should be large, but not too large or there is going to be a loss of precision.

In glOrtho:
>(left, right, top, bottom) should be 0, screen width, 0, screen height)
>Near and Far can be something like 1 and 1000 (small and large) respectively.

Their matrices are:
$ M_\text{projection}^\text{ortho} = \begin{pmatrix} \frac{2}{right - left} & 0 & 0 & \frac{left + right}{left - right}\\ 0 & \frac{2}{top - bottom} & 0 & \frac{bottom + top}{bottom - top}\\ 0 & 0 & \frac{-2}{far - near} & \frac{near + far}{near - far}\\ 0 & 0 & 0 & 1 \end{pmatrix} $

$ M_\text{projection}^\text{perspective}= \begin{pmatrix} \frac{1}{\text{aspect}\cdot\tan\frac{\text{fov}}{2}} & 0 & 0 & 0 \\ 0 & \frac{1}{\tan\frac{\text{fov}}{2}} & 0 & 0\\ 0 & 0 & \frac{near + far}{near - far} & \frac{2\cdot near\cdot far}{near - far}\\ 0 & 0 & -1 & 0 \end{pmatrix} $

Alternative to gluPerspective is glFrustum which also defines the same perspective projection by the defining the dimensions of a "cut-off pyramid" (a shape called a frustum) which has arguments similar to glOrtho
glFrustum(left, right, bottom, top, near, far)
$ M_\text{projection}^\text{frustum}= \begin{pmatrix} \frac{2\cdot near}{right - left} & 0 & \frac{right + left}{right - left} & 0\\ 0 & \frac{2near}{top - bottom} & \frac{top + bottom}{top - bottom} & 0\\ 0 & 0 & \frac{far + near}{far - near} & \frac{2\cdot far\cdot near}{far - near} \end{pmatrix} $

3/?

Anonymous

Anonymous Fri 02 Jul 2021 22:16:19 No.13352345 Report

Quoted By: >>13352350 >>13352412 >>13352682

>>13352333
>What is a view matrix???
A view matrix specifies how to transform a point in relation to the camera. You can use translation, rotation, scaling matrices to accomplish this or you can use gluLookAt:
gluLookAt(px, py, pz, cx, cy, cz, ux, uy, uz);
>p - Point at which the camera is looking at
>c - Camera location
>u - Camera rotation i.e. where is "up?" (like, filming horizontally or vertically)

A matrix for gluLookAt is:
$ f=p-c\\ s=\hat{f} \times \hat{u}\\ r=\hat{s} \times \hat{f} $
$M_\text{view}^\text{lookAt}=\begin{pmatrix}s_x&s_y&s_z&0\\r_x&r_y&r_z&0\\-f_x&-f_y&-f_z&0\\0&0&0&1\end{pmatrix}$

To understand f, s and r equations your retarded ASS needs to learn some vector operations too:
>adding and subtracting vectors
$a\pm b=\begin{pmatrix}a_x\\a_y\\a_z\\1\end{pmatrix}\pm\begin{pmatrix}b_x\\b_y\\b_z\\1\end{pmatrix}=\begin{pmatrix}a_x\pm b_x\\a_y\pm b_y\\a_z \pm b_z\\1\end{pmatrix}$

>vector magnitude (a.k.a. length)
Using pytagorean theorem:
$\left \| a \right \| = \left \| \begin{pmatrix}a_x\\a_y\\a_z\\1\end{pmatrix} \right \| = \sqrt{a_x^2 + a_y^2 + a_z^2}$
Or using dot product (cause cos = 1)
$||a|| = \sqrt{a\cdot a}$

>vector normalization
Means making its magnitude between 0 and 1, accomplished by dividing x,y,z with length.
$\hat{a}=\begin{pmatrix}a_x / ||a||\\a_y / ||a||\\a_z / ||a||\\1\end{pmatrix}$

>dot product
$a\cdot b=\begin{pmatrix}a_x\\a_y\\a_z\\1\end{pmatrix}\cdot\begin{pmatrix}b_x\\b_y\\b_z\\1\end{pmatrix}=a_x b_x + a_y b_y +a_z b_y$
Another equation (can be used to find angle between two vectors):
$a\cdot b=||a||||b||\cos\measuredangle(a,b)$

>cross product
$a\times b=\begin{pmatrix}a_x\\a_y\\a_z\\1\end{pmatrix}\times\begin{pmatrix}b_x\\b_y\\b_z\\1\end{pmatrix}=\begin{pmatrix}a_yb_z - a_zb_y\\ a_xb_z - a_zb_x\\a_xb_y - a_yb_z\\1\end{pmatrix}$
Another equation (but for magnitude only):
$||a\times b|| = ||a||||b||\sin\measuredangle (a, b)$

4/?

Anonymous

Anonymous Fri 02 Jul 2021 22:17:09 No.13352350 Report

Quoted By: >>13352356 >>13352412 >>13352682

>>13352345
>What is a model matrix??????
A model matrix is three more matrices: translation, rotation and scaling matrices (order matters here)
$M_\text{model} = M_\text{translate}\cdot M_\text{rotate}\cdot M_\text{scale}$

Scaling transformation inflates the point away from the origin (0, 0, 0).
You are obviously retarded if you put zero for sx, sy, sz values cause then the point will become one with the origin point.
The scaling matrix looks like an identity matrix, except the diagonal is different from 1 (clearly if sx, sy, sz are 1 then no scaling occurs and it's like you multiplied it with an identity matrix)
$ M_\text{model}^\text{scale} = \begin{pmatrix} s_x & 0 & 0 & 0\\ 0 & s_y & 0 & 0\\ 0 & 0 & s_y & 0\\ 0 & 0 & 0 & 1 \end{pmatrix} $

Translation transformation moves a point somewhere away from the origin.
Translation matrix looks like an identity matrix too except translation coordinates are embedded to the right.
$ M_\text{model}^\text{translate} = \begin{pmatrix} 1 & 0 & 0 & t_x\\ 0 & 1 & 0 & t_y\\ 0 & 0 & 1 & t_z\\ 0 & 0 & 0 & 1 \end{pmatrix} $

5/?

Anonymous

Anonymous Fri 02 Jul 2021 22:18:18 No.13352356 Report

Quoted By: >>13352364 >>13352412 >>13352682

>>13352350
Now because you are STUPID let me demonstrate to you what happens when you multiply a scaling matrix with a vector:
$\begin{pmatrix} x'\\y'\\z'\\1 \end{pmatrix} = \begin{pmatrix} s_x & 0 & 0 & 0\\ 0 & s_y & 0 & 0\\ 0 & 0 & s_z & 0\\ 0 & 0 & 0 & 1 \end{pmatrix} \cdot \begin{pmatrix} x\\y\\z\\1 \end{pmatrix} = \begin{pmatrix} s_x x + 0 + 0 + 0\\ 0 + s_y y + 0 + 0\\ 0 + 0 + s_z z + 0\\ 0 + 0 + 0 + 1 \end{pmatrix} = \begin{pmatrix} s_xx\\ s_yy\\ s_zz\\ 1 \end{pmatrix} $
Do you see how this produced these simple scaling equations??
$\begin{align*} x' &= s_xx\\ y' &= s_yy\\ z' &= s_yy\\ \end{align*}$
Now let me show you what happens when you multiply the translation matrix with that:
$ \begin{pmatrix} x''\\ y''\\ z''\\ 1 \end{pmatrix}= \begin{pmatrix} 1 & 0 & 0 & t_x\\ 0 & 1 & 0 & t_y\\ 0 & 0 & 1 & t_z\\ 0 & 0 & 0 & 1 \end{pmatrix} \cdot \begin{pmatrix} s_xx\\ s_yy\\ s_zz\\ 1 \end{pmatrix} = \begin{pmatrix} s_xx + 0 + 0 + t_x\\ 0 + s_yy + 0 + t_y\\ 0 + 0 + s_zz + t_z\\ 0 + 0 + 0 + 1 \end{pmatrix} = \begin{pmatrix} s_xx + t_x\\ s_yy + t_y\\ s_zz + t_z\\ 1 \end{pmatrix} $
Do you see how this just adds tx, ty and tz??
$ \begin{align*} x'' &= s_xx + t_x\\ y'' &= s_yy + t_y\\ z'' &= s_yy + t_z\\ \end{align*} $
Do you see how matrix multiplication works now??
Do you understand that every matrix I've shown so far does something like this??

6/?

Anonymous

Anonymous Fri 02 Jul 2021 22:19:54 No.13352364 Report

Quoted By: >>13352369 >>13352412 >>13352682

>>13352356
Rotation transformation rotates a point around the origin.
Rotation matrix is three more matrices for rotation around each axis:
$M_\text{model}^\text{rotate} = R_z(\theta_x)\cdot R_y(\theta_y)\cdot R_x(\theta_z)$
Their matrices are like the identity matrix except with sin/cos embedded around the axis that you want to rotate about:
$ R_x(\theta_x) = \begin{pmatrix} 1 & 0 & 0 & 0\\ 0 & \cos\theta_x & -\sin\theta_x & 0\\ 0 & \sin\theta_x & \cos\theta_x & 0\\ 0 & 0 & 0 & 1 \end{pmatrix} $
$ R_y(\theta_y) = \begin{pmatrix} \cos\theta_y & 0 & \sin\theta_y & 0\\ 0 & 1 & 0 & 0\\ -\sin\theta_y & 0 & \cos\theta_y & 0\\ 0 & 0 & 0 & 1 \end{pmatrix} $
$ R_z(\theta_z) = \begin{pmatrix} \cos\theta_z & -\sin\theta_z & 0 & 0\\ \sin\theta_z & \cos\theta_z & 0 & 0\\ 0 & 0 & 1 & 0\\ 0 & 0 & 0 & 1 \end{pmatrix} $

Because these fuckers produce a problem called a gimbal lock (due to the fact it's unclear which order ) there is another type of rotation called quaternion rotation which allows you to rotate around all three axises at the same time.
Instead of just x-axis, y-axis or z-axis, let's say you want to rotate around an axis $(a_x, a_y, a_z)$ by angle $\theta$ .

First what you do is make a quaternion $q = w + x\mathbf{i} + y\mathbf{j} + z\mathbf{k}$ with the following parameters:
$ w = \cos\frac{\theta}{2}\\ x = \frac{a_x}{||a||}\sin\frac{\theta}{2}\\ y = \frac{a_y}{||a||}\sin\frac{\theta}{2}\\ z = \frac{a_z}{||a||}\sin\frac{\theta}{2} $

Then what you do is put those parameters in the following rotation matrix:
$ R_q(\theta) = \begin{pmatrix} w + x - y - z &2xy-2wz&2xz+2wy&0\\ 2xy+2wz&w-x+y-z&2yz-2wx&0\\ 2xz-2wy&2yz+2wx&w-x-y+z&0\\ 0&0&0&1 \end{pmatrix} $

How do you use any of these to rotate a point around an origin?? You use it like any other transformation matrix.
$\begin{pmatrix}x'\\y'\\z'\\1\end{pmatrix} = R(\theta)\cdot \begin{pmatrix}x\\y\\z\\1\end{pmatrix}$

7/?

Anonymous

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Anonymous Fri 02 Jul 2021 22:20:40 No.13352369 Report

Quoted By: >>13352387 >>13352412 >>13352671 >>13352682

>>13352364
Overall
$\begin{pmatrix}u\\v\\w\\1\end{pmatrix} = M_\text{projection}\cdot M_\text{view}\cdot \underbrace{T\cdot R\cdot S}_{M_\text{model}} \begin{pmatrix}x\\y\\z\\1\end{pmatrix}$

$M_\text{projection}$ is either $M_\text{ortho}$ , $M_\text{perspective}$ or $M_\text{frustum}$ which I wrote about (using identity matrix here makes an orthographic projection where the screen is 1x1).

$M_\text{view}$ is either $T_\text{camera}\cdot R_\text{camera}\cdot S_\text{camera}$ or $M_\text{lookAt}$ which I also wrote about. (using identity matrix here places the camera at origin usually looking towards at z+ axis, depending on perspective matrix settings).

$T$ is the translation matrix $T(t_x, t_y, t_z)$

$R$ is the rotation matrix which is either $R_x(\theta)$ , $R_y(\theta)$ , $R_z(\theta)$ , all three combined $R_z(\theta_z)\cdot R_x(\theta_x)\cdot R_y(\theta_y)$ , or quaternion rotation $R_q(a, \theta)$

$S$ is the scaling matrix $S(s_x, s_y, s_z)$ .

Every single one of these is a 4x4 matrix that eventually ends up transforming the vector $(x, y, z, 1)$ in some way to project it to $(u, v, w, 1)$

Now before you make a YET ANOTHER thread, I want YOU to buy a 50 cent notebook and practice multiplying these fuckers together before I see you ever make another one of these threads.
*IF*, and I say *IF*, I ever see you make another thread and it DOESN'T contain a picture of your notebook with matrix algebra on it, I am going to KILL YOU in Fortnite.

8/8

Anonymous

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Anonymous Fri 02 Jul 2021 22:23:56 No.13352387 Report

Quoted By:

>>13352369

Anonymous

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Anonymous Fri 02 Jul 2021 22:30:26 No.13352412 Report

Quoted By:

>>13352320
>>13352329
>>13352333
>>13352345
>>13352350
>>13352356
>>13352364
>>13352369
Heckin based effort posts

Anonymous

Anonymous Fri 02 Jul 2021 23:32:20 No.13352624 Report

Quoted By:

>>13352320
Sorry just woke up.
Effort post, noble prize, but can we just start with why
$ u=ax+by+cz+dtv=ex+fy+gz+htw=ix+jy+kz+ltq=mx+ny+oz+pt$
Don't worry i will go through all of them too one by one.

Anonymous

Anonymous Fri 02 Jul 2021 23:34:30 No.13352632 Report

Quoted By: >>13352704

sorry i mean

$ u=ax+by+cz+dt v=ex+fy+gz+ht w=ix+jy+kz+lt q=mx+ny+oz+pt $

why this...model?
how is this found?

Anonymous

Anonymous Fri 02 Jul 2021 23:43:43 No.13352671 Report

Quoted By:

>>13352369
fuck i swear this is impossible to learn online by just typing like an idiot

Anonymous

Anonymous Fri 02 Jul 2021 23:46:28 No.13352682 Report

Quoted By: >>13352716

>>13352320
>>13352329
>>13352333
>>13352345
>>13352350
>>13352356
>>13352364
>>13352369
i hope your answer isnt in vain but i suspect OP will create a similar thread tomorrow

Anonymous

Anonymous Fri 02 Jul 2021 23:52:52 No.13352704 Report

Quoted By: >>13352716

>>13352632
Oh my fucking God, learn what a linear transformation is, for the love of Christ.

Anonymous

Anonymous Fri 02 Jul 2021 23:58:13 No.13352716 Report

Quoted By:

>>13352682
>another thread
omfg, no thanks. this is a big fat retarded linkblasting, here s a noble prize, which we have done before again and again, without no clarity on small tiny things i kept asking and asking AGAin
>>13352704
so what about linear transformation?
what exactly do you linearly transform AGAIN? you gonna linkblasting something completely vague anyway to avoid showing off how much of a retard you are?

Anonymous

Anonymous Sat 03 Jul 2021 00:01:16 No.13352728 Report

Quoted By:

i mean... w+x-y-z? wtf is that from?

sighhhhhhhhhhhhhhh

Anonymous

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Anonymous Sat 03 Jul 2021 00:07:00 No.13352749 Report

Quoted By: >>13352767

>Again, the proof follows easily from definitions is left to the reader.
Oh no no no no no.... OP BTFO.

Anonymous

Anonymous Sat 03 Jul 2021 00:13:45 No.13352767 Report

Quoted By:

>>13352749
>how do you INFER your variabels, operands and data from to construct the correct projection?
>INFER
>CONSTRUCT
read

Anonymous

Anonymous Sat 03 Jul 2021 00:15:16 No.13352769 Report

Quoted By: >>13352788

im so done here

thanks 4chan for forcing me to reinvent so much

Anonymous

Anonymous Sat 03 Jul 2021 00:21:44 No.13352788 Report

Quoted By: >>13352815 >>13353328 >>13353797

>>13352769
Reinventing would require effort, which you haven't demonstrated

Anonymous

Anonymous Sat 03 Jul 2021 00:34:52 No.13352815 Report

Quoted By:

>>13352788
whatever, this place has done enough and i guess even stackoverflow will have tons of unworkable and midrange solutions...

Anonymous

Anonymous Sat 03 Jul 2021 03:20:37 No.13353328 Report

Quoted By: >>13354120

>>13352788
also you dont have what i need

Anonymous

Anonymous Sat 03 Jul 2021 08:00:36 No.13353797 Report

Quoted By:

>>13352788
what is linear tranformmmm

Anonymous

Anonymous Sat 03 Jul 2021 10:04:38 No.13354120 Report

Quoted By: >>13354372

>>13353328
UV are the fucking texture coordinates, not the screen coordinates. What the fuck are you talking about?

Anonymous

Anonymous Sat 03 Jul 2021 11:56:38 No.13354372 Report

Quoted By:

>>13354120
....i use this for screen with U as horizontal and V as vertical i guess. Sorry i made that up cuz its conveniently similar

Anonymous

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Anonymous Sat 03 Jul 2021 15:01:21 No.13354888 Report

Quoted By:

ITT: intelligent and well-intentioned anons taking the bait and trying to help an ill-intention idiot.

this thread has gone on long enough.
this OP has been spamming threads like this on /sci/, /g/, /wsr/ and god knows else where for a month now.
they create 2-5 threads in the span of minutes that are all essentially duplicates of themselves.
this is like thread 100.

to future anons, just hide this thread. OPs been given all he needs multiple times over. if you can't tell by now in this thread, you are wasting your time wasting your time.

i specifically create pic related because OP is such a titanic insufferable flaming faggot.

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