in the last thread we concluded that 1 != 0
now I know this was VERY impressive and that I should take a break, but I will now prove that 1 != 2
Now firstly by definition using penis axioms 1 != 2.
Good.
But many people look at hitomi and laugh
>uhhhh hurr durr this is dumb cuz uhhhh like that implies 1 = 2
>durr 0*h = 1 => 2*0*h = 2*1 given x*2 = 0, uhhhh durr then 0*h = 2 durr 1 = 2
the elementary return of 0*h is E[0*h] = E[1]
the Hitomi return is H[0*h] = H[1] = 0
This is because elementary numbers aren't Hitomi numbers so evaluating the Hitomi return of one is 0.
it's the same idea for a complex number z = 2 + 0i, Re(z) = 2, Im(z) = 0
you violate the idea of equivalence by multiplying two on both sides because you're you're comparing the Asuka field to the elementary one, where [2*0*h] is not an equivalent operation because the two is inside the field the equila statement is 2*[h*0] = [h*0] + [h*0], since h*0 is the definition of a unitary object.
otherwise 2 = 1 would be a restatement saying 2 is the unitary object.
ergo 0/0 = 1, but 1 != 0 or 2
This is all a work in progress.