/sci/ - Science & Math » Thread #13329273

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Anonymous Sun 27 Jun 04:31:41 2021 No.13329273 View Reply Original Report

Quoted By: >>13329307 >>13329752

How do you even go about proving this

Anonymous

Anonymous Sun 27 Jun 2021 04:38:22 No.13329298 Report

Quoted By: >>13329388 >>13329752

literally just evaluate $\lim_{n\to\infty}1-2^{-n}$

Anonymous

Anonymous Sun 27 Jun 2021 04:40:49 No.13329307 Report

Quoted By: >>13329388 >>13329665 >>13329752

>>13329273
For every epsilon > 0 find an explict N such that for n > N
| 1 - 2^(-n) - 1| < epsilon

It should be quiet easy if you have already learned about logarithms.

Anonymous

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Anonymous Sun 27 Jun 2021 05:22:35 No.13329388 Report

Quoted By: >>13329665

>>13329298
>>13329307
thanks. Does anyone know any related proof/thm for this one

Anonymous

Anonymous Sun 27 Jun 2021 07:39:51 No.13329665 Report

Quoted By:

>>13329307
>logarithms
That will get the exact minimum N, but you can skip the logarithm if you want and just get a bigger N.
>>13329388
For this I would use the definition of converging sequence, and the definition of series from OP.

Anonymous

Anonymous Sun 27 Jun 2021 08:28:41 No.13329752 Report

Quoted By:

>>13329298
>>13329307
don't do his homework

>>13329273
just review the lecture notes anon, it will get much harder later on

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