/sci/ - Science & Math » Thread #13283755

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Anonymous Wed 16 Jun 09:48:13 2021 No.13283755 View Reply Original Report

Quoted By: >>13283756 >>13283757 >>13283862 >>13283869 >>13284105 >>13285126 >>13285204

ill paypal anyone 30$ for telling me

the open circuit voltage
the open circuit resistance
the Load current
The voltage across the load
the maximum power transfer to the load

Anonymous

Anonymous Wed 16 Jun 2021 09:49:24 No.13283756 Report

Quoted By:

>>13283755
This is fucking easy bro and it’s laughable you’re asking for help on here. EE wasn’t as easy as you thought it would be huh?

Anonymous

Anonymous Wed 16 Jun 2021 09:51:32 No.13283757 Report

Quoted By:

>>13283755
anon get your shit together it's literally filling in basic formulas

Anonymous

Anonymous Wed 16 Jun 2021 09:55:43 No.13283763 Report

Quoted By: >>13283780

OP here litterally will never need this, my education requires electronics for no reason whatsoever. it prolly is easy, but is it 30$ easy?

Anonymous

Anonymous Wed 16 Jun 2021 10:02:24 No.13283780 Report

Quoted By:

>>13283763
fuck it give me your discord i'll do it

Anonymous

Anonymous Wed 16 Jun 2021 10:51:07 No.13283862 Report

Quoted By:

>>13283755
thorium just doesn't work, try uranium

Anonymous

Anonymous Wed 16 Jun 2021 10:55:25 No.13283869 Report

Quoted By:

>>13283755
rtot 100 + 470*1047/1517
itot 5/rtot

Anonymous

Anonymous Wed 16 Jun 2021 12:31:49 No.13284105 Report

Quoted By:

>>13283755
http://falstad.com/circuit/circuitjs.html

edit: thanks for the gold kind stranger!

Anonymous

Anonymous Wed 16 Jun 2021 13:22:59 No.13284223 Report

Quoted By:

you will never, ever be an engineer if this is the kind of shit that stumps you
embarrassing, anon

Anonymous

Anonymous Wed 16 Jun 2021 18:41:44 No.13285126 Report

Quoted By:

>>13283755
>first semester shitter pissing the floor about basic EE stuff

which resistance is supposed to be the load?

Anonymous

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Anonymous Wed 16 Jun 2021 19:03:24 No.13285204 Report

Quoted By:

>>13283755
$ R_{GES} = R_1 + R_3 || (R_2+R_4) = 100 + \frac{470*(47+1000)}{470+47+1000} \Omega \\ I_1 = I_2 + I_3\\ I_1 = \frac{U_4}{R_{GES}}\\ I_2 = \frac{(R_2 + R_4)}{R_3 || (R_2 + R_4)}*I_1 = \frac{47+470+1000}{470}*I_1\\ I_3 = \frac{R_3}{R_3 || (R_2 + R_4)}*I_1 = \frac{47+470+1000}{47+1000}*I_1 $

if you want the voltages then just use

$ U = R*I $

for the individual resistor

if you want the power then use

$ P = U*I\\ P = R*I^2\\ P = U^2/R $

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