/sci/ - Science & Math » Thread #13131720

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Anonymous Fri 14 May 21:14:37 2021 No.13131720 View Reply Original Report

Quoted By: >>13131792 >>13131826 >>13132226 >>13132262 >>13133238 >>13133406 >>13133426 >>13133463 >>13133600 >>13133629 >>13134135 >>13134153 >>13136552 >>13137221 >>13138763

Post a more aesthetic equation. Top tip: you can't.

Anonymous

Anonymous Fri 14 May 2021 21:18:42 No.13131742 Report

Quoted By: >>13131755 >>13132070 >>13132821

$P(OP)_{fag} = 1$

Anonymous

Anonymous Fri 14 May 2021 21:20:26 No.13131755 Report

Quoted By:

>>13131742
You're just jealous.

Anonymous

Anonymous Fri 14 May 2021 21:28:11 No.13131790 Report

Quoted By: >>13131803

$\dfrac{1}{1-x}=\sum_{n=0}^\infty x^n$

Anonymous

Anonymous Fri 14 May 2021 21:28:50 No.13131792 Report

Quoted By: >>13132226 >>13136918

>>13131720
what is it?

Anonymous

Anonymous Fri 14 May 2021 21:32:04 No.13131803 Report

Quoted By:

>>13131790
Very aesthetic and very nice for combinatorics, but what about
$ (x+1)^n = \sum_{k=0}^\infty {{(n)_k \over k!}x^k} $
since you can derive it from that

El Cabrón

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El Cabrón Fri 14 May 2021 21:34:10 No.13131816 Report

Quoted By: >>13132826

For me, it’s picrel.

Anonymous

Anonymous Fri 14 May 2021 21:35:33 No.13131826 Report

Quoted By:

>>13131720
Looks horrendous

Anonymous

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Anonymous Fri 14 May 2021 21:42:38 No.13131875 Report

Quoted By:

Anonymous

Anonymous Fri 14 May 2021 22:19:09 No.13132070 Report

Quoted By:

>>13131742
fpbp

Anonymous

Anonymous Fri 14 May 2021 22:53:29 No.13132226 Report

Quoted By:

>>13131792
>>13131720
Paris crack law I think, used in engineering to find the number of loading cycles required to grow a crack in a material from length a_0 to length a_c

Anonymous

Anonymous Fri 14 May 2021 23:01:53 No.13132262 Report

Quoted By:

>>13131720
IEEEuler's formula
$e^{i\pi} + 1^{\text{NaN}\infty} = 0$

Anonymous

Anonymous Sat 15 May 2021 01:35:38 No.13132821 Report

Quoted By:

>>13131742
fpbp

Anonymous

Anonymous Sat 15 May 2021 01:37:31 No.13132826 Report

Quoted By: >>13133197

>>13131816
>el faggót

El cAbrón

El cAbrón Sat 15 May 2021 03:31:12 No.13133197 Report

Quoted By:

>>13132826
No, vos.

Anonymous

Anonymous Sat 15 May 2021 03:45:00 No.13133238 Report

Quoted By:

>>13131720
>Not setting pi = 1 like a proper physicist
LOL

Anonymous

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Anonymous Sat 15 May 2021 04:06:19 No.13133306 Report

Quoted By: >>13133467 >>13133533

Simple as

Anonymous

Anonymous Sat 15 May 2021 04:37:20 No.13133406 Report

Quoted By:

>>13131720
1+1×1-1=1÷1

Anonymous

Anonymous Sat 15 May 2021 04:44:52 No.13133426 Report

Quoted By: >>13133600

>>13131720
How about this one?

$\frac{1}{k!}\sum_{s=1}^{\big\lfloor\frac{N}{k}\big\rfloor}\frac{1}{\left(s!\right)^k}\prod_{r=0}^{ks-1}\left(N-r\right)$

Anonymous

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Anonymous Sat 15 May 2021 04:48:58 No.13133442 Report

Quoted By:

I know it's normalfag shit, but I like it.
t. electrical engineer

Anonymous

Anonymous Sat 15 May 2021 04:54:54 No.13133463 Report

Quoted By:

>>13131720
Maxwell's equations are pretty comfy desu

Anonymous

Anonymous Sat 15 May 2021 04:55:56 No.13133467 Report

Quoted By:

>>13133306
PATRICIAN

Anonymous

Anonymous Sat 15 May 2021 05:16:20 No.13133533 Report

Quoted By: >>13134885

>>13133306
funny, i do advance electromagnetism and am used to writing it
$\nabla \cdot \mathbf{B} = \rho_m$

Anonymous

Anonymous Sat 15 May 2021 05:38:48 No.13133600 Report

Quoted By:

>>13131720
How about it, OP? At least tell me how >>13133426 works.

Anonymous

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Anonymous Sat 15 May 2021 05:42:22 No.13133611 Report

Quoted By: >>13134967 >>13136925

>people who can't TeX their favorite aesthetic equation
The most aesthetic is clearly $i\hbar\dot\Psi=\hat{H}\Psi$
>bonus round
$\frac{\partial\mathcal{L}}{\partial q}=\frac{d}{dt}\frac{\partial\mathcal{L}}{\partial\dot{q}}$

Anonymous

Anonymous Sat 15 May 2021 05:53:03 No.13133629 Report

Quoted By:

>>13131720
${R}_{\mu \nu}-\frac{1}{2}R {g}_{\mu \nu}+\Lambda {g}_{\mu \nu}-\frac{8 \pi G}{c^4} {T}_{\mu \nu} = 0$

Anonymous

Anonymous Sat 15 May 2021 08:49:24 No.13134135 Report

Quoted By:

>>13131720
$U(t) = \mathcal{T} \exp\mathopen{}\left( -i \int_{0}^{t} dt' \, H(t') \right)$

Anonymous

Anonymous Sat 15 May 2021 08:57:11 No.13134153 Report

Quoted By:

>>13131720
$\partial_t \rho + \nabla\cdot(u\rho)$

Anonymous

Anonymous Sat 15 May 2021 09:01:12 No.13134168 Report

Quoted By: >>13136957

$ 0\neq1 $

Anonymous

Anonymous Sat 15 May 2021 12:57:16 No.13134885 Report

Quoted By: >>13134928

>>13133533
Why?
I looked it up and I saw that the form you posted is for when magnetic monopoles exist

Anonymous

Anonymous Sat 15 May 2021 13:10:11 No.13134928 Report

Quoted By: >>13137004

>>13134885
Twinks generalize EM to accommodate magnetic monopoles

Anonymous

Anonymous Sat 15 May 2021 13:23:07 No.13134967 Report

Quoted By: >>13136440

>>13133611
>Expanding out E
Kek

Anonymous

Anonymous Sat 15 May 2021 15:05:26 No.13135257 Report

Quoted By:

$\mathscr{F}(\xi) = \int_{\mathbb{R}^n} f(x)e^{-ix \cdot \xi} \mathrm{d}x$

Anonymous

Anonymous Sat 15 May 2021 18:29:10 No.13136165 Report

Quoted By:

$\sigma_{ij,j}+f_i=0$

Anonymous

Anonymous Sat 15 May 2021 19:27:11 No.13136440 Report

Quoted By:

>>13134967
what?

Anonymous

Anonymous Sat 15 May 2021 19:41:00 No.13136508 Report

Quoted By:

$\frac{dA}{dE} = \tau$

Anonymous

Anonymous Sat 15 May 2021 19:50:03 No.13136552 Report

Quoted By: >>13136568

>>13131720
$\bigoplus_{k\in\mathbb{Z}}M_k(\mathrm{SL}_2(\mathbb{Z}))=\mathrm{span}\{E_4^aE_6^b: a,b\ge 0\}$

Anonymous

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Anonymous Sat 15 May 2021 19:52:35 No.13136568 Report

Quoted By:

>>13136552

Anonymous

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Anonymous Sat 15 May 2021 20:06:50 No.13136633 Report

Quoted By:

$1 + 1 = 2$

Anonymous

Anonymous Sat 15 May 2021 21:29:14 No.13136918 Report

Quoted By: >>13137081 >>13137101 >>13137112

>>13131792
Allows you to estimate how many more times you can subject something to loading, when there is an existing crack in the member/structure, before the crack is propagated and catastrophic failure takes place. It's an experimentally derived equation, I believe.

Anonymous

Anonymous Sat 15 May 2021 21:32:08 No.13136925 Report

Quoted By:

>>13133611
Sauce???

Anonymous

Anonymous Sat 15 May 2021 21:43:39 No.13136957 Report

Quoted By:

>>13134168
based and nontrivial ringpilled

Anonymous

Anonymous Sat 15 May 2021 21:54:58 No.13137004 Report

Quoted By:

>>13134928
engineer chads use magnetic currents to represent equivalent sources

Anonymous

Anonymous Sat 15 May 2021 22:14:40 No.13137081 Report

Quoted By:

>>13136918
yeah, its paris law
$\frac{da}{dN}=A \cdot \Delta K^m$
where A and m are derived experimentally.
and using $\Delta K = \Psi (a) sqrt{\pi a \sigma_0}$ and some rearranging and integrating you get OPs expression

Anonymous

Anonymous Sat 15 May 2021 22:20:36 No.13137101 Report

Quoted By:

>>13136918
yeah, its paris law
$\frac{da}{dN}=A \Delta K^m$
where A and m and determined experimentally.
using the relation for the stress intensity factor $\Delta K = \Psi (a) \sqrt{\pi a \sigma_0}$ and some rearranging and integration you end at OPs expression.

Anonymous

Anonymous Sat 15 May 2021 22:22:47 No.13137112 Report

Quoted By: >>13137129

>>13136918
>>13136918
yeah, its paris law
$\frac{da}{dN}=A \Delta K^m$
where A and m and determined experimentally.
using the relation for the stress intensity factor $\Delta K = \Psi (a) \sqrt{\Delta \sigma \pi a}$ and some rearranging and integration you end at OPs expression.

Anonymous

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Anonymous Sat 15 May 2021 22:26:14 No.13137129 Report

Quoted By: >>13137140

>>13137112
pic related, i used A instead of C because OPs retarded notation

Anonymous

Anonymous Sat 15 May 2021 22:28:25 No.13137140 Report

Quoted By: >>13137151

>>13137129
Why did you post the same thing 3 times?

Anonymous

Anonymous Sat 15 May 2021 22:29:40 No.13137151 Report

Quoted By: >>13137176

>>13137140
because im stupid and cant use latex without missing something

Anonymous

Anonymous Sat 15 May 2021 22:35:19 No.13137176 Report

Quoted By: >>13137249

>>13137151
Are you a mech eng gigachad or a civil cuck?

El cAbrón

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El cAbrón Sat 15 May 2021 22:44:18 No.13137221 Report

Quoted By:

>>13131720
Number of dicks OP and his mom have sucked = picrel

Anonymous

Anonymous Sat 15 May 2021 22:49:38 No.13137249 Report

Quoted By:

>>13137176
mech eng giga chad

Anonymous

Anonymous Sat 15 May 2021 23:29:34 No.13137524 Report

Quoted By: >>13137534 >>13137652 >>13137675 >>13137759 >>13138395

The set $\mathcal{\hat{B}}$ of Barnett-Tooker integrable functions is definitely one of the most beautiful mathematical objects I have ever seen.
$\mathcal{\hat{B}} = \left \{ f\in C(\mathbb{R}): \iiint f(x)d^3x < \lim_{n\rightarrow \hat\infty - b}\sum_{k=1}^n k; b = \pi + e + \sqrt{2}\ \right \}$
The most beautiful theorem, Barnett's identity, arguably the most important result in all of mathematics, modified with a zeta cap function $\hat \zeta_b(s) = \sum_{n=1}^{\hat\infty - b}n^{-s}$ (defined as zeta function when n tends toward neighborhood of infinity) when $b$ is set to Wildberger constant $b=\pi + e + \sqrt{2}$ gives rise to Barnett-Tooker-Wildberger conjecture:
$ \hat \zeta_{\pi + e + \sqrt{2}}(-1) = \frac{e^{i\pi}}{11 + 0.999\dots} $
If proven, the pending renaming is the 'Fundamental theorem of Mathematics'.

Anonymous

Anonymous Sat 15 May 2021 23:30:44 No.13137534 Report

Quoted By:

>>13137524
Holy mother of based

Anonymous

Anonymous Sat 15 May 2021 23:56:46 No.13137652 Report

Quoted By: >>13137670

>>13137524
Mathematics is so beautiful. It blows my mind that mathematicians are able to do not just one but THREE integrals in a row... maybe in the future it will be possible to perform four or even five

Anonymous

Anonymous Sun 16 May 2021 00:00:24 No.13137670 Report

Quoted By:

>>13137652
We can only dream to manage that kind of raw power anon...

Anonymous

Anonymous Sun 16 May 2021 00:01:27 No.13137675 Report

Quoted By:

>>13137524
I love how schizo posts, with enough jargon and confidence, can actually seem to be a reasonable perspective.

Anonymous

Anonymous Sun 16 May 2021 00:22:48 No.13137759 Report

Quoted By:

>>13137524
I gather that right as we speak here, Barnett, Tooker and Wildberger are
all gathered in a bunker deep below the desert somewhere undisclosed,
feverishly trying to work out a proof of this important conjecture.

Anonymous

Anonymous Sun 16 May 2021 02:34:26 No.13138395 Report

Quoted By:

>>13137524
And how does this benefit society

Anonymous

Anonymous Sun 16 May 2021 04:25:59 No.13138763 Report

Quoted By:

>>13131720
$[X_i, X_j] = f_{ij}^k X_k$
$\mathrm{Ad}_{e^X} = e^{\mathrm{ad}_X}$ $\frac{d}{dt} e^{X(t)} = e^{X(t)} \frac{1 - e^{-\mathrm{ad}_X}}{\mathrm{ad}_X} \frac{d}{dt} X(t)$

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