>>13118151I don't remember how to find lengths of equilateral triangle so let me figure this out myself instead of looking it up like a retard
1/2 (base)height = 6
so a 30-60-90 triangle with (short side)(long side)=6 is half the equilateral small triangle
we will call short side s and long side l, and the hypotenuse h
cos(60)=s/h
sin(60)=l/h
sin(60)cos(60)=6/h^2
I used wolfram for sin(60) and cos(60) cause lazy
(sqrt(3)/2))(1/2)=6/h^2
h=sqrt(6/((sqrt(3)/2))(1/2)))
h=sqrt(24/(sqrt(3)))
I was using h for hypotenuse now I am gonna use h for height instead and b for hypotenuse since its also base
b=sqrt(24/(sqrt(3)))
(1/2)bh=6
h=12/sqrt(24/(sqrt(3)))
big triangle is 4x that area so 2x each way
so big triangle is b=2sqrt(24/(sqrt(3))) and h=24/sqrt(24/(sqrt(3)))
area of enclosed white space is 96 plus yellow
so if you draw a meme rectangle around part of it lol the meme rectangle is base 7sqrt(24/(sqrt(3))) and height is 24/sqrt(24/(sqrt(3))) and area 168
so u I guess just find a way to find the pink in picrelated and that is yellow in op
and then add that to 96 and you have area of all enclosed space lol