>>13079383Id choose a 25% option.
The rules of the game state that there is always one and only one correct number. It is irrelevant if smb fucked up the answer labels. There is always only one correct answer, so the coin toss would get me through 25% of the time.
The thing is, I am not answering this question randomly, so it is irrelevant that there are 2 similar options. I will choose one of them and I will be right with a 50% chance. C does not overtake in this case since I act non-randomly now.
The real answer is, you are trying to define a random variable where the sum of event probs does not add up to 1.
Lets take a coin toss. You have 2 coins: one is fair, the other one is all heads. Now you gotta assign the single outcome probs when you toss either one of them. The correct way would be saying there are 4 sides in total, 2 outcomes with 1/4 and 3/4 probs. But using the same mode of thinking as in the oppic, you will be a retard who says: there are 2 sides, tails have 1 instance, heads have 3 instances, so the probs are 1/2 and 3/2.
Or you could also argue that there is a 1/2 chance we choose the unfair coin, thus there is 1/2 chance to roll heads. But there ia also the fair coin. And if we choose it, we get 1/2 chance to roll heads and 1/2 to roll tails. And you get a nonsensical discrete variable you are trying to describe as (Ph = 1/2, Ph = 1/2, Pt= 1/2). Then you scratch ur head and go (Ph = 1.0, Pt = 1/2).
Both these come from the reyard ignoring that all probs have to add up to exactly one.
