>>13034372if you think of yourself as a pipe with cross sectional area and a certain volume flow rate (rain water concentration times running speed) then the rate at which you pick up rain water is:
Rain water absorption rate (kg/s) = Area * rain density in air * running speed
Ar=a*r*v
proportional to running speed
so given equal time amount of time, running absorbs more
but you spend less time outside running if distance is constant (a reasonable assumption for real world applications)
So integrate above w.r.t time to get total rain water absorbed and you get
TAr = a*r*v*t
v*t = distance, so TAr = a*r*d
so velocity goes away, and total is a function of distance only. i.e. it doesn't matter whether you run or not (what mythbusters found)
This does not account for the vertical component of velocity (rain is falling) which is unaffected by how fast you move horizontally. In this case you cannot do the v*t = d substitution above, and v is an independent variable, leaving only t.
So once we take into account vertical velocity of rain water, it is proportional to time, meaning the faster you run the less total rain you absorb.
mythbusters btfo. :)
