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Anonymous Sun 25 Apr 10:07:52 2021 No.13028730 View Reply Original Report

Quoted By: >>13028734 >>13028740 >>13028779

What is this? Can it be expressed as operations performed on known constants?

Anonymous

Anonymous Sun 25 Apr 2021 10:09:07 No.13028734 Report

Quoted By: >>13028736

>>13028730
Define "operations".

Anonymous

Anonymous Sun 25 Apr 2021 10:09:43 No.13028736 Report

Quoted By:

>>13028734
any defined popular function

Anonymous

Anonymous Sun 25 Apr 2021 10:13:36 No.13028740 Report

Quoted By: >>13028773

>>13028730
It would typically be written in terms of special functions.
You can write this in terms of the Struve function for example, which is sort of like a Bessel function.

Anonymous

Anonymous Sun 25 Apr 2021 10:31:03 No.13028773 Report

Quoted By: >>13028788 >>13028833

>>13028740
what about in terms of constants?

Anonymous

Anonymous Sun 25 Apr 2021 10:33:16 No.13028779 Report

Quoted By: >>13028781

>>13028730
Take your meds.

Anonymous

Anonymous Sun 25 Apr 2021 10:34:00 No.13028781 Report

Quoted By:

>>13028779
not a very constructive post

Anonymous

Anonymous Sun 25 Apr 2021 10:36:18 No.13028788 Report

Quoted By:

>>13028773
You could write it as an infinite series or something?

Anonymous

Anonymous Sun 25 Apr 2021 10:55:08 No.13028833 Report

Quoted By: >>13028856 >>13028860 >>13028865

>>13028773
This integral IS a constant. There's no free parameter in this integral. Just evaluate the Struve function at the right argument.

$\displaystyle{\int^\pi_0\sin\sin xdx=H_0(1)\pi}$

where

$\displaystyle{H_\alpha(x)=\frac{x^\alpha}{2^{\alpha-1}\sqrt\pi\Gamma(\alpha+\frac12)}\int^{\frac12\pi}_0\sin(x \sin t)\cos^{2\alpha}tdt}$

If you want something else then just go fuck around and see what Struve functions do and see what it is you want. Just saying "I want a constant" is so vague you can't expect to get any help from just that.

Anonymous

Anonymous Sun 25 Apr 2021 10:57:31 No.13028841 Report

Quoted By:

https://en.wikipedia.org/wiki/Lattice_QCD
Can it be expressed as operations performed on known constants?

Anonymous

Anonymous Sun 25 Apr 2021 11:03:27 No.13028856 Report

Quoted By:

>>13028833
what I said in terms of constant I meant like a function involving $\pi$ or $\pi$

Anonymous

Anonymous Sun 25 Apr 2021 11:04:12 No.13028860 Report

Quoted By: >>13028871 >>13028875

>>13028833
Top lel. First I thought you just made this up for an elaborate hoax but then I looked up Struve functions and they're actually a thing.

Anonymous

Anonymous Sun 25 Apr 2021 11:06:13 No.13028865 Report

Quoted By: >>13028871

>>13028833
when I said in terms of constants, I meant like a function of $\pi$ or $\e$ , like how the sum of the reciprocal of all squares is $\frac{\pi^2}{6}$

Anonymous

Anonymous Sun 25 Apr 2021 11:07:24 No.13028868 Report

Quoted By: >>13028930

[code:lit]
\displaystyle{H_\alpha(x)=\frac{x^\alpha}{2^{\alpha-1}\sqrt\pi\Gamma(\alpha+\frac12)}\int^{\frac12\pi}_0\sin(x \sin t)\cos^{2\alpha}tdt}
[/code:lit]
f-ck this shit

Anonymous

Anonymous Sun 25 Apr 2021 11:09:32 No.13028871 Report

Quoted By:

>>13028860
Yeah, I've certainly led a pretty amazing life to know about all this shit. Where would I be if I didn't learn my fucking Struve functions.
>>13028865
Well then, once more I will reiterate, your integral is given in terms of the constants $\pi$ and the notorious $H_0(1)$

Anonymous

Anonymous Sun 25 Apr 2021 11:10:25 No.13028875 Report

Quoted By:

>>13028860
Wtf why would you think it's a joke?

Anonymous

Anonymous Sun 25 Apr 2021 11:50:01 No.13028930 Report

Quoted By:

>>13028868
>code
Hi /g/
$<br />\displaystyle{H_\alpha(x)=\frac{x^\alpha}{2^{\alpha-1}\sqrt\pi\Gamma(\alpha+\frac12)}\int^{\frac12\pi}_0\sin(x \sin t)\cos^{2\alpha}tdt}<br />$

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