/sci/ - Science & Math » Thread #13021633

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Anonymous Fri 23 Apr 21:25:32 2021 No.13021633 View Reply Original Report

Quoted By: >>13021677 >>13021678 >>13022530 >>13022704 >>13022754 >>13022831

Any differential equation geniuses here that can take me through the solution to this problem step by step?

El Cabrón

El Cabrón Fri 23 Apr 2021 21:36:43 No.13021677 Report

Quoted By: >>13021750

>>13021633
Download a copy of Mathematica and run WolframAlpha[ same query]
And step-by-step will be enabled

Anonymous

Anonymous Fri 23 Apr 2021 21:36:42 No.13021678 Report

Quoted By: >>13021687

>>13021633
Alright anon, so basically click the orange button on the top right that says "step-by-step solution".

Anonymous

Anonymous Fri 23 Apr 2021 21:38:57 No.13021687 Report

Quoted By: >>13021708 >>13021750 >>13021759

>>13021678
i don't have pro version of wolf

Anonymous

Anonymous Fri 23 Apr 2021 21:44:30 No.13021708 Report

Quoted By:

>>13021687
ffs its only like 10 a month

go be poor somewhere else

El Cabrón

El Cabrón Fri 23 Apr 2021 21:53:25 No.13021750 Report

Quoted By:

>>13021687
Do this >>13021677 faggot

Anonymous

Anonymous Fri 23 Apr 2021 21:55:10 No.13021759 Report

Quoted By: >>13021769

>>13021687
wolfram alpha step by step won't help you much because 99% it's using some programmatic and or brute force algorithm

El Cabrón

El Cabrón Fri 23 Apr 2021 21:57:25 No.13021769 Report

Quoted By:

>>13021759
Nope. It’s quite good. It doesn’t work for everything, not even every DE, but what it works for it does quite well.

Anonymous

Anonymous Fri 23 Apr 2021 22:02:26 No.13021800 Report

Quoted By:

your ODE is equivalent to

y''(x) = 1/ln(x)

the solution to which is well known.

Anonymous

Anonymous Sat 24 Apr 2021 02:08:44 No.13022530 Report

Quoted By: >>13022731

>>13021633
Why is this giving _x_ in terms of _y_?

Anonymous

Anonymous Sat 24 Apr 2021 03:05:22 No.13022704 Report

Quoted By:

>>13021633
Idk, try series.

Anonymous

Anonymous Sat 24 Apr 2021 03:11:41 No.13022731 Report

Quoted By:

>>13022530
because it was easier to compute

Anonymous

Anonymous Sat 24 Apr 2021 03:18:04 No.13022754 Report

Quoted By:

>>13021633
You can write y'/y = 1/y''
So ln|y| = integral(1/y'') + c
or y = A*integral(1/y'')
Maybe use numerical methods after that?

Anonymous

Anonymous Sat 24 Apr 2021 03:47:26 No.13022831 Report

Quoted By:

>>13021633
Substitute
$y'=p(y),\ \ y''=p'p$ Then you'll get
$p^2p'=y.$

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