/sci/ - Science & Math » Thread #12997801

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Anonymous Mon 19 Apr 00:56:22 2021 No.12997801 View Reply Original Report

Quoted By: >>13000010 >>13000022 >>13000520

how do i use tex on 4chan?

Anonymous

Anonymous Mon 19 Apr 2021 00:57:11 No.12997804 Report

Quoted By:

x^2

Anonymous

Anonymous Mon 19 Apr 2021 00:58:15 No.12997806 Report

Quoted By: >>12997814

[x^2]

Anonymous

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Anonymous Mon 19 Apr 2021 00:58:20 No.12997807 Report

Quoted By: >>12998627 >>13000356 >>13001709

$ \mathfrak{I\ have\ no\ idea...} $

Anonymous

Anonymous Mon 19 Apr 2021 01:00:46 No.12997814 Report

Quoted By:

>>12997806
like this $x^{2}[\math]$

Anonymous

Anonymous Mon 19 Apr 2021 01:03:11 No.12997826 Report

Quoted By:

$x^{2} [\math]$

Anonymous

Anonymous Mon 19 Apr 2021 01:05:21 No.12997834 Report

Quoted By:

\x^2

Anonymous

Anonymous Mon 19 Apr 2021 01:08:50 No.12997855 Report

Quoted By:

$\x^{2} [\math]$

Anonymous

Anonymous Mon 19 Apr 2021 01:12:34 No.12997874 Report

Quoted By:

\mathfrak{I\ have\ no\ idea...}

Anonymous

Anonymous Mon 19 Apr 2021 01:15:22 No.12997880 Report

Quoted By:

$\mathfrak{I\ have\ no\ idea...}$

Anonymous

Anonymous Mon 19 Apr 2021 01:17:49 No.12997886 Report

Quoted By: >>13000011

${x^2}$
${x^2}$
$x^{2}$
{x^2}

Anonymous

Anonymous Mon 19 Apr 2021 02:11:10 No.12998043 Report

Quoted By:

you dont

Anonymous

Anonymous Mon 19 Apr 2021 04:52:07 No.12998627 Report

Quoted By:

>>12997807
hahahahaha kek

Anonymous

Anonymous Mon 19 Apr 2021 13:06:01 No.13000000 Report

Quoted By: >>13000003 >>13000006 >>13000008 >>13000022 >>13000053 >>13000188 >>13000237 >>13000341 >>13000474 >>13001094 >>13001267 >>13002299

Use Groff instead.

Anonymous

Anonymous Mon 19 Apr 2021 13:06:20 No.13000003 Report

Quoted By:

>>13000000
Checked

Anonymous

Anonymous Mon 19 Apr 2021 13:07:08 No.13000006 Report

Quoted By:

>>13000000
YOU BASTARD YOU STOLE MY 13 MILLION

Anonymous

Anonymous Mon 19 Apr 2021 13:07:17 No.13000008 Report

Quoted By:

>>13000000
SciKek has spoken. Groff it will be!

Anonymous

Anonymous Mon 19 Apr 2021 13:07:28 No.13000009 Report

Quoted By:

$x^{2}$

Anonymous

Anonymous Mon 19 Apr 2021 13:07:32 No.13000010 Report

Quoted By:

>>12997801
13,000,000 GIT

Anonymous

Anonymous Mon 19 Apr 2021 13:07:43 No.13000011 Report

Quoted By:

>>12997886
>>12997886
>x2x2
>{x^2}
wut?

Anonymous

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Anonymous Mon 19 Apr 2021 13:10:15 No.13000022 Report

Quoted By: >>13000074 >>13000465

>>12997801
Sorry bro... You are retarded...

>>13000000
Checked and based.

Anonymous

Anonymous Mon 19 Apr 2021 13:12:59 No.13000031 Report

Quoted By:

$x^2 \textit{KEKEKEKKEK}$

Anonymous

Anonymous Mon 19 Apr 2021 13:20:19 No.13000053 Report

Quoted By:

>>13000000
Based and Smithpilled

Anonymous

Anonymous Mon 19 Apr 2021 13:32:05 No.13000074 Report

Quoted By:

>>13000022
i dont have that option on my phone

Anonymous

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Anonymous Mon 19 Apr 2021 14:06:52 No.13000188 Report

Quoted By:

>>13000000

Anonymous

Anonymous Mon 19 Apr 2021 14:22:14 No.13000237 Report

Quoted By:

>>13000000
CHECKED

Anonymous

Anonymous Mon 19 Apr 2021 14:23:26 No.13000242 Report

Quoted By:

$x^2$

Anonymous

Anonymous Mon 19 Apr 2021 14:48:09 No.13000341 Report

Quoted By:

>>13000000
Classic /sci/, in the middle of work

Anonymous

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Anonymous Mon 19 Apr 2021 14:52:32 No.13000356 Report

Quoted By:

>>12997807
$\mathfrak{Heil Hitler}$

Anonymous

Anonymous Mon 19 Apr 2021 15:22:18 No.13000465 Report

Quoted By:

>>13000022
In all fairness, Its not on the post a new thread box either

Anonymous

Anonymous Mon 19 Apr 2021 15:24:16 No.13000472 Report

Quoted By:

$ \delta \, \epsilon \left ( 0,1 \right ) \\ \displaystyle \prod_{k=0}^{n} \left ( 1 + \delta ^{2^{k}} \right ) = (1+ \delta)(1+ \delta ^{2})(1+ \delta ^{4}) \cdots (1+ \delta ^{2^{n-1}})(1+ \delta ^{2^{n}}) \\ (1- \delta) \prod_{k=0}^{n} \left ( 1+ \delta ^{2^{k}} \right ) = (1- \delta)(1+ \delta)(1+ \delta ^{2})(1+ \delta ^{4}) \cdots (1+ \delta ^{2^{n-1}})(1+ \delta ^{2^{n}}) \\ = (1- \delta ^{2})(1+ \delta ^{2})(1+ \delta ^{4}) \cdots (1+ \delta ^{2^{n-1}})(1+ \delta ^{2^{n}}) \\ = (1- \delta ^{4})(1+ \delta ^{4}) \cdots (1+ \delta ^{2^{n-1}})(1+ \delta ^{2^{n}}) = (1- \delta ^{2^{n}})(1+ \delta ^{2^{n}}) = 1- \delta ^{2^{n+1}} \\ \\ \boxed{(\delta ^{2^n})^2 = \delta ^{2 \cdot 2^n}=\delta^{2^{n+1}}} \\ \displaystyle \prod_{k=0}^{n} \left ( 1+ \delta ^{2^{k}} \right ) = \dfrac{1- \delta^{2^{n+1}}}{1- \delta} \\ \displaystyle \lim_{n \to \infty} \prod_{k=0}^{n} \left (1+ \delta ^{2^{k}} \right ) = \lim_{n \to \infty} \dfrac{1- \delta^{2^{n+1}}}{1- \delta} = \dfrac{1}{1- \delta} $

Anonymous

Anonymous Mon 19 Apr 2021 15:24:31 No.13000474 Report

Quoted By:

>>13000000
based and checkpilled

Anonymous

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Anonymous Mon 19 Apr 2021 15:31:32 No.13000508 Report

Quoted By:

Anonymous

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Anonymous Mon 19 Apr 2021 15:34:00 No.13000520 Report

Quoted By:

>>12997801
Ask the expert.

Anonymous

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Anonymous Mon 19 Apr 2021 17:48:08 No.13001094 Report

Quoted By:

>>13000000
w- what's happening?
Are we ascending?

Anonymous

Anonymous Mon 19 Apr 2021 18:14:38 No.13001267 Report

Quoted By:

>>13000000
CHECK'D

Anonymous

Anonymous Mon 19 Apr 2021 19:54:35 No.13001709 Report

Quoted By: >>13001715

>>12997807
\mathfrak{I\ have\ no\ idea...}

Anonymous

Anonymous Mon 19 Apr 2021 19:55:41 No.13001715 Report

Quoted By:

>>13001709
$\mathfrak{I\ have\ no\ idea...}$

Anonymous

Anonymous Mon 19 Apr 2021 22:19:59 No.13002299 Report

Quoted By:

>>13000000
checked

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