take the integral 0 dx between 0 and inf.
well if we solve it we have 0*inf.
inf = n
0 * n limit
0 / (1/n) = 0 / 0
0 = z
z / z limit
lim z ->0 (1) = 1.
clearly.
but n * 0 = 0.
right?
take one.
1 = sum 1/2^n where n >= 1
1/2 = sum 1/3^n where n >= 1
etc.
...
1 = 1/n + 1/n + 1/n +... where is n is very large.
because limits assume information I'll use hitomi's number which assumes different information.
1 = 1/h + 1/h + ...
1 = 0 + 0 + ...
0 + 0 = 0
thus clearly 1 = 0
right?
but a + a = 2a.
so 1 = h * 0
h * 0 is unambiguously 1
well if we solve it we have 0*inf.
inf = n
0 * n limit
0 / (1/n) = 0 / 0
0 = z
z / z limit
lim z ->0 (1) = 1.
clearly.
but n * 0 = 0.
right?
take one.
1 = sum 1/2^n where n >= 1
1/2 = sum 1/3^n where n >= 1
etc.
...
1 = 1/n + 1/n + 1/n +... where is n is very large.
because limits assume information I'll use hitomi's number which assumes different information.
1 = 1/h + 1/h + ...
1 = 0 + 0 + ...
0 + 0 = 0
thus clearly 1 = 0
right?
but a + a = 2a.
so 1 = h * 0
h * 0 is unambiguously 1
