all Pythagorean triplets are either in the form
$(2k+1)^2+(2k2+2k)^2=(2k+2k2+1)^2[\math]<br /> or<br /> <script type="math/tex">(2k)^2+(k^2?1)^2=(k^2+1)^2[\math]<br /> where <script type="math/tex"> k \in N [\math]<br /> <br /> prove me wrong.$