Why $1^x$ allays is 1?

If we got that $x^y=z$ and $z^{1/y}=x\;\left(x,y\right)\in\mathbb{R}$

if $z$ becomes equal to 1

$y=\cfrac{2i\pi\text{n}}{\ln\left(x\right)}\quad\text{n}\in\mathbb{Z}$

$x^{y}=x^{\frac{2i\pi\text{n}}{\ln x}}=1$

but:

$1^{\frac{\ln x}{2i\pi\text{n}}}\neq x$

why $z^{1/y}=x$ isn't true anymore?