/sci/ - Science & Math » Thread #12886168

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Math God Request

Anonymous Fri 26 Mar 16:15:35 2021 No.12886168 View Reply Original Report

Quoted By: >>12886184

Explain and I will confess my idiocy.

Anonymous

Anonymous Fri 26 Mar 2021 16:17:34 No.12886177 Report

Quoted By: >>12886180

Hint: Use a substitution z=x^2+4

Anonymous

Anonymous Fri 26 Mar 2021 16:19:21 No.12886180 Report

Quoted By:

Anonymous

Anonymous Fri 26 Mar 2021 16:20:41 No.12886184 Report

Quoted By: >>12886186

>>12886168
$\frac{4x^3}{(x^2 + 4)^{1/2}} = \frac{4x^3(x^2 + 4)}{(x^2 + 4)^{3/2}}$

Then you can just add the two fractions.

Anonymous

Anonymous Fri 26 Mar 2021 16:22:11 No.12886186 Report

Quoted By: >>12888573

>>12886184
i am an idiot

Anonymous

Anonymous Sat 27 Mar 2021 01:36:49 No.12888573 Report

Quoted By:

>>12886186
We all are

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