/sci/ - Science & Math » Thread #12883831

575KiB, 1388x1156, Its been 2 hours and i got nothin-1.png

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Anonymous Fri 26 Mar 00:24:08 2021 No.12883831 View Reply Original Report

Quoted By: >>12883903

Can someone help me solve these? I knew how to do em at one point, but the math part of my mind has been wiped

Anonymous

Anonymous Fri 26 Mar 2021 00:25:44 No.12883838 Report

Quoted By: >>12883850

3. Learn how to use logarithms
4. Learn how to factor polynomials

Anonymous

Anonymous Fri 26 Mar 2021 00:28:25 No.12883850 Report

Quoted By: >>12883864

>>12883838
Im trying with khan academy and other online recources, its just im supposed to submit these questions in a few hours and I dont think I have enough time

Anonymous

Anonymous Fri 26 Mar 2021 00:34:14 No.12883864 Report

Quoted By:

>>12883850
You do know that 27 is just 3^3?

Anonymous

Anonymous Fri 26 Mar 2021 00:45:37 No.12883903 Report

Quoted By: >>12883914

>>12883831
$3^{4} (3^{2x^{2}-7}) = 3^{3(x-1)} * 3 ^ {8}$
$3^{2x^{2}-7} = 3^{3(x-1)} * 3 ^ {4}$
$\log(3^{2x^{2}-7}) = \log(3^{3(x-1)} * 3 ^ {4})$
$(2x^{2}-7 )\ log(3) = 3(x-1) \log(3) + 4 \ log(3)$
$2x^{2}-7 = 3x - 3 + 4$
$2x^{2} - 3x - 8 = 0$

You can do the rest yourself. Just double check what I did above.

Anonymous

Anonymous Fri 26 Mar 2021 00:48:08 No.12883914 Report

Quoted By: >>12883921

>>12883903
Thank you autistic dad. Much appreciated

Anonymous

Anonymous Fri 26 Mar 2021 00:49:23 No.12883921 Report

Quoted By:

>>12883914
kek. anytime virgin

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