/sci/ - Science & Math » Thread #12854265

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Anonymous Fri 19 Mar 09:19:08 2021 No.12854265 View Reply Original Report

Quoted By: >>12854273 >>12854277 >>12855288 >>12855347

i will suck pp for hint, any thoughts /sci/

sus

sus Fri 19 Mar 2021 09:29:05 No.12854273 Report

Quoted By:

>>12854265
calc 2 retard fuck off

Anonymous

Anonymous Fri 19 Mar 2021 09:32:50 No.12854277 Report

Quoted By: >>12854281 >>12854376

>>12854265
By Jensen's inequality
$\sqrt[n]{|\Re (a_n)|} = \sqrt[n]{\frac{|a_n + \bar {a_n}|}{2}} \leq \frac{1}{2} \left( \sqrt[n]{|a_n|} + \sqrt[n]{ |\bar {a_n}|} \right) = \sqrt[n]{|a_n|}$
So
$\limsup_{n \to \infty} \frac{1}{\sqrt[n]{|\Re (a_n)|}} \geq \limsup_{n \to \infty} \frac{1}{\sqrt[n]{|a_n|}}$

Anonymous

Anonymous Fri 19 Mar 2021 09:34:16 No.12854281 Report

Quoted By:

>>12854277
>Jensen's inequality
ty dude

Anonymous

Anonymous Fri 19 Mar 2021 10:25:11 No.12854366 Report

Quoted By: >>12855286

is there not an easier way to do it...

Anonymous

Anonymous Fri 19 Mar 2021 10:28:14 No.12854376 Report

Quoted By: >>12855295

>>12854277
this seems too complicated lol

Anonymous

Anonymous Fri 19 Mar 2021 15:43:51 No.12855286 Report

Quoted By:

>>12854366
You really only need to say |Re(x)| <= |x|

Anonymous

Anonymous Fri 19 Mar 2021 15:45:25 No.12855288 Report

Quoted By:

>>12854265
/sci/ is seriously just full of inbreeds that can't solve hs questions

Anonymous

Anonymous Fri 19 Mar 2021 15:47:47 No.12855295 Report

Quoted By:

>>12854376
filtered

Anonymous

Anonymous Fri 19 Mar 2021 16:07:27 No.12855347 Report

Quoted By:

>>12854265
Impossible.

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