>>12826757Sorry for wording improperly. What I meant to say is that if you have 4 sisters, one of which doesn't have blue eyes, then no matter how you split them up into pairs one pair will always contain the sister with brown eyes and one will always contain two sisters with blue eyes thus making the possible number of ways to choose a pair with two blue eyed sisters equal to that of choosing a pair containing a sister without blue eyes. Resulting in a 50/50 chance.
Of course the calculations for verifying the correctness of the approach I presented would be much simpler since you have a (3/4)*(2/3) = 1/2 chance of not choosing the sister with the not blue eyes for both sisters in the pair of Jones sisters you meet.
I just wanted to give an explanation for how I found the answer without just stating it or just proving that it was correct.
