/sci/ - Science & Math » Thread #12794907

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Anonymous Fri 05 Mar 23:10:08 2021 No.12794907 View Reply Original Report

Quoted By: >>12794918

>...+1/2 O2

Anonymous

Anonymous Fri 05 Mar 2021 23:14:58 No.12794918 Report

Quoted By: >>12794936

>>12794907
just multiply everything by 2 brainlet

Anonymous

Anonymous Fri 05 Mar 2021 23:19:51 No.12794936 Report

Quoted By: >>12794963 >>12795006 >>12795022 >>12796418

>>12794918
why not notate the original equation in a way that is physically plausible

Anonymous

Anonymous Fri 05 Mar 2021 23:29:16 No.12794963 Report

Quoted By:

>>12794936
This is why we need weedout classes. You got weeded, OP.

Anonymous

Anonymous Fri 05 Mar 2021 23:42:37 No.12795006 Report

Quoted By: >>12795063 >>12796432

>>12794936
If the units are moles or molar equivalents rather than molecules, there's nothing physically implausible about coefficcient of 1/2.

Anonymous

Anonymous Fri 05 Mar 2021 23:49:57 No.12795022 Report

Quoted By:

>>12794936
because who gives a fuck about the amount of oxygen that's given off. equations are written like this so we can get a better feel for how much reactant is turned into product

Anonymous

Anonymous Fri 05 Mar 2021 23:58:43 No.12795053 Report

Quoted By:

its so we can calculate the molar quantities of other materials in the reaction you retard

Anonymous

Anonymous Sat 06 Mar 2021 00:00:32 No.12795063 Report

Quoted By:

>>12795006
yeah isn't that just one O

Anonymous

Anonymous Sat 06 Mar 2021 07:51:46 No.12796418 Report

Quoted By:

>>12794936
because you focus on a chemical species more interesting to have as unit as frigging oxygen?

Anonymous

Anonymous Sat 06 Mar 2021 07:57:24 No.12796432 Report

Quoted By: >>12796435 >>12796438

>>12795006
are moles even or odd?

Anonymous

Anonymous Sat 06 Mar 2021 07:58:51 No.12796435 Report

Quoted By:

>>12796432
everything you want anon, based on the starting reagent amount you choose

Anonymous

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Anonymous Sat 06 Mar 2021 07:59:53 No.12796438 Report

Quoted By:

>>12796432
you know that 1/2 is equal to 0.5... right?

Anonymous

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Anonymous Sat 06 Mar 2021 10:33:44 No.12796834 Report

Quoted By:

> $H_2 + \frac{1}{2}O_2 \longrightarrow H_2O$

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