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This solution assumes that the part about the heat capacity of water is a red herring and that the student isn't meant to get into differential equations.
>Calculated how many joules have been produced by the heater in 10 minutes.
200(J/s) * 600 (s) = 120,000 J
>How much ice (kg) would this amount of energy melt?
120 kJ / 334 kJ = 0.359 kg
>How much energy is needed to melt all the ice
334 kJ
>Calculate the time needed to melt all the ice
334 kJ / 200 J/s = 1670 s = 27.83 minutes
