/sci/ - Science & Math » Thread #12769036

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Anonymous Mon 01 Mar 00:02:37 2021 No.12769036 View Reply Original Report

Quoted By: >>12769060 >>12769255

So, you like maths, do you? prove it.

Anonymous

Anonymous Mon 01 Mar 2021 00:03:21 No.12769044 Report

Quoted By:

Prove you can arrive at this solution.

Anonymous

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Anonymous Mon 01 Mar 2021 00:05:48 No.12769060 Report

Quoted By:

>>12769036
You didn't pose the problem with a picture of kurisu gesturing to it, so I have no incentive to solve it.

Anonymous

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Anonymous Mon 01 Mar 2021 00:20:15 No.12769108 Report

Quoted By: >>12769114

0x0=2

There is no disproving.

Anonymous

Anonymous Mon 01 Mar 2021 00:22:21 No.12769114 Report

Quoted By:

>>12769108
proof by uwu conjecture

Anonymous

Anonymous Mon 01 Mar 2021 01:04:44 No.12769255 Report

Quoted By:

>>12769036
Write the integrand as $\frac{\sec x}{\sin x+ \cos x} - \frac{\sec x}{\sin x + 2\cos x}$ . For the first term, we have $\frac{\sec x}{\sin x+ \cos x = \frac{\sec^2 x}{1+\tan x}$ so a u-substitution with u=1+tan x shows you get $\log(1+\tan x)+C$ . Second term is the same except you use a 2 instead of a 1, so you get $\log(1+\tan x) - \log(2+\tan x)+C$ overall. The result is just using special values of tan.

Anonymous

Anonymous Mon 01 Mar 2021 01:22:54 No.12769307 Report

Quoted By:

Do your own homework, faggot.

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