>>12702791>>12702866Brainlets. Consider the following:
if ,
then we have precedent showing that the square operator is NOT the duplication operator. It's arbitrarily defined. So the notion that
is absurd. If we can apply the square operator to a trig function, and it doesn't duplicate the function bur rather duplicates the arguments, then the square operator applied to the latter case must also duplicate the arguments rather than duplicating the function.
