Can someone explain to a mathlet how to calculate probability in the ttrpg Wrath and Glory?
The basics are:
> Roll a pool of six sided dice (d6)
> Every 1/2/3 is a failure (0 points)
> Every 4/5 is a success (1 point)
> Every 6 is a double success (2 points)
So, for example, if I rolled 7d6, and got a result of 2/3/2/2/5/6/1, I will count that as 3 successes.
> This gets compared to a difficulty number (DN) set by the one running the game.
So in the previous example, if it was a DN5 test and I got 3 successes, I will fail the test.
I'm trying to use anydice.com to figure it out, but I'm not sure how to put it in. The way I see it, each dice in the pool gives a 50% chance for one success, with a 1/6 chance of an extra success, but saying 66% of success doesn't feel right. If its a DN2 test, 1d6 will give a 1/6 chance of success, but 2d6 will give...?
The basics are:
> Roll a pool of six sided dice (d6)
> Every 1/2/3 is a failure (0 points)
> Every 4/5 is a success (1 point)
> Every 6 is a double success (2 points)
So, for example, if I rolled 7d6, and got a result of 2/3/2/2/5/6/1, I will count that as 3 successes.
> This gets compared to a difficulty number (DN) set by the one running the game.
So in the previous example, if it was a DN5 test and I got 3 successes, I will fail the test.
I'm trying to use anydice.com to figure it out, but I'm not sure how to put it in. The way I see it, each dice in the pool gives a 50% chance for one success, with a 1/6 chance of an extra success, but saying 66% of success doesn't feel right. If its a DN2 test, 1d6 will give a 1/6 chance of success, but 2d6 will give...?
