So a A^2+B^3=C^2 triangle
Where 3^2+4^2=C^2
If you make a rectangle that is
8 length and 6width.
You mark lines half way on length vertically and half way on width horizontally.
You produce 4 triangles that follow this. Their area is 6. There are four so the total area is is 24.
And since C=5 the center square's area is 25+ the area of the triangles is 49.
But we say the area of the rectangle is length 8 x width 6=48.
If you alternate the triangles to produce a square the sides of the square would be 7 length and 7 width. Which comes out to 49.
But if you do the same and mark the half way points it produces 4 triangles with 3.5^2+3.5^2=c^2
And doing the same process the area comes out to 48.9986.. which is close to 49 and round up is 49.
So what is area?
I mean all rectangles can produce these A^2+B^2=C^2 triangles.
No one has given an answer
Where 3^2+4^2=C^2
If you make a rectangle that is
8 length and 6width.
You mark lines half way on length vertically and half way on width horizontally.
You produce 4 triangles that follow this. Their area is 6. There are four so the total area is is 24.
And since C=5 the center square's area is 25+ the area of the triangles is 49.
But we say the area of the rectangle is length 8 x width 6=48.
If you alternate the triangles to produce a square the sides of the square would be 7 length and 7 width. Which comes out to 49.
But if you do the same and mark the half way points it produces 4 triangles with 3.5^2+3.5^2=c^2
And doing the same process the area comes out to 48.9986.. which is close to 49 and round up is 49.
So what is area?
I mean all rectangles can produce these A^2+B^2=C^2 triangles.
No one has given an answer
