/sci/ - Science & Math » Thread #12655249

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Anonymous Tue 02 Feb 05:59:01 2021 No.12655249 View Reply Original Report

Quoted By: >>12655667 >>12655671 >>12655685 >>12655689 >>12655897 >>12655991

Always expend the brackets first
This is the correct method of doing so.

Anonymous

Anonymous Tue 02 Feb 2021 06:52:22 No.12655392 Report

Quoted By: >>12655891

You fine? Sums inside parenthesis go first, this is all proved by field axioms

Anonymous

Anonymous Tue 02 Feb 2021 08:44:31 No.12655667 Report

Quoted By:

>>12655249
Wrong

Anonymous

Anonymous Tue 02 Feb 2021 08:47:08 No.12655671 Report

Quoted By:

>>12655249
Nobody cares nerd

Anonymous

Anonymous Tue 02 Feb 2021 08:55:44 No.12655685 Report

Quoted By: >>12655891

>>12655249
Doing that takes three operations (2 x 2, 2 x 2, 4 + 4) whereas you could just do two (2 + 2, 2 * 4)

Anonymous

Anonymous Tue 02 Feb 2021 08:57:44 No.12655689 Report

Quoted By: >>12655891

>>12655249
But... why?
2+2 is 4. Times 2 is 8.
2 times two is four, done twice is four plus four.
Thus eight.
It's... legitimately the same answer in both cases. The first method just makes the computation a "step" faster.

Anonymous

Anonymous Tue 02 Feb 2021 10:41:26 No.12655891 Report

Quoted By:

>>12655689
>>12655685
>>12655392
It is done like this because once the equations become more complex, they are correct steps to take

Anonymous

Anonymous Tue 02 Feb 2021 10:42:28 No.12655897 Report

Quoted By: >>12655982

>>12655249
Also solves your 8÷2(2+2) equation

Anonymous

Anonymous Tue 02 Feb 2021 11:31:54 No.12655982 Report

Quoted By: >>12655988 >>12656020

>>12655897
8÷2(2+2)
= 8÷4+4
= 2 + 4
= 6

Anonymous

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Anonymous Tue 02 Feb 2021 11:33:44 No.12655988 Report

Quoted By:

>>12655982
>+4

Anonymous

Anonymous Tue 02 Feb 2021 11:34:36 No.12655991 Report

Quoted By: >>12655994 >>12656016

>>12655249
Why would you do an operation outside the parenthesis before the operation outside it?

Anonymous

Anonymous Tue 02 Feb 2021 11:35:37 No.12655994 Report

Quoted By:

>>12655991
*inside

Anonymous

Anonymous Tue 02 Feb 2021 11:43:28 No.12656016 Report

Quoted By: >>12656049

>>12655991
you are doing the operation inside it, using the outside integer

Anonymous

Anonymous Tue 02 Feb 2021 11:44:53 No.12656020 Report

Quoted By:

>>12655982
8÷2(2+2)
= 8÷(4+4)
= 8÷8
= 1

Anonymous

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Anonymous Tue 02 Feb 2021 12:03:49 No.12656049 Report

Quoted By: >>12656141

>>12656016
>you are doing the operation inside it
>using the outside integer
So... This is perfectly sensical to you?:
$4+(-(3-7)+9)$
$(-(3-7)+9+4)$
$(-(3-7-9-4))$
$((-3+7+9+4))$

Anonymous

Anonymous Tue 02 Feb 2021 12:58:08 No.12656141 Report

Quoted By:

>>12656049
your second step is incorrect
4+(?(3?7)+9)
you first separate ?(3?7) becomes (-3+7) then put it back in
4+((?3+7)+9)
4+(4+9)
4+(13)
17

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