>>12536306I will find a solution very soon. Lay talks about repeability.
x1=Ax0
x2=Ax1
x3=Ax2
....
I'm very close to solution. I can feel it.
See, If A would be unit matrix [1 0;0 1]
Let us start with e_x=[1;0]
Ae_x=[1 0;0 1]*[1;0]
=[1,0]
we don't move. char(A,L)=(1-L)^2
So the eigenvalues are duplicate 1.
And eigenvectors? unit vectors [1 0] and [0 1]. No wonder we don't move.
Nextly, A=[0 0;0 0]
We move to origo and stay there. Eigenvalues are duplicate zero. Maybe, if we have duplicate value, it would be ONE VALUE and it would be a LINE.
If we have two DISTINCT values, we get a PARABELE.
Aah, I'm gonna get orgasm soon. I'm so close to win cucklex numbercucks. Real values for the win!
