>>12522660They are not constants though. A family of curves is the set of all curves the expression produces for all values of a. The problem with your solution is that a is common to both families, so it's like a more complicated version of my exapmle in
>>12522214 I would like to point out again that for the given h(x,y,a)=0 youcfound a solution f(x,y,a,b)=0 which works for all a and b. The problem is that the seconds parameters a and b are not free to take any values they want, a is restricted to be equal to the a of the first. So while for example h(x,y,1)=0 will intersect vertically with f(x,y,1,b)=0 for all b, it is not guaranteed to do so with f(x,y,5,6) and so in your families there can be members that do not have the property and so your families are not proven to be orthogonal which makes your solution wrong (in fact I am almost certain that you will always be able to find values which violate the property)
