>>12509109>first you wrote 3x^(2/3) not 3x^(-2/3).In the example in the text book, which Wolfram Alpha states is correct, when you factor out x^(-2/3), you essentially add (2/3) to the other exponents to convert x^(1/3) into x and x^(4/3) into x^2. I tried going through the same process with x^(2/3) instead of x(-2/3), and I thought I could subtract (2/3) from the other exponents instead of adding, but Wolfram Alpha tells me that 3x^(2/3)-6x^(1/3)+3x(4/3) and 3x^(2/3)(1-2x^(-1/3)+x^(2/3)) are not equivalent.