>>12469095You can use the minors formula for determinant to reduce it from the n x n matrix determinant to an alternating sum of scaled (n - 1) x (n - 1) matrices. Since these are all scaled by 2, you can pull out a single 2. You then apply the same formula to the (n - 1) x (n - 1) matrices to get even smaller matrices, and pull out yet another 2. Repeat until n is exhausted and you have 2^n det(A).
