/sci/ - Science & Math » Thread #12414168

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Anonymous Thu 03 Dec 07:21:24 2020 No.12414168 View Reply Original Report

Quoted By: >>12414186 >>12414220 >>12414395 >>12416888 >>12417330 >>12417380 >>12417400 >>12417411

I've been staring at this shit for over an hour now.

Is there something wrong with this calculator I'm using or am I retarded?

Anonymous

Anonymous Thu 03 Dec 2020 07:23:16 No.12414170 Report

Quoted By: >>12414173

You are, in fact, retarded

Anonymous

Anonymous Thu 03 Dec 2020 07:27:37 No.12414173 Report

Quoted By: >>12414179 >>12414182 >>12414189 >>12414196 >>12414953

>>12414170
Would you mind helping me count my beans, sire?

Anonymous

Anonymous Thu 03 Dec 2020 07:31:49 No.12414179 Report

Quoted By: >>12414181 >>12414854

>>12414173
No, you don't deserve it.

Anonymous

Anonymous Thu 03 Dec 2020 07:33:21 No.12414181 Report

Quoted By: >>12414206 >>12414210

>>12414179
I'm sure you don't mean that, but I figured I'd reach out if I couldn't figure it out on my own.

Anonymous

Anonymous Thu 03 Dec 2020 07:33:34 No.12414182 Report

Quoted By: >>12414854

>>12414173
factor denominator by sqrt term

Anonymous

Anonymous Thu 03 Dec 2020 07:34:59 No.12414186 Report

Quoted By: >>12414854 >>12418035

>>12414168
Heh, this must have been purposefully crafted to fuck with people. The cancellations are too good to be coincidental.

Here's a hint: use the fact that $(a+b)(a-b) = a^2 - b^2$ . What should you multiply top and bottom by to take advantage of this?

Anonymous

Anonymous Thu 03 Dec 2020 07:35:27 No.12414189 Report

Quoted By: >>12414854

>>12414173
don't feel like latexing it out but:

multiply top and bottom by the conjugate sqrt (x^2 + 1) - x

a bunch of shit should cancel and you'll get sqrt(x^2+1) - x^2/(sqrt(x^2+1)/

factor out a 1/sqrt(x^2+1) and the x^2's cancel out leaving you with just 1/sqrt(x^2+1)

usually these problems are solved by multiplying top and bottom by whatever the conjugate of the denominator is

Anonymous

Anonymous Thu 03 Dec 2020 07:39:58 No.12414196 Report

Quoted By:

>>12414173
You are kinda retarded. Multiply top and bottom by sqrt(x^2 + 1), cancel out both (x + sqrt) terms. Profit.

Anonymous

Anonymous Thu 03 Dec 2020 07:45:29 No.12414206 Report

Quoted By: >>12414854

>>12414181
Just use wolframalpha you lazy cunt

Anonymous

Anonymous Thu 03 Dec 2020 07:46:40 No.12414210 Report

Quoted By: >>12414854

>>12414181
$\frac{\frac{x}{y} + 1}{y + x} = \left( \frac{\frac{x}{y} + 1}{y + x} \right) \frac{y}{y} = \frac{x + y}{y(y + x)} = \frac{1}{y}$

Anonymous

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Anonymous Thu 03 Dec 2020 07:55:26 No.12414220 Report

Quoted By: >>12414854

>>12414168

Anonymous

Anonymous Thu 03 Dec 2020 09:17:33 No.12414395 Report

Quoted By:

>>12414168
You are retarded. It's a one-passage simplification

Anonymous

Anonymous Thu 03 Dec 2020 11:07:17 No.12414581 Report

Quoted By:

This is a troll thread that gets posted over and over again, but fuck me I can't figure what the troll is supposed to be.

Anonymous

Anonymous Thu 03 Dec 2020 13:49:39 No.12414854 Report

Quoted By:

I ended up going to sleep after >>12414179

The problem may have been that I was grinding so late at night. I should have seen it.

>>12414206
Any pay for pro?

>>12414182
>>12414186
>>12414189
>>12414210
>>12414220
Thanks for the spoon feeding -- I know how annoying it seeing folk ask asking advice.

Anonymous

Anonymous Thu 03 Dec 2020 14:26:59 No.12414953 Report

Quoted By:

>>12414173

Combine the two terms in the numerator; simplify the numerator of the numerator and the denominator (they are in fact identical expressions) by multiplying by its conjugate.

Anonymous

Anonymous Thu 03 Dec 2020 22:17:45 No.12416888 Report

Quoted By:

>>12414168
num: sqrt(x^2+1)+x/sqrt(x^2+1)
Multiply denominator of the fraction in the numerator with the denominator of the whole;
Simplify devision. 1/sqrt(x^2+1)
This is pretty trivial bro
Read basic math by meme Lang

Anonymous

Anonymous Fri 04 Dec 2020 00:17:38 No.12417330 Report

Quoted By:

>>12414168
Hint:

sqrt(1 + x^2) + x = (1 + (x / sqrt(1 + x^2))) * sqrt(1 + x^2)

Anonymous

Anonymous Fri 04 Dec 2020 00:32:34 No.12417380 Report

Quoted By:

>>12414168
Turn everything into exponents dude.

Anonymous

Anonymous Fri 04 Dec 2020 00:39:37 No.12417400 Report

Quoted By: >>12417403

>>12414168
We can rewrite the expression
$\frac{\frac{x}{\sqrt{x^2+1}} + 1}{\sqrt{x^2+1} +x } = \frac{ \frac{x + \sqrt{x^2+1}}{\sqrt{x^2}+1}}{\sqrt{x^2+1} +x } = \frac{x+\sqrt{x^2+1}}{\sqrt{x^2+1}(\sqrt{x^2+1} + x ) } = \frac{1}{\sqrt{x^2 +1}}$

Anonymous

Anonymous Fri 04 Dec 2020 00:40:38 No.12417403 Report

Quoted By: >>12418137

>>12417400
btw, the expression only holds when
$x \not=-\sqrt{x^2+1}$

Anonymous

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Anonymous Fri 04 Dec 2020 00:42:30 No.12417411 Report

Quoted By: >>12417489 >>12419345

>>12414168
Done. Don't bother with fraction bar bullshit.

Anonymous

Anonymous Fri 04 Dec 2020 01:19:19 No.12417489 Report

Quoted By: >>12417864

>>12417411
fuck man the fact that I don't think to do stuff like this is why I will never be good at math.

Anonymous

Anonymous Fri 04 Dec 2020 04:11:32 No.12417864 Report

Quoted By: >>12418160

>>12417489
It's not about thinking about stuff, nigger, it's that you don't do the exercises. Do all the fucking exercises in the book because every exercise reveals a common error or a common challenge.

Anonymous

Anonymous Fri 04 Dec 2020 05:17:28 No.12418035 Report

Quoted By:

>>12414186
Anon.. I cant even-

Anonymous

Anonymous Fri 04 Dec 2020 06:11:49 No.12418137 Report

Quoted By:

>>12417403
https://www.google.com/search?q=y%3Dsqrt(x%5E2%2B1)%2Bx

Anonymous

Anonymous Fri 04 Dec 2020 06:20:51 No.12418160 Report

Quoted By: >>12418234

>>12417864
Fuck me, why don't I do my goddamned homework?

Anonymous

Anonymous Fri 04 Dec 2020 06:44:59 No.12418234 Report

Quoted By:

>>12418160
Don't do it to finish. Do it to learn. Every time that you see a problem and you think "This shit took me hours to finish", work out what you did wrong. Take your time in learning the mistake, write down that mistake in a separate notebook to review what mistakes not to make. Once you're confident, think how you could do that shit faster. Take your time in examining and trimming down your reasoning. Your solving speed will grow exponentially, so just fucking do it.

Anonymous

Anonymous Fri 04 Dec 2020 15:52:42 No.12419345 Report

Quoted By:

>>12417411
based, did it same way. something sexy about seeing you ignore radicals

Anonymous

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Anonymous Fri 04 Dec 2020 16:10:36 No.12419411 Report

Quoted By:

The "trick" about this expression is that a $1$ is obscured, namely

$1=\dfrac{a\cdot c+b}{a\cdot c+b}=c\cdot\dfrac{a+b/c}{a\cdot c+b}$

As a consequence

$\dfrac{1}{c} = \dfrac{a+b/c}{a\cdot c+b}$

where the right hand side looks like it depends on $a$ and $b$ but actually it doesn't.

Use this relation with $a=1, b=x, c=\sqrt{1+x^2}$

Anonymous

Anonymous Fri 04 Dec 2020 16:20:45 No.12419446 Report

Quoted By:

Just multiply the expression with the root and you get 1. Fuck them for givinh you the solution

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