/sci/ - Science & Math » Thread #12366679

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Anonymous Fri 20 Nov 18:53:13 2020 No.12366679 View Reply Original Report

Quoted By: >>12366683 >>12366710 >>12366754 >>12366758 >>12368406

How do you solve for v2 if only h, v1 and d is given?

Anonymous

Anonymous Fri 20 Nov 2020 18:54:33 No.12366683 Report

Quoted By:

>>12366679
by doing your own homework

Anonymous

Anonymous Fri 20 Nov 2020 19:00:05 No.12366710 Report

Quoted By:

>>12366679
>using Latin script for angles

Anonymous

Anonymous Fri 20 Nov 2020 19:16:34 No.12366754 Report

Quoted By:

>>12366679
Let y = h/cos(v1)
Then tan(v2)= sqrt(h^2 - y^2)/(y-d)

Anonymous

Anonymous Fri 20 Nov 2020 19:17:44 No.12366758 Report

Quoted By:

>>12366679
With h and v1 you can get both the vertical and horizontal sides of the right triangle, which you can then use to calculate v2.

In fact you really only need one side of the right triangle, so there are 2 ways to do this

Anonymous

Anonymous Sat 21 Nov 2020 02:45:50 No.12368406 Report

Quoted By:

>>12366679
Law of cosines gives you the hypotenuse of the inner right triangle, call it k.
$k^2 = h^2 + d^2 - 2hd\cos v_1$

Law of sines gives you the angle v2
$\frac{\sin v_1}{k} = \frac{\sin(\pi-v_2)}{h}$
Ah shit you can do the rest.

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