/sci/ - Science & Math » Thread #12359677

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I'm currently working on Spivak's Calculus

Anonymous Wed 18 Nov 23:01:45 2020 No.12359677 View Reply Original Report

Quoted By: >>12359838

and I don't know how to prove the part b.
I'll post the step of the solution in the solution's manual that I don't get so someone can help me out

Anonymous

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Anonymous Wed 18 Nov 2020 23:04:22 No.12359690 Report

Quoted By: >>12359958

If we have to prove it is true for n?k, why would I want the equation to hold just for k<n?
I know it's trivial for k=n and it's reasonable, but how come do you prove it for n?k after that?

Anonymous

Anonymous Wed 18 Nov 2020 23:34:31 No.12359812 Report

Quoted By:

Are you asking why he only shows the proof for k<n, not n?k?

Anonymous

Anonymous Wed 18 Nov 2020 23:41:51 No.12359838 Report

Quoted By:

>>12359677
Just skip it. The proof is obvious

Anonymous

Anonymous Thu 19 Nov 2020 00:07:11 No.12359958 Report

Quoted By:

>>12359690
Because k=n-1<n is the last step. You have shown k<n->k+1 and k=1 true. So 1->2->...->n-1->n.
The n is fixed.

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