/sci/ - Science & Math » Thread #12356940

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Homework help

Anonymous Wed 18 Nov 02:28:11 2020 No.12356940 View Reply Original Report

Quoted By: >>12356972 >>12356978 >>12356987 >>12357213

If y’all could help me I’d appreciate it

Anonymous

Anonymous Wed 18 Nov 2020 02:44:21 No.12356972 Report

Quoted By: >>12356976

>>12356940
$ 4\log_2{p} + \log_2{x} -q = \log_2{\frac{81x}{16}} \\ 4\log_2{p} + \log_2{x} -q = \log_2{81} + \log_2{x} - \log_2{16} \\ 4\log_2{p} - q = \log_2{81} - 4 \\ q = 4, p = \sqrt^4{81} $

Anonymous

Anonymous Wed 18 Nov 2020 02:45:29 No.12356976 Report

Quoted By:

>>12356972
Fuck, what is wrong with the formatting?

$test$

Does TeX no longer work on this board?

Anonymous

Anonymous Wed 18 Nov 2020 02:46:34 No.12356978 Report

Quoted By:

>>12356940
$ 4\log_2{p} + \log_2{x} -q = \log_2{\frac{81x}{16}} // 4\log_2{p} + \log_2{x} -q = \log_2{81} + \log_2{x} - \log_2{16} // 4\log_2{p} - q = \log_2{81} - 4 // q = 4, p = \sqrt^4{81} $

Anonymous

Anonymous Wed 18 Nov 2020 02:49:20 No.12356987 Report

Quoted By:

>>12356940
$4\log_2{p}+\log_2{x}-q=\log_2{\frac{81x}{16}}\implies4\log_2{p}+\log_2{x}-q=\log_2{81}+\log_2{x}-\log_2{16}\implies4\log_2{p}-q=\log_2{81}-4\impliesq=4,p=\sqrt^4{81}4\log_2{p}+\log_2{x}-q=\log_2{\frac{81x}{16}}\implies4\log_2{p}+\log_2{x}-q=\log_2{81}+\log_2{x}-\log_2{16}\implies4\log_2{p}-q=\log_2{81}-4\impliesq=4,p=\sqrt^4{81} $

Anonymous

Anonymous Wed 18 Nov 2020 03:02:09 No.12357012 Report

Quoted By:

p = 3
q = 4

Anonymous

Anonymous Wed 18 Nov 2020 04:56:23 No.12357213 Report

Quoted By:

>>12356940
p = 3
q = 5

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