92KiB, 750x736, EFjwgGaXUAApOgh.jpg View SameGoogleiqdbSauceNAO Anonymous Wed 11 Nov 02:04:58 2020 No.12328701 ViewReplyOriginalReport Quoted By: >>12329252 ...[1(n^2), 2(n^2),1(n^2)]=nn^2 [1(n^3),3(n^3),3(n^3),1(n^3)]=nn^3 ........