/sci/ - Science & Math » Thread #12267980

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Anonymous Sat 24 Oct 15:31:40 2020 No.12267980 View Reply Original Report

Quoted By: >>12267988 >>12268153 >>12268244

Hey /sci/
What’s the answer?

Anonymous

Anonymous Sat 24 Oct 2020 15:33:11 No.12267988 Report

Quoted By: >>12267996

>>12267980
I'm pretty sure you can just type this into a calculator

Anonymous

Anonymous Sat 24 Oct 2020 15:34:57 No.12267996 Report

Quoted By:

>>12267988
Do it by hand

Anonymous

Anonymous Sat 24 Oct 2020 15:37:35 No.12268012 Report

Quoted By: >>12268030

it is equal to infinity

Anonymous

Anonymous Sat 24 Oct 2020 15:40:32 No.12268030 Report

Quoted By: >>12268052

>>12268012
Wrong

Anonymous

Anonymous Sat 24 Oct 2020 15:43:05 No.12268052 Report

Quoted By: >>12268067

>>12268030
Zero?

Anonymous

Anonymous Sat 24 Oct 2020 15:44:53 No.12268067 Report

Quoted By: >>12268110

>>12268052
I believe it goes to 1

Anonymous

Anonymous Sat 24 Oct 2020 15:48:41 No.12268093 Report

Quoted By:

$0$

Anonymous

Anonymous Sat 24 Oct 2020 15:50:56 No.12268110 Report

Quoted By: >>12268121 >>12268123

>>12268067
Wolfram alpha agrees with zero

Anonymous

Anonymous Sat 24 Oct 2020 15:53:08 No.12268121 Report

Quoted By: >>12268132 >>12268239

>>12268110
I just plugged it in and it’s not zero. It approaches zero on both sides, and integrates to 1

Anonymous

Anonymous Sat 24 Oct 2020 15:53:20 No.12268123 Report

Quoted By:

>>12268110
Wolfram alpha is a robofag. The answer is 0 because of the definition of the symbols used to describe the problem, not because a website agrees with you.

Anonymous

Anonymous Sat 24 Oct 2020 15:54:23 No.12268132 Report

Quoted By: >>12268138

>>12268121
Wrong.

Anonymous

Anonymous Sat 24 Oct 2020 15:55:58 No.12268138 Report

Quoted By: >>12268146

>>12268132
Show work then

Anonymous

Anonymous Sat 24 Oct 2020 15:56:38 No.12268146 Report

Quoted By: >>12268175

>>12268138
I'm saying you plugged it in wrong. Show your screenshot.

Anonymous

Anonymous Sat 24 Oct 2020 15:57:36 No.12268153 Report

Quoted By: >>12268155

>>12267980

Anonymous ## Mod Mod Icon 12/21/15(Mon)00:55:56 No.7734126?

Reminder: /sci/ is for discussing topics pertaining to science and mathematics, not for helping you with your homework or helping you figure out your career path.

If you want advice regarding college/university or your career path, go to /adv/ - Advice.

If you want help with your homework, go to /wsr/ - Worksafe Requests.

Anonymous

Anonymous Sat 24 Oct 2020 15:58:05 No.12268155 Report

Quoted By: >>12268185

>>12268153
This isn’t my homework

Anonymous

Anonymous Sat 24 Oct 2020 16:01:52 No.12268175 Report

Quoted By: >>12268239

>>12268146
Show work first.
Oh, and graph the fucking function.

Anonymous

Anonymous Sat 24 Oct 2020 16:03:03 No.12268185 Report

Quoted By:

>>12268155
>Understandable, have a nice day

Anonymous

Anonymous Sat 24 Oct 2020 16:07:58 No.12268208 Report

Quoted By: >>12268222

where is $dx$

El Arcón

El Arcón Sat 24 Oct 2020 16:08:09 No.12268209 Report

Quoted By: >>12268222

It's missing something like "dx" and it's not clear if minus one is inside the integrand.

Anonymous

Anonymous Sat 24 Oct 2020 16:11:07 No.12268222 Report

Quoted By: >>12268233 >>12268276

>>12268208
Implied
>>12268209
>being this retarded
Calc 1 students guaranteed

Anonymous

Anonymous Sat 24 Oct 2020 16:14:56 No.12268233 Report

Quoted By:

>>12268222
can you write that again using $dx$ or at least parentheses?

Anonymous

Anonymous Sat 24 Oct 2020 16:18:23 No.12268239 Report

Quoted By:

>>12268175
No, show your screenshot.
I'm specifically disputing the claim in this post, not making a claim of my own.
>>12268121
>I just plugged it in and it’s not zero.

Anonymous

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Anonymous Sat 24 Oct 2020 16:18:38 No.12268242 Report

Quoted By: >>12268284

Here op I improved it.

Anonymous

Anonymous Sat 24 Oct 2020 16:19:04 No.12268244 Report

Quoted By: >>12268255 >>12268379

>>12267980
The function is zero everywhere, why is the integral not zero?

Anonymous

Anonymous Sat 24 Oct 2020 16:22:27 No.12268255 Report

Quoted By: >>12268379

>>12268244
Because if you say that he's going to pretend the integrand is """implied""" to be just the stuff in the abs and if you say the other thing he pretends that the -1 is part of the integrand too.

Anonymous

Anonymous Sat 24 Oct 2020 16:24:25 No.12268265 Report

Quoted By:

$\int_{-\infty}^{\infty}|x||\frac{1}{x}|dx-1$
$-\int_{-\infty}^{0}x\frac{1}{x}dx+\int_{-\infty}^{0}x\frac{1}{x}dx-1$
$-1$

Anonymous

Anonymous Sat 24 Oct 2020 16:27:44 No.12268276 Report

Quoted By:

>>12268222
>deliberately miscommunicating and then blaming others for not understanding

Anonymous

Anonymous Sat 24 Oct 2020 16:30:41 No.12268284 Report

Quoted By:

>>12268242
the fact that the dots are not equally distanced from the bar makes me extremely uncomfortable

Anonymous

Anonymous Sat 24 Oct 2020 16:38:17 No.12268309 Report

Quoted By: >>12268325 >>12268327 >>12271279

Stupid question, I haven't run into absolute values in Calculus 1 except when integrating 1/x to ln|x|. How do you deal with them?

Anonymous

Anonymous Sat 24 Oct 2020 16:42:41 No.12268325 Report

Quoted By:

>>12268309
in $\mathbb{R}$ just remember that $|f(x)|$ flips up at roots, so it changes sign on the original function to make it positive

Anonymous

Anonymous Sat 24 Oct 2020 16:43:45 No.12268327 Report

Quoted By:

>>12268309
Me neither, but I would guess you separate the integral at the point(s) of discontinuity, like 0 for y=|x|

Anonymous

Anonymous Sat 24 Oct 2020 16:54:54 No.12268364 Report

Quoted By: >>12268372

|x/x|=1
1-1=0
/0dx=0x=0

Anonymous

Anonymous Sat 24 Oct 2020 16:56:55 No.12268372 Report

Quoted By: >>12268388 >>12268391 >>12268408 >>12268417 >>12271279

>>12268364
$\frac{x}{x}$ is not defined at 0

Anonymous

Anonymous Sat 24 Oct 2020 16:59:30 No.12268379 Report

Quoted By: >>12268382 >>12271279

>>12268244
It’s not zero everywhere. It’s not zero anywhere.
It approaches zero at infinity
Look
2^(1/2)-1 =.4...
>>12268255
Definitely a calc 1 student. Cuz you’re a fucking dunce

Anonymous

Anonymous Sat 24 Oct 2020 17:01:26 No.12268382 Report

Quoted By: >>12268390

>>12268379
>OP pic
>2^(1/2)-1 =.4...
bro u ok?

Anonymous

Anonymous Sat 24 Oct 2020 17:02:57 No.12268388 Report

Quoted By:

>>12268372

for x=/=0

Anonymous

Anonymous Sat 24 Oct 2020 17:03:16 No.12268390 Report

Quoted By:

>>12268382
I just realized that that isn’t x^1/x
I can’t read and should probably go to sleep

Anonymous

Anonymous Sat 24 Oct 2020 17:03:28 No.12268391 Report

Quoted By: >>12268405

>>12268372
it is via l'hopital's rule, gb2HS

Anonymous

Anonymous Sat 24 Oct 2020 17:08:53 No.12268405 Report

Quoted By: >>12269221

>>12268391
no nigger, we can show continuity, not that it's defined at 0

Anonymous

Anonymous Sat 24 Oct 2020 17:09:26 No.12268408 Report

Quoted By:

>>12268372

An integral at a single x value is 0 anyway

Anonymous

Anonymous Sat 24 Oct 2020 17:12:28 No.12268417 Report

Quoted By:

>>12268372
proof that x is differentiable on the entire real line, brainlet, let's see where ur criticism takes you

Anonymous

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Anonymous Sat 24 Oct 2020 17:15:02 No.12268425 Report

Quoted By:

Anonymous

Anonymous Sat 24 Oct 2020 21:59:15 No.12269221 Report

Quoted By:

>>12268405
the absolute state of mathcucks

Anonymous

Anonymous Sun 25 Oct 2020 13:03:34 No.12271279 Report

Quoted By:

>>12268372
Functions that are continuous in all but a finite number of points are still integrable. If you want to be pedantic and say that the definition of integrability requires that they're defined over the entire interval of integration, then I get to be pedantic and set f(x)=0 for every x where the function isn't defined and now the integral exists and equals 0.

>>12268379
Well, you're dumb.

>>12268309
You can go full masochist and set $|x| = \sqrt{x^2}$

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