Quoted By:
>3
The head at the middle of the very large tank where fluid speed is small is simply 4 meters. Where the monometer is located, you find the hydrostatic pressure, which turns out to be 12.596 kPa. Then you use Bernoulli: . Compute velocity in the pipe to be 7.30 m/s. Multiple velocity by area to get flow of 0.014 m^3/s or 14 liters/second.
>4
You're given velocity , and you can see that it doesn't depend on time, so you have steady flow. For steady flow, and . Compute all these to get . Steady flow, incompressible Navier-Stokes is , and similarly for the y component. The laplacian term falls out, and you get and similarly for y. Solve both of these (simple) differential equations and set the condition at the origin and finally you get (in pascals).