66KiB, 849x455, brian-greene1.jpg View SameGoogleiqdbSauceNAO Anonymous Wed 14 Oct 09:26:27 2020 No.12229913 ViewReplyOriginalReport Quoted By: >>12230060 >>12230380 z(x, y)' = z(x,y) as you increase the order to infinity i.e. z(x,y)^nth partial derivative of x and y = z(x,y). How hard is it to find a series of solutions for this partial differential equation?