/sci/ - Science & Math » Thread #12210940

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How do I get the forces of ->A, ->B and ->C?

Anonymous Fri 09 Oct 08:50:51 2020 No.12210940 View Reply Original Report

Quoted By: >>12210950 >>12210960

Need help to solve this. I want to find the forces stored in A, B and C but don't know how.

Anonymous

Anonymous Fri 09 Oct 2020 08:51:17 No.12210942 Report

Quoted By: >>12210946

What have you tried?

Anonymous

View Same Google iqdb SauceNAO 121165526_390785412300853_762791 (...).jpg, 777KiB, 3024x4032

Anonymous Fri 09 Oct 2020 08:53:26 No.12210946 Report

Quoted By: >>12210950 >>12210960 >>12211030

>>12210942
Shit wrong picture

Anonymous

Anonymous Fri 09 Oct 2020 08:53:27 No.12210947 Report

Quoted By: >>12210967

pro tip: write vectors as $\hat{\mathbf{x}} x + \hat{\mathbf{y}} y$ . ignore the boldface when writing by hand, the hat is enough to distinguish vectors. adding two vectors is obvious this way

Anonymous

View Same Google iqdb SauceNAO 1602113030213.gif, 2MiB, 230x230

Anonymous Fri 09 Oct 2020 08:54:33 No.12210950 Report

Quoted By:

>>12210940
>>12210946
fucking zoomers

Anonymous

Anonymous Fri 09 Oct 2020 09:00:09 No.12210960 Report

Quoted By: >>12211028

>>12210940
>>12210946
rotate the image for proper viewing if you want our help. we aren't tilting our heads sideways for you

Anonymous

Anonymous Fri 09 Oct 2020 09:04:22 No.12210967 Report

Quoted By:

>>12210947
where do you see a boldface and how do i properly apply that notation
not OP though

Anonymous

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Anonymous Fri 09 Oct 2020 09:23:48 No.12211028 Report

Quoted By: >>12211036 >>12211049

>>12210960

Anonymous

Anonymous Fri 09 Oct 2020 09:24:30 No.12211030 Report

Quoted By:

>>12210946
shit dont move lmao

Anonymous

Anonymous Fri 09 Oct 2020 09:26:22 No.12211036 Report

Quoted By: >>12211049

>>12211028
Kid if you can't solve this, then you might need to switch your school course and go for something more humanistic.

Anonymous

Anonymous Fri 09 Oct 2020 09:27:54 No.12211040 Report

Quoted By: >>12211049

tell us what you are thinking OP. that way we can gauge just how fucking retarded you are (but seriously, tell us what your thought process is)

Anonymous

Anonymous Fri 09 Oct 2020 09:31:42 No.12211049 Report

Quoted By: >>12211054 >>12211067

>>12211028
P>>12211040
I haven't had the time to study mechanics. >>12211036
Im retarded, but Im trying to find the force stored in point A, B and C but I don't know how. im retarded but please help me

Anonymous

Anonymous Fri 09 Oct 2020 09:35:31 No.12211054 Report

Quoted By: >>12211068

>>12211049
There's hardly anything to study here other than precalculus math, I bet you aren't even in Uni.

Anonymous

Anonymous Fri 09 Oct 2020 09:44:58 No.12211067 Report

Quoted By:

>>12211049
you are studying statics. that means nothing moves. that means all forces and torques at all points are zero. i want you to draw the free body diagrams at each point listed, and write the algebraic expressions for the torques at all the points due to forces elsewhere. we'll go from there

also, pro tip, use a '.' as a radix instead of ',' you savage

Anonymous

Anonymous Fri 09 Oct 2020 09:46:04 No.12211068 Report

Quoted By: >>12211074

>>12211054
I took summer classes and passed, but yes I lack precalculus and geometri knowledge. Please be help me. I will not waste people's time again.

Anonymous

Anonymous Fri 09 Oct 2020 09:55:29 No.12211074 Report

Quoted By: >>12211088 >>12211100

>>12211068
in statics all total forces and torques are zero at all points
$\sum_i \mathbf{F}_i = \mathbf{0}$
$\sum_i \boldsymbol{\tau}_i = \mathbf{0}$
torque is defined as
$<br />\boldsymbol{\tau} \equiv \mathbf{r} \times \mathbf{F}<br />$
in your problem, all the forces are perpendicular to the forces, so the cross products reduce to multiplication

i can't actually read your figure to go farther. clean it up first

Anonymous

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Anonymous Fri 09 Oct 2020 10:06:03 No.12211088 Report

Quoted By: >>12211258

>>12211074
I can write the numbers if it may help.

q1= 16kN/m
M1= 57 kN/m
->Q1=(0, -128) kN/m

->D=(0, 19.2) kN/m
->D= (0, -19.2) kN/m

->A=(0, Unknown) kN
->B=(0, Unknown) kN
->C=(0, Unknown) kN

Thats the numbers. I do not understand how to find the answer.

Anonymous

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Anonymous Fri 09 Oct 2020 10:14:17 No.12211100 Report

Quoted By:

>>12211074
Here is one better drawn

Anonymous

Anonymous Fri 09 Oct 2020 10:48:20 No.12211158 Report

Quoted By:

bump

Anonymous

Anonymous Fri 09 Oct 2020 11:54:34 No.12211258 Report

Quoted By:

>>12211088

Select on point, around which you will suppose everything will turn. Let's say you choose point A and you will make everything turn clockwise around it.

Check the direction each of the other forces will try and turn the bar around A. Get the torque from each of these forces in relation with point A. The sum of all of them is ZERO, so your equation will be something like T1+T2-T3-T4+...=0.

Notice that you can do this fixing any point. It is usual to pick a point that you don't know much information about, because it will not show up in the equation to solve.

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