THIS IS THE ALGORITHM
U'R' -- thats it..
(for those of you not familiar with the lingo, the apostrophe indicates a COUNTERCLOCKWISE move) so in this case, the move is the top layer counterclockwise 1/4 turn, and the layer all the way to the right counterclockwise 1/4 turn)
Ive been playing with this move and found a few interesting things.
(STARTING WITH A SOLVED CUBE) If you execute this move (algorithm) then turn the entire cube clockwise 1/4 turn and execute the algorithm again, followed by turning the entire cube clockwise 1/4 turn, execute the algorithm again, turn the cube, algorithm, etc etc etc...
ive found that if you do the algorithm once, then turn etc etc you have to do it 12 times before the cube is back in perfect order.
if you execute the algorithm 2 times before turning the cube everytime, you have to do it 60 times before its back in perfect order.
If you execute the algorithm 3 times before turning everytime, you have to do it 12 times.
If you execute the algorithm 4 times before turning everytime, you have to do it 180 times.
If you execute the algorithm 5 times before turning everytime, you have to do it 60 times.
If you execute the algorithm 6 times before turning everytime, you have to do it 24 times.
If you execute the algorithm 7 times before turning everytime, you have to do it 4 times.
There doesnt seem to be a logical pattern that can help you predict how many times you have to execute the algorithm and turn the cube before its solved again...
My question is, can any of you come up with an equation that can predict how many times you have to do the move and turn the cube before the cube is back in perfect order based on how many times you execute the move before turning the cube? for example, if i wanna know if i do the move 14 times before turning the cube everytime, how many times would i have to do that before its solved again
U'R' -- thats it..
(for those of you not familiar with the lingo, the apostrophe indicates a COUNTERCLOCKWISE move) so in this case, the move is the top layer counterclockwise 1/4 turn, and the layer all the way to the right counterclockwise 1/4 turn)
Ive been playing with this move and found a few interesting things.
(STARTING WITH A SOLVED CUBE) If you execute this move (algorithm) then turn the entire cube clockwise 1/4 turn and execute the algorithm again, followed by turning the entire cube clockwise 1/4 turn, execute the algorithm again, turn the cube, algorithm, etc etc etc...
ive found that if you do the algorithm once, then turn etc etc you have to do it 12 times before the cube is back in perfect order.
if you execute the algorithm 2 times before turning the cube everytime, you have to do it 60 times before its back in perfect order.
If you execute the algorithm 3 times before turning everytime, you have to do it 12 times.
If you execute the algorithm 4 times before turning everytime, you have to do it 180 times.
If you execute the algorithm 5 times before turning everytime, you have to do it 60 times.
If you execute the algorithm 6 times before turning everytime, you have to do it 24 times.
If you execute the algorithm 7 times before turning everytime, you have to do it 4 times.
There doesnt seem to be a logical pattern that can help you predict how many times you have to execute the algorithm and turn the cube before its solved again...
My question is, can any of you come up with an equation that can predict how many times you have to do the move and turn the cube before the cube is back in perfect order based on how many times you execute the move before turning the cube? for example, if i wanna know if i do the move 14 times before turning the cube everytime, how many times would i have to do that before its solved again
