>>12164044start with each of the points at the midpoints of each of the lines of the recgnalge. we can break the shape inside down to right angled triangles and 4 hypotonuses. we know that a^2 + b^2 = c^2, if we were to move a point away from a midpoint, we would be increasing one side of one of these right angles triangles and decreasing another. but as they are squared in pythagoras' theorem, and due to x^2 having a derivative that increases along with x, we know that if we increase one side and decrease the other (by the same amount of course), we would be increasing one of the sides more than we would be decreasing the other, so the sum of the hypotenuses squared would be greater. ok, sure, but this is not perimeter and if you look at the graph for root x, you will see that the derivative decreases. wait but isn't square root inverse of x of x^2, maybe this could imply that the perimeter never changes and OP is being a massive faggot. so for the perimeter to never change, even though the increase is greater than the decrease, when added to the square of the other side and rooted, there is no change in increase and decrease but its also dependent on the other side so yeah maybe this is harder than i thought
