/sci/ - Science & Math » Thread #12155792

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So this is an exponential derivative?

Anonymous Thu 24 Sep 12:22:53 2020 No.12155792 View Reply Original Report

Quoted By: >>12155864 >>12155947 >>12155952

$\left(\left(x^{\left(-1\right)}\right)\left(2^{\left(-1\right)}\right)+1\right)^{x}$

Anonymous

Anonymous Thu 24 Sep 2020 12:24:06 No.12155794 Report

Quoted By:

$\left(\left(x^{\left(-1\right)}\right)\left(2^{\left(-1\right)}\right)+1\right)^{x}[/math$

Anonymous

Anonymous Thu 24 Sep 2020 12:25:35 No.12155799 Report

Quoted By: >>12155877

$\left(\left(x^{\left(-1\right)}\right)\left(2^{\left(-1\right)}\right)+1\right)^{x}$

Anonymous

Anonymous Thu 24 Sep 2020 12:28:39 No.12155810 Report

Quoted By:

Shit sorry, had math scripts blocked

Anonymous

Anonymous Thu 24 Sep 2020 13:00:21 No.12155864 Report

Quoted By: >>12155933

>>12155792
2^(-1)
why not just say 1/2?
also, you might just be overflowing your floats

Anonymous

Anonymous Thu 24 Sep 2020 13:07:03 No.12155877 Report

Quoted By: >>12155933

>>12155799
$ \left ( \dfrac{1}{2x}+1 \right )^x $

Anonymous

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Anonymous Thu 24 Sep 2020 13:18:34 No.12155918 Report

Quoted By: >>12155933

Anonymous

Anonymous Thu 24 Sep 2020 13:28:18 No.12155933 Report

Quoted By: >>12155938 >>12155941

>>12155864
>>12155877
Yeah you're right, that's nicer

>>12155918
See? Weird huh. It's supposed to hone in on ~1.6486...

If something so simple 'overflows' our 'floats', did they really design them right?

Anonymous

Anonymous Thu 24 Sep 2020 13:30:01 No.12155938 Report

Quoted By:

>>12155933
Btw, for context, the farther we go from origo the closer to the derivative. n to infinity

Anonymous

Anonymous Thu 24 Sep 2020 13:30:55 No.12155941 Report

Quoted By: >>12156047

>>12155933
https://www.youtube.com/watch?v=pQs_wx8eoQ8

Anonymous

Anonymous Thu 24 Sep 2020 13:34:14 No.12155947 Report

Quoted By:

>>12155792
Wolfram gives me something far different

Anonymous

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Anonymous Thu 24 Sep 2020 13:35:22 No.12155952 Report

Quoted By: >>12155958

>>12155792
Shit, forgot image

Anonymous

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Anonymous Thu 24 Sep 2020 13:38:20 No.12155958 Report

Quoted By: >>12156033

>>12155952
Scratch that, I'm retarded and I didn't see the domain.
Nice function op, liked it. Batman looking plot.

Anonymous

Anonymous Thu 24 Sep 2020 14:21:20 No.12156033 Report

Quoted By:

>>12155958
Shit, Wolfram too? It's not supposed to do that.

My TI-84 draws it similar but different. Starts jittering earlier, then negative side stretches 8x further than positive. 8:1 vs 2:1. Must be an 8-bit pricessir quirk

Anonymous

Anonymous Thu 24 Sep 2020 14:26:11 No.12156047 Report

Quoted By:

>>12155941
Bretty gud explanation, thanks. So if the software engineers paid attention this wouldn't occur, right?

Anonymous2

Anonymous2 Thu 24 Sep 2020 14:30:25 No.12156055 Report

Quoted By: >>12156083 >>12156128

What are the actual limits as x goes to +infinity and to -infinity? The limit as x goes to 0 should be the square root of e, shouldn't it?

Anonymous

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Anonymous Thu 24 Sep 2020 14:49:28 No.12156083 Report

Quoted By:

>>12156055
True, good catch.

Anonymous

Anonymous Thu 24 Sep 2020 15:09:56 No.12156128 Report

Quoted By: >>12157079

>>12156055
Actually, x going to 0 is undefined here. But that's because I reversed the equation to walk to infinity

$\lim_{n \rightarrow \infty } ({1\over2n}+1)^n = \lim_{h \rightarrow 0} \sqrt[h]{{h\over2}+1} = \sqrt{e}$
where $n = {1\overh}$

Anonymous

Anonymous Thu 24 Sep 2020 15:29:15 No.12156195 Report

Quoted By: >>12156204 >>12156756

https://www.desmos.com/calculator/q4ba48zy5q
here's a fun little relation to play around with

Anonymous

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Anonymous Thu 24 Sep 2020 15:32:14 No.12156204 Report

Quoted By:

>>12156195

which, interestingly enough, also converges to e

Anonymous

Anonymous Thu 24 Sep 2020 18:21:36 No.12156756 Report

Quoted By:

>>12156195
Weird. Animated graphs are nice

Anonymous

Anonymous Thu 24 Sep 2020 20:06:22 No.12157079 Report

Quoted By:

>>12156128
Of course you are right. I was confused by the plot, where the patterns of error made it look like it was converging as x -> 0.

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