/sci/ - Science & Math » Thread #12132202

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Anonymous Thu 17 Sep 19:30:46 2020 No.12132202 View Reply Original Report

Quoted By: >>12132210 >>12132324 >>12132419 >>12132498 >>12132757

Let's say you get a code like this:

9D1746E6084F5019F7845AFDA12BD2AB
F339B37FE528FAB676BD469328B055CC
685B34B69D6C10B2DDB3B21D29832395
CE7E54B29E3F3D3A6C844B0D110B0E65
7025E4F0E8083033EB42308232C8A815
96241319E8D35C0DA1B27D1D3B389696
6C1476A9E565BE4CD277F3794D256E32
DAFAF26794DA83B13716610C25BCF637
AD4E5A5341CD48260276024F28C631EC
78B1B512B9B2F7D1D79738E43724E0F9
A2D507153A3F2A77CC5073E694467082
6ABCFDF8A505272ED18A377FC3FC246C
37DC483BC0103FFF35F448BAAECB7F74
3AFD1C8CE7BCCC4CCFEB92AB9A5D9428
8B116CB4D50DC42FAF75FC421AC13A6A
40FBFCE020A89A023A37D992B147203A
35930D3950714DD8715F8709CCF1BCEF
835819181638B18E6CCB03EC83C0CEFD
E0B209C645070B8A0E3F35CC039FD0AA
06E70A05605B7FF853C748A4803630D1
F1F9BAC388991E65CC1280554F8AC852
7B2D152131AADB6C33FB577DB4E70D23
04DAF517C134FDCDDF68ABDE029401EB

How would you proceed to decrypt it without further information?

Anonymous

Anonymous Thu 17 Sep 2020 19:31:46 No.12132206 Report

Quoted By:

Without any further information I simply wouldn't care about it and just go on with my day.

Anonymous

Anonymous Thu 17 Sep 2020 19:33:06 No.12132210 Report

Quoted By:

>>12132202
Start with frequency analysis, limited to hex digits,

Anonymous

Anonymous Thu 17 Sep 2020 20:18:54 No.12132324 Report

Quoted By:

>>12132202
I would hang myself

Anonymous

Anonymous Thu 17 Sep 2020 20:47:38 No.12132419 Report

Quoted By:

>>12132202
Try to play it as audio and do analysis there, it seems to have wave embeded inthere.

Anonymous

Anonymous Thu 17 Sep 2020 21:01:36 No.12132498 Report

Quoted By:

>>12132202
Find the most common symbol or group of symbols in there because that could be the letter E since it's the most common letter.

Anonymous

Anonymous Thu 17 Sep 2020 22:10:13 No.12132757 Report

Quoted By: >>12132871

>>12132202
if they're md5 try running it through a rainbow table

Anonymous

Anonymous Thu 17 Sep 2020 22:40:01 No.12132871 Report

Quoted By:

I'd look at the block size first, if there is one. That appears to be split into blocks of 16 bytes, and many encryption algorithms use a 16-byte block size, like AES, so I'd think maybe it's AES ciphertext.

MD5 hashes are also 16 bytes (per >>12132757), but a series of different MD5 hashes doesn't make a lot of sense.

Then I'd just try converting the hex straight to ASCII, just in case it's that simple, but that doesn't seem to be the case here.

So, it's probably just some kind of ciphertext encrypted with some algorithm. Without more info, all you can do is try a lot of different algorithms that are easy to bruteforce.

If it's AES or something else strong, you're just going to have to try a dictionary attack against the password used to generate the key, if there even is a password. If it's a key generated by /dev/random and there's no scavenger hunt that could take you to the key or any other clues about it, then it's likely impossible to ever decrypt.

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