/sci/ - Science & Math » Thread #12128751

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Keplerian stuff

Anonymous Wed 16 Sep 20:42:34 2020 No.12128751 View Reply Original Report

Quoted By: >>12129245 >>12130710

I don't understand anything of this problem. Like, I have zero clue what this is, what's going on.

This is not my homework. Could someone walk me through this one step at a time?
I figured understanding this would probably teach me everything about celestial mechanics.

For instance, I didn't find the Gauss functions anywhere online.

Anonymous

Anonymous Wed 16 Sep 2020 21:16:41 No.12128857 Report

Quoted By:

Guys hlep.

Anonymous

Anonymous Wed 16 Sep 2020 22:08:40 No.12128993 Report

Quoted By:

Dammit guys wtf bros

Anonymous

Anonymous Wed 16 Sep 2020 23:34:27 No.12129240 Report

Quoted By: >>12129622

Bump. I am not familiar with physics at all so I can not help but this board can use some genuine academic questions.

Anonymous

Anonymous Wed 16 Sep 2020 23:35:51 No.12129245 Report

Quoted By:

>>12128751
use the stupid question thread and also describe your problem as best as you can, including what you tried to do.
nobody will answer here. there, you're more likely to find an answer

Anonymous

Anonymous Thu 17 Sep 2020 01:26:33 No.12129552 Report

Quoted By: >>12130339 >>12131389

$ \delta \, \epsilon \left ( 0,1 \right ) \\ \displaystyle \prod_{k=0}^{n} \left ( 1 + \delta ^{2^{k}} \right ) = (1+ \delta)(1+ \delta ^{2})(1+ \delta ^{4}) \cdots (1+ \delta ^{2^{n-1}})(1+ \delta ^{2^{n}}) \\ (1- \delta) \prod_{k=0}^{n} \left ( 1+ \delta ^{2^{k}} \right ) = (1- \delta)(1+ \delta)(1+ \delta ^{2})(1+ \delta ^{4}) \cdots (1+ \delta ^{2^{n-1}})(1+ \delta ^{2^{n}}) \\ = (1- \delta ^{2})(1+ \delta ^{2})(1+ \delta ^{4}) \cdots (1+ \delta ^{2^{n-1}})(1+ \delta ^{2^{n}}) \\ = (1- \delta ^{4})(1+ \delta ^{4}) \cdots (1+ \delta ^{2^{n-1}})(1+ \delta ^{2^{n}}) = (1- \delta ^{2^{n}})(1+ \delta ^{2^{n}}) = 1- \delta ^{2^{n+1}} \\ \\ \boxed{(\delta ^{2^n})^2 = \delta ^{2 \cdot 2^n}=\delta^{2^{n+1}}} \\ \displaystyle \prod_{k=0}^{n} \left ( 1+ \delta ^{2^{k}} \right ) = \dfrac{1- \delta^{2^{n+1}}}{1- \delta} \\ \displaystyle \lim_{n \to \infty} \prod_{k=0}^{n} \left (1+ \delta ^{2^{k}} \right ) = \lim_{n \to \infty} \dfrac{1- \delta^{2^{n+1}}}{1- \delta} = \dfrac{1}{1- \delta} $

Anonymous

Anonymous Thu 17 Sep 2020 02:03:19 No.12129622 Report

Quoted By: >>12130692

>>12129240
>this board can use some genuine academic questions.
Anything that can be found on a high school or college homework problem is not a genuine academic question

Anonymous

Anonymous Thu 17 Sep 2020 07:06:05 No.12130339 Report

Quoted By: >>12131389

>>12129552

This has nothing to do with the problem

Anonymous

Anonymous Thu 17 Sep 2020 10:32:28 No.12130692 Report

Quoted By: >>12130713

>>12129622
it's better than the dick ass trash that gets posted otherwise

Anonymous

Anonymous Thu 17 Sep 2020 10:42:36 No.12130710 Report

Quoted By:

>>12128751
No idea desu

Anonymous

Anonymous Thu 17 Sep 2020 10:46:24 No.12130713 Report

Quoted By:

>>12130692
This kind of shit is posted on a daily basis, check the catalog

Anonymous

Anonymous Thu 17 Sep 2020 11:17:59 No.12130745 Report

Quoted By:

You need to interpret the problem first in two dimensions like x and y

Anonymous

Anonymous Thu 17 Sep 2020 14:38:25 No.12131389 Report

Quoted By:

>>12129552
>>12130339

Nice result, much more interesting than the OP's problem.

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