/sci/ - Science & Math » Thread #12113894

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Anonymous Sun 13 Sep 06:42:18 2020 No.12113894 View Reply Original Report

Quoted By: >>12115838

>2020
>I am forgotten

Anonymous

Anonymous Sun 13 Sep 2020 06:44:51 No.12113899 Report

Quoted By: >>12113911

>a middle school math formula

Anonymous

Anonymous Sun 13 Sep 2020 06:49:27 No.12113911 Report

Quoted By:

>>12113899
Elementary you mean

Anonymous

Anonymous Sun 13 Sep 2020 06:53:06 No.12113920 Report

Quoted By: >>12113927 >>12114168 >>12115813

$\displaystyle ax^3+bx^2+cx+d=0 \\ S=2b^3-9abc+27a^2d \\ T=b^2-3ac \\ Q= \sqrt{(2b^3-9abc+27a^2d)^2-4(b^2-3ac)^3}= \sqrt{S^2-4T^3} \\ C= \sqrt[3]{ \frac{1}{2}(Q+2b^3-9abc+27a^2d)} = \sqrt[3]{ \frac{1}{2}(Q+S)} = \sqrt[3]{ \frac{1}{2} \left ( \sqrt{S^2-4T^3}+S \right )} \\ x_1= - \dfrac{b}{3a}- \dfrac{C}{3a}- \dfrac{b^2-3ac}{3aC} = - \dfrac{b}{3a}- \dfrac{C}{3a}- \dfrac{T}{3aC} \\ x_2= - \dfrac{b}{3a}+ \dfrac{C(1+i \sqrt{3})}{6a}+ \dfrac{(1-i \sqrt{3})(b^2-3ac)}{6aC} \\ ~~~~ = - \dfrac{b}{3a}+ \dfrac{C(1+i \sqrt{3})}{6a}+ \dfrac{(1-i \sqrt{3})T}{6aC} \\ x_3= - \dfrac{b}{3a}+ \dfrac{C(1-i \sqrt{3})}{6a}+ \dfrac{(1+i \sqrt{3})(b^2-3ac)}{6aC} \\ ~~~~ = - \dfrac{b}{3a}+ \dfrac{C(1-i \sqrt{3})}{6a}+ \dfrac{(1+i \sqrt{3})T}{6aC} \\ $

Anonymous

Anonymous Sun 13 Sep 2020 06:56:21 No.12113927 Report

Quoted By: >>12113932

>>12113920
>d/a
>few synthetic divisions
>cuadratic formula
Woah, such complex, so (( e l e g a n t )), such math.

Anonymous

Anonymous Sun 13 Sep 2020 06:59:56 No.12113932 Report

Quoted By:

>>12113927
>cuadratic formula
kek

Anonymous

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Anonymous Sun 13 Sep 2020 08:54:46 No.12114144 Report

Quoted By:

Quick! Kill everyone in this thread! I found the quadratic rapist gang!

>square roots myself

Anonymous

Anonymous Sun 13 Sep 2020 09:14:11 No.12114168 Report

Quoted By: >>12114216 >>12114219

>>12113920
What software do you use to write this?

Anonymous

Anonymous Sun 13 Sep 2020 09:36:42 No.12114216 Report

Quoted By:

>>12114168
I refuse to believe that this post is not bait

Anonymous

Anonymous Sun 13 Sep 2020 09:37:45 No.12114219 Report

Quoted By:

>>12114168
LaTeX btw, there should be a guide in the sticky

Anonymous

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Anonymous Sun 13 Sep 2020 13:58:10 No.12114774 Report

Quoted By: >>12115813

>it is year 2020
>kids still can't solve more than 2 roots

Anonymous

Anonymous Sun 13 Sep 2020 19:37:27 No.12115813 Report

Quoted By:

>>12113920
>>12114774
Why not just use the rule of cardigan? Much easier and could be taught to a 5th grader

Anonymous

Anonymous Sun 13 Sep 2020 19:47:30 No.12115838 Report

Quoted By:

>>12113894
>Teleports behind you
> $x_{n+1} = x_{n} - \frac{ax_n^2 + bx_n + c}{2ax_n +b}$
>"Heh, no hard filings"
>Converges quadratically

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