/sci/ - Science & Math » Thread #12093089

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/sqt/ - stupid questions thread

Anonymous Sun 06 Sep 23:28:51 2020 No.12093089 View Reply Original Report

Quoted By: >>12093129 >>12093205 >>12093276 >>12094477 >>12094680 >>12098351 >>12098992 >>12099983

The thread for questions that don't deserve their own thread
For book recommendations, check the sticky and/or the /sci/ wiki. To download free books, check http://gen.lib.rus.ec/
For learning how to use the inboard latex, check the sticky. You can also test your latex before you post by clicking the "TEX" button in your reply box.

If you ask any question, remember that there is almost no universal notation in many fields.

>What is a BAD question?
Help me with this problem.
Do this problem for me.
What does T mean in this equation: $\mu \chi = \frac{33 T}{\aleph}$
>What is a GOOD question?
Here's the problem I'm having trouble with. I've tried ____, but it didn't work. I don't know how to get past _____.
If m is rest mass and c is the speed of light, then what is E in the equation E=mc^2?

previous thread >>12077754

Anonymous

Anonymous Sun 06 Sep 2020 23:39:20 No.12093129 Report

Quoted By: >>12093133

>>12093089
Why can't the universe exist without an observer?

Anonymous

Anonymous Sun 06 Sep 2020 23:39:39 No.12093131 Report

Quoted By:

Where did the touhou poster go? I know that this is a bit off topic but he really did help contribute to the /sqt/.

Anonymous

Anonymous Sun 06 Sep 2020 23:40:18 No.12093133 Report

Quoted By:

>>12093129
Says who? It literally does

Anonymous

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Anonymous Sun 06 Sep 2020 23:41:14 No.12093136 Report

Quoted By: >>12093141 >>12093165 >>12102766

Did they build this knowing it was a waste of money?

Anonymous

Anonymous Sun 06 Sep 2020 23:43:33 No.12093141 Report

Quoted By: >>12093148

>>12093136
what scientific research facilities aren't a waste of money by your standards? at least it found evidence for gravitational waves.

Anonymous

Anonymous Sun 06 Sep 2020 23:44:42 No.12093144 Report

Quoted By: >>12093149

Really dumb question but, I find myself using the solution's manual a lot for the level 2+ physics questions (the textbook that we're using has 3 levels of problems, the 1st is really simple, the 2nd example is like a little bit more complex as it might take 10-15 minutes, while the 3rd level would be like the last question on a midterm), is this 'normal' for students who are not really that good in physics? I feel like whenever I resort to the manual after some attempts, I feel like I'm 'cheating' myself but at the same time, I know that it's better to have an idea of what to do than not have it at all.

Anonymous

Anonymous Sun 06 Sep 2020 23:46:25 No.12093148 Report

Quoted By: >>12093154

>>12093141
What are gravity waves made of? What is 'waving'?

Anonymous

Anonymous Sun 06 Sep 2020 23:46:31 No.12093149 Report

Quoted By: >>12093156

>>12093144
you're probably relying too much on the solution manual.
the level 3 problems aren't meant to be immediately obvious. you're supposed to sit there for a bit, think, try some things before getting an answer. same with level 2, to an extent.
if you know the solution guide exists what's most likely is you're looking at the problem, thinking about whether you know how to do it, and then just going straight to the guide if nothing pops in your head immediately.

I say this because I was the same way and getting rid of my solution guide helped a lot in my understanding.

Anonymous

Anonymous Sun 06 Sep 2020 23:47:47 No.12093154 Report

Quoted By:

>>12093148
what are light waves made of? what is "waving"?

gravity waves are composed of space distortions. like how black holes bend the space around them, except if you imagine a binary black hole system spinning around each other it would look like an oscillating dipole.

Anonymous

Anonymous Sun 06 Sep 2020 23:48:02 No.12093156 Report

Quoted By:

>>12093149
>if you know the solution guide exists what's most likely is you're looking at the problem, thinking about whether you know how to do it, and then just going straight to the guide if nothing pops in your head immediately.
True. Thank you anon, I'll just delete the manual and take it out of the trash if I've spent like 40+ minutes on it.

Anonymous

Anonymous Sun 06 Sep 2020 23:52:09 No.12093165 Report

Quoted By:

>>12093136
That thing takes us one step closer to understanding gravity. What are you even talking about? That station is going to be used for the next 100 yeas, at least.

Anonymous

Anonymous Mon 07 Sep 2020 00:04:27 No.12093184 Report

Quoted By: >>12093197 >>12094427 >>12094620

Im struggling to understand divergence and curl. Not what they represent, I think I understand that fairly well, but how they are defined and how they are computed. I understand that $\nabla$ is an operator, and I understand how you can have something like $\nabla A$ I think (?) but where I am really having an issue is something like $\nabla \cdot A$ or $\nabla \times A$

My issue is that if $\nabla$ is itself an operator, then what you have in the two above looks something like "operator operator operand" instead of the expected "operand operator operand". In other words, I dont see the distanction between the above and something like $y = +*x$ . Can someone tell me what I am missing? I have tried looking at a few videos and my textbook, but they all seem to focus on how to conceptualize and/or understand what the curl and divergence actually mean, not how they are computed. Like, if I have $A = B \times ( \nabla \times C)$ how would I do that? If I am trying to do "something cross C" and that something is del, what am I crossing C with, since del is an operator?

Anonymous

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Anonymous Mon 07 Sep 2020 00:09:08 No.12093195 Report

Quoted By: >>12093200 >>12093217

Why is the moon a perfect circle?

Anonymous

Anonymous Mon 07 Sep 2020 00:09:22 No.12093197 Report

Quoted By: >>12093230

>>12093184
when you think about del being used in front of an operator, it's helpful to think of it like: $ \nabla = \frac{ \partial }{ \partial x} \hat{x} + \frac{ \partial}{ \partial y} \hat{y} + \frac{ \partial }{ \partial z} \hat{z}$
in the 3d case at least, obviously generalized to whatever coordinate system you're using.

Anonymous

Anonymous Mon 07 Sep 2020 00:10:35 No.12093200 Report

Quoted By: >>12093217 >>12093220

>>12093195
most celestial objects are circular because gravity is a central force. meaning when these objects form, the lowest-energy configuration is spherical.

Anonymous

Anonymous Mon 07 Sep 2020 00:13:43 No.12093205 Report

Quoted By: >>12093345

>>12093089
c isnt speed of light there dumbass. its just a magnitude equal to speed of light. theres no meters/sec anywhere in that equation.

Anonymous

Anonymous Mon 07 Sep 2020 00:13:50 No.12093206 Report

Quoted By: >>12093209

How does one get the ratio of x1/x2 = y1/y2 from the equation x1y2=x2y1?
I don't understand the process of rearranging them.

Anonymous

Anonymous Mon 07 Sep 2020 00:15:11 No.12093209 Report

Quoted By: >>12093213

>>12093206
divide both sides by x2y2
the y2 cancels on the left and the x2 cancels on the right

Anonymous

Anonymous Mon 07 Sep 2020 00:16:47 No.12093213 Report

Quoted By: >>12093218

>>12093209
How fuck that worked, how did you think of that?

Anonymous

Anonymous Mon 07 Sep 2020 00:18:29 No.12093217 Report

Quoted By: >>12095405

>>12093195
It's actually not a perfect circle, but it is close enough that it appears as one to us. If you were to measure it really precisely, you would find all sorts of irregularities like mountain ranges and the like. In fact, the back side of the moon is actually considerably thicker than the side that faces the earth (by several kilometers, I think, but dont quote me on that) This is the case with all rocky bodies.

If you are asking why it is a circle (as opposed to a geometrically perfect circle) see>>12093200 Basically the idea is that the center of gravity of a planet or moon is at its exact center (hence the term center of gravity) and all parts of the body are pulled towards this point with approximately the same force, so mass tends to evenly distribute itself around over time. The lowest energy state (and thus the configuration that will be reached over time) is where all mass is as close to evenly spread out as possible.

Anonymous

Anonymous Mon 07 Sep 2020 00:18:46 No.12093218 Report

Quoted By:

>>12093213
it's a very common process. think of what equation you have and what equation you want to get. think of what sort of operations you can do to both sides (since you're free to do anything as long as you do it to both sides) to get from what you have to what you want.

the more you do manipulations like this the more comfortable you'll be

Anonymous

Anonymous Mon 07 Sep 2020 00:19:09 No.12093220 Report

Quoted By: >>12093225

>>12093200
I thought gravity wasn't a force, but a pseudo force. Isn't it too weak to have any affect on such massive physical objects? Or is it because these celestial objects start out as like liquid lava and then cool & harden

Anonymous

Anonymous Mon 07 Sep 2020 00:22:51 No.12093225 Report

Quoted By:

>>12093220
gravity is a force. it is one of the four fundamental forces
gravity is a weak force, but when you have extremely massive objects (i.e. planets) then the collective strength of the gravitational field they produce is large.
even everyday objects are affected by each other's gravity. there's a gravitational attraction between you and your computer screen. the difference is you're both experiencing a much larger attraction to the massive planet below you, so you don't notice anything. but if you were in space with just your computer monitor, over a long period of time you would be pulled closer together.

it's like one electron doesn't produce that much of an electric field, but if you were to put 10^20 electrons together (ignoring the impossibility) then the collective electric field would be massive.

Anonymous

Anonymous Mon 07 Sep 2020 00:25:07 No.12093230 Report

Quoted By: >>12093243 >>12093253 >>12094620

>>12093197
I get that, but $\nabla = \frac{ \partial }{ \partial x} \hat{x} + \frac{ \partial}{ \partial y} \hat{y} + \frac{ \partial }{ \partial z} \hat{z}$ of what? If it was $A = ( \nabla B \times C )$ instead of $A = ( \nabla \times C )$ then I would understand. then you would be saying $\nabla = \frac{ \partial A }{ \partial x} \hat{x} + \frac{ \partial B}{ \partial y} \hat{y} + \frac{ \partial C }{ \partial z} \hat{z}$ Otherwise, what am I taking the partial derivative with respect to x *of*?

Anonymous

Anonymous Mon 07 Sep 2020 00:30:49 No.12093243 Report

Quoted By: >>12093253 >>12093338

>>12093230
nothing, until you act on something. think of it as a vector where the entries are partial derivatives. when these derivatives hit something on the right side, they act on it.

similarly, think of a constant vector (1,2,3). when you dot this vector with another one, you multiply the components by 1,2, and 3 respectively. but when you don't act it on anything then what is it doing? it's just there.

to help your understanding, I recommend you do: $C=f \hat{x} + g \hat{y} + h \hat{z} \\ f \equiv f(x,y,z) \text{ same with g, h} \\ A= \nabla \times C$
treat the del as you would any vector, and what would you end up with for A? (f, g, h are arbitrary)

Anonymous

Anonymous Mon 07 Sep 2020 00:34:57 No.12093253 Report

Quoted By: >>12093338

>>12093243
>>12093230
adding to this because I always end up thinking of more helpful things, you say you understand $A= \nabla B$ . but what are you doing here? think about this in terms of the definition of del that I gave earlier.

you're taking the partial of B with respect to x and then that's the x hat component, and then repeating with y and z. is that not just the same thing as multiplying the vector representation of del by a scalar function B?
with this line of thinking, del is a vector function. vectors can be dotted with other vectors (divergence) or crossed with other vectors (curl) or multiplied by scalar functions (gradient).

Anonymous

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Anonymous Mon 07 Sep 2020 00:43:00 No.12093275 Report

Quoted By: >>12093348

Anonymous

Anonymous Mon 07 Sep 2020 00:43:04 No.12093276 Report

Quoted By: >>12093291 >>12093348

>>12093089
What exists outside the universe?

Anonymous

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Anonymous Mon 07 Sep 2020 00:45:22 No.12093283 Report

Quoted By: >>12093289 >>12093290

How do I do this problem?
I can't relate linear density formula (u = m/L) to the density formula (p=m/V), I know that I'm supposed to get u=p*A (pi*r^2) but how though?

Anonymous

Anonymous Mon 07 Sep 2020 00:48:01 No.12093289 Report

Quoted By: >>12093305

>>12093283
V = A*L

Anonymous

Anonymous Mon 07 Sep 2020 00:48:11 No.12093290 Report

Quoted By: >>12093305

>>12093283
you have density that relates to the entire volume of the object
the linear density is the density per unit length. when you remove the "length" aspect of a wire, what are you left with? just a cross-sectional area. so your volumetric density times your cross sectional area is your linear density.

Anonymous

Anonymous Mon 07 Sep 2020 00:48:14 No.12093291 Report

Quoted By:

>>12093276
Define 'the universe'.

Anonymous

Anonymous Mon 07 Sep 2020 00:55:22 No.12093305 Report

Quoted By: >>12093312

>>12093290
>>12093289
Thank you both!

Anonymous

Anonymous Mon 07 Sep 2020 00:57:40 No.12093312 Report

Quoted By:

>>12093305
Cheers, lad.

Anonymous

Anonymous Mon 07 Sep 2020 01:10:24 No.12093338 Report

Quoted By: >>12093366 >>12093374

>>12093253
>>but when you don't act it on anything then what is it doing? it's just there
Thats my point, without anything to act on, it has no value, and if it has no value, no real meaning, how can you take the cross product between it and a vector?

>> treat the del as you would any vector, and what would you end up with for A?
How do you treat it as a vector? It isnt a vector, its an instruction. I am seeing this as being the same thing as y = +*x. It's an invalid operation, a syntax error. "+" is an instruction saying "add", "*" is an instruction saying to multiply, and "x" is some number. So I would read this as "y is equal to addition multiplied by x" or more generally, "y is equal to <instruction> <instruction> <value>". You cant multiply x by addition. addition/multiplication instructions needs to values to operate on, ie <value> <instruction> <value>. The same goes for the cross and dot product. when I see $A = \nabla \times C$ I see this as "A is equal to <instruction> <instruction> <value>"

>>12093243
>> is that not just the same thing as multiplying the vector representation of del by a scalar function B?
Yes, but in the case of $\nabla B$ you are taking the partial derivative of B with respect to x, y, and z respectively. But the vector representation of del still isnt a vector really, its still an instruction. If you take the B away, it has no meaning.

Thank you for helping with this by the way, I really appreciate it.

Anonymous

Anonymous Mon 07 Sep 2020 01:16:31 No.12093345 Report

Quoted By:

>>12093205

What units do you think energy is measured in anon?

Anonymous

Anonymous Mon 07 Sep 2020 01:20:05 No.12093348 Report

Quoted By: >>12095448 >>12102404

>>12093275
Did you have a question?

>>12093276
That depends. if the "universe" is defined as "all there is" then nothing can exist outside of it, as by definition, if it exists, then it is contained within the universe.

Are you asking what exists in a physical location beyond the edge? If so, that also depends. First of all, there may or may not even be an "edge" in the first place. We can see about 14.5 billion light years in all directions, and we call this region of space the "observable universe" because it is what we can see. It might be that this is all there is, and there is either a boundary or something else (more on that in a bit) when you reach that point. But it could also be that there is just more stuff beyond, that the point in space 14.5 billion light years from us actually isnt any different from any other location, and there is more stuff on all sides of that point, ie there is no "boundary", it just keeps going. This is because if, hypothetically, we assume that there *is* more universe beyond the observable universe, we would be unable to see it from our current location, because light from that region of space has not had enough time to reach us. The universe is 14.5 billion years old, so anything further than the distance light travels in 14.5 billion years will be fundamentally un-observable to us.

For the sake of exploring the idea, lets say we suddenly are able to instantly teleport to any location in the universe, and so we teleport to a point in space 14.5 billion light years away. I mentioned two possibilities, that there is some sort of "boundary" or that there is not. Assuming there is a boundary, we dont know quite what it would look like. One idea is that it would be like trying to sail off the edge of the earth: you just end up on the other side, and eventually going in a circle, back where you started. It is also possible that there is a boundary, but it is further away, or it could just go on forever.

Anonymous

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Anonymous Mon 07 Sep 2020 01:20:22 No.12093349 Report

Quoted By: >>12093354

Just posting this again!!

How do i draw this??
I'm doing organic chem first year at uni but i just have no clue how this is happening? I have only just touched on organic chemical reactions so I have no clue how they occur?
I've written this out from what I know.. I just don't know how to draw it out like the arrows and what loses what and where it comes from - and exaplain the whole pathway in detail!??
If it would be easier to explain over discord I can post my ID
Thanks frens

Anonymous

Anonymous Mon 07 Sep 2020 01:23:12 No.12093354 Report

Quoted By: >>12093359

>>12093349
I hear your question, your call into the void for help, but I posses not the answers you seek.
krosis.

Anonymous

Anonymous Mon 07 Sep 2020 01:27:33 No.12093359 Report

Quoted By:

>>12093354
That's okay I appreciate that.

Anonymous

Anonymous Mon 07 Sep 2020 01:31:14 No.12093366 Report

Quoted By: >>12093374 >>12093395

>>12093338
>without anything to act on, it has no value
This is true. on its own, it doesn't mean anything.

I think a lot of your problem in understanding right now is your understanding of vectors. What is a vector? If you think it's a "magnitude and a direction," I would challenge you to try and think of them more abstractly.
Anything that you can put into a vector form is a vector. You can have a vector of functions $\overrightarrow{F}=A(x,y) \hat{x} + B(x,y) \hat{y}$ . Are you comfortable with this? On its own, what would you say the "meaning" of this vector would be? It doesn't necessarily have one, it's just a collection of functions that are to be used for a certain purpose.

>How do you treat it as a vector? It isnt a vector, its an instruction.
But it is a vector. We'll get to this.
I understand your point where you say y=+*x doesn't make sense. That's because + and * are operations that take two inputs. What kind of operation is $\frac{ \partial }{\partial x}$ ? It is an operation, correct, but it only takes one input. $\frac{ \partial }{\partial x} f(x,y)$ has a meaning, while +f(x,y) doesn't.
So, we see that we can "multiply" a partial derivative operator by an expression and it is a valid thing to do (it just returns the derivative of the expression), while the same isn't quite true for addition and multiplication.

Now, how do we treat a vector of partial derivatives? Just the same as we would treat any other vector. Instead of the entries being numbers, or functions, or expressions, they are partial derivatives.

>But the vector representation of del still isnt a vector really, its still an instruction.
Still, try to break away from thinking of this as an "instruction," rather than a vector of partial derivatives.
When you compute $\nabla B$ what are you doing? First, you differentiate this wrt x and then put this in the x component of a final vector. (cont.)

Anonymous

Anonymous Mon 07 Sep 2020 01:36:37 No.12093374 Report

Quoted By: >>12093395

>>12093366
>>12093338
If we wanted to write this step mathematically, we would write $\frac{ \partial }{\partial x} B \hat{x}$
What happens when we act with the vector representation of $\nabla \text{ on } B \text{ ? } (\frac{ \partial }{ \partial x} \hat{x} + ...)B= \frac{ \partial B}{ \partial x} \hat{x} + \text{ same for y, z}$ . We get the same result.

What this is all leading to is that there is an explicit vector representation of del (provided that you know how many dimensions you're working with), that is equivalent to the gradient operation. When we use this vector representation in different ways, we recover the divergence and curl.

>If you take the B away, it has no meaning.
On its own, del is a vector differential operator. The vector itself has the meaning that it is ready to act on something to the right. It "operates" on expressions. You can't graph an operator, so maybe that's what you mean by it "has no meaning"?

Anonymous

Anonymous Mon 07 Sep 2020 01:50:10 No.12093395 Report

Quoted By: >>12093400

>>12093374
>>12093366
I think this finally has gotten through my thick skull... so if B is a vector with 3 components, you could write $A = \nabla \times C$ as $(\frac{ \partial Ax }{\partial x} + \frac{ \partial Ay }{\partial y} + \frac{ \partial Az }{\partial z}) \times (Ax + Ay + Az)$ right?

Anonymous

Anonymous Mon 07 Sep 2020 01:51:32 No.12093400 Report

Quoted By: >>12093423

>>12093395
wait no, I wrote that wrong, should be

$A = \nabla \times B$

and

$(\frac{ \partial Bx }{\partial x} + \frac{ \partial By }{\partial y} + \frac{ \partial Bz }{\partial z}) \times (Bx + By + Bz)$

Anonymous

Anonymous Mon 07 Sep 2020 01:56:45 No.12093407 Report

Quoted By:

posting >>12090334 again in case someone knows some commutative algebra
in general i was just looking for a field extension of $\mathbb{Q}$ of degree 3 that wasn't pure cubic (so not of the form $\mathbb{Q} (\sqrt[3]{k})$ for some rational k). the wikipedia article on cubic fields shows that specific polynomial as an example of a non-pure cubic field so i figured it would be easier to show, but apparently not
but if anyone has any other example of such an extension that is easier to check that would be great too, i can only think in terms of degree 3 polynomials with 1 real and 2 complex roots

Anonymous

Anonymous Mon 07 Sep 2020 02:06:28 No.12093423 Report

Quoted By: >>12093447

>>12093400
Almost correct, but getting quite close.
First of all, are you writing $(Bx + By + Bz) \text{ when you mean } (Bx \; By \; Bz)$ like as a vector?

Explicitly, you would write $A = \nabla \times B$ as:
$ A= \begin{bmatrix} \frac{ \partial }{ \partial x} \\ \frac{ \partial }{ \partial y} \\ \frac{ \partial }{ \partial z} \end{bmatrix} \times \begin{bmatrix} B_x \\ B_y \\ B_z \end{bmatrix} = \text{det} \begin{bmatrix} \hat{x} & \hat{y} & \hat{z} \\ \frac{ \partial }{ \partial x} & \frac{ \partial }{ \partial y} & \frac{ \partial }{ \partial z} \\ B_x & B_y & B_z \end{bmatrix} $

let me know if this clears things up or makes it more confusing

Anonymous

Anonymous Mon 07 Sep 2020 02:16:08 No.12093447 Report

Quoted By: >>12093449

>>12093423
>> First of all, are you writing (Bx+By+Bz) when you mean (BxByBz) like as a vector?

yes, thanks

This answers everything I think, but to confirm, when you do "partial derivative with respect to x times By" for example, (in the matrix multiplication) do you just then take the partial derivative of By with respect to x?

Anonymous

Anonymous Mon 07 Sep 2020 02:18:34 No.12093449 Report

Quoted By: >>12093470

>>12093447
Yes.
By is just the y component of the vector B. It can depend on the variables x,y,and z though. This is one of the more confusing nuances because when it's abstracted like this you don't necessarily realize that.

$\frac{ \partial }{ \partial x} * B_y = \frac{ \partial B_y}{ \partial x}$

Anonymous

Anonymous Mon 07 Sep 2020 02:24:14 No.12093470 Report

Quoted By: >>12093472

>>12093449
You have successfully freed me of a mental trap I have been stuck in for the past 72 hours, and thus have earned my undying gratitude.

When you put it like that, it seems so obvious lol. I guess everything does in retrospect. Whenever I end up getting stuck on an idea, it seems to always be that one thing that NOBODY else has an issue with, or at least nobody asks the question the way I would.

Again, thank you so much for taking the time to help me with this, I am sure most people would have just given up after round one, or not taken the effort to adapt what they were saying based on how I was interpreting what you had said before.

Anonymous

Anonymous Mon 07 Sep 2020 02:25:19 No.12093472 Report

Quoted By:

>>12093470
>Whenever I end up getting stuck on an idea, it seems to always be that one thing that NOBODY else has an issue with, or at least nobody asks the question the way I would.
yep, these are always hard to clear up because the online resources aren't geared towards these types of problems. that's why stuff like this and in-person instruction is best, because you can ask specific questions.

cheers

Anonymous

Anonymous Mon 07 Sep 2020 03:49:22 No.12093626 Report

Quoted By: >>12093634

Should I even bother joining the research lab of a chinese professor with mostly foreign chinese students? seems like they would just converse amongst themselves in chinese and leave me out of most things, but does anyone have experience in the situation?

Anonymous

Anonymous Mon 07 Sep 2020 03:51:20 No.12093634 Report

Quoted By: >>12093659

>>12093626
only if the lab is extremely well-known and you'd be doing high quality work.
otherwise if there's a lab of even remotely similar quality, join that one instead,

Anonymous

Anonymous Mon 07 Sep 2020 03:52:26 No.12093637 Report

Quoted By: >>12093642

If I am given the task "Prove A B"
and I prove you can always get from A to B
Have I completed the task?

Anonymous

Anonymous Mon 07 Sep 2020 03:53:57 No.12093642 Report

Quoted By: >>12093646

>>12093637
this falls under "horribly-worded question because we have no idea about the details"

Anonymous

Anonymous Mon 07 Sep 2020 03:56:04 No.12093646 Report

Quoted By: >>12093649

>>12093642
I was doing a calculus III exercise that asked for me to show two vectors are linearly dependent if and only if they are parallel. I showed algebraically two linearly dependent lines are always parallel. Did I answer the question?

Anonymous

Anonymous Mon 07 Sep 2020 03:58:53 No.12093649 Report

Quoted By: >>12093658

>>12093646
since it's "if and only if" and you proved that linear dependent -> parallel, you have to also show parallel -> linearly independent, unless your proof is symmetric (in which case you state that you could do the steps backwards and prove the converse)

Anonymous

Anonymous Mon 07 Sep 2020 04:03:28 No.12093658 Report

Quoted By:

>>12093649
Thanks anon for clearing up the logic. It does seem to indeed be symmetric.

Anonymous

Anonymous Mon 07 Sep 2020 04:04:38 No.12093659 Report

Quoted By:

>>12093634
ok thanks, i will probably just look elsewhere

Anonymous

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Anonymous Mon 07 Sep 2020 05:53:47 No.12093906 Report

Quoted By: >>12093939

Dumb thought experiment:
I have an accelerating mass on a circular track, with a laser shining through a portion of the track. No losses due to friction, ideal scenario, etc, etc. Several questions:
>Does the laser blueshift?
>If it does, then the laser gains energy. I presume energy is transferred from the mass to the laser?
>If it does, then does the mass attempt to decelerate in the absence of a driving force?
>Finally, what happens when the mass clears the laser and it is allowed to shine back to the other end of the track? Where does the blueshifted energy go?

Anonymous

Anonymous Mon 07 Sep 2020 06:07:40 No.12093939 Report

Quoted By: >>12093953

>>12093906
>Does the laser blueshift?
yes, you're moving towards the emitter
>If it does, then the laser gains energy. I presume energy is transferred from the mass to the laser?
your understanding of redshift and blueshift is incorrect. the light is blueshifted because the relative motion between the source and the observer.
energy is not conserved across different reference frames, so there is no absolute gain in energy that comes from anything.
>If it does, then does the mass attempt to decelerate in the absence of a driving force?
this makes no sense, see above
>Finally, what happens when the mass clears the laser and it is allowed to shine back to the other end of the track? Where does the blueshifted energy go?
it doesn't go anywhere because there's no extra energy in the system

Anonymous

Anonymous Mon 07 Sep 2020 06:13:37 No.12093953 Report

Quoted By: >>12093999 >>12094008

>>12093939
>your understanding of redshift and blueshift is incorrect
How does energy not transfer from the mass to the laser?
c = (lambda) * (frequency)
E = h * (frequency)
If the laser does indeed blueshift, then the energy of the laser should increase, yea?

Anonymous

Anonymous Mon 07 Sep 2020 06:33:42 No.12093999 Report

Quoted By: >>12094021

>>12093953
The energy of the laser is higher in the car's frame when it's moving towards the laser. This doesn't break any laws, it's purely due to the relative motion
>transfer from the mass to the laser
what does this mean? there's no "transfer" happening. the car sees the light as higher energy, that's it.

when dealing with different reference frames, only invariant quantities are unchanged. the relevant invariant quantity would be $E^2-(pc)^2$ this is the same in all reference frames. the momentum p for light is given by $p= \hbar k= \frac{h}{ \lambda }$ . This quantity is the same to the laser and to the car.

Anonymous

Anonymous Mon 07 Sep 2020 06:38:05 No.12094008 Report

Quoted By: >>12094021

>>12093953
also, just to reiterate. how would there be energy transfer from the mass to the laser? there's no force between them, no interaction. in order to transfer energy there has to be some kind of interaction.

Anonymous

Anonymous Mon 07 Sep 2020 06:47:15 No.12094021 Report

Quoted By: >>12095395

>>12094008
I'm still reading >>12093999 but my line of thinking is as follows:
Blueshifted light gains energy. I am assuming energy is conserved (until I understand 12093999). If it is conserved, then how did the light gain energy? Naive guess is it's being transferred from the kinetic energy of the mass to the light.
I'm not really used to multiple frames of references, so I'll work out how the invariant would be used in my model.

Anonymous

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Anonymous Mon 07 Sep 2020 09:33:04 No.12094282 Report

Quoted By:

Is this correct?

Anonymous

Anonymous Mon 07 Sep 2020 10:41:12 No.12094427 Report

Quoted By:

>>12093184
>My issue is that if ? is itself an operator, then what you have in the two above looks something like "operator operator operand"
? is an operator, ?· is an operator, ?× is an operator. The naming is mnemonic, you're not *literally* taking the dot or cross product of ? with a vector.

Given f : R^n->R, ?f : R^n->R^n = <?f/?x, ?f/?y, ?f/?z, ...>
Given f : R^n->R^n, ?·f : R^n->R = ?f_x/?x+?f_y/?y+?f_z/?z+...
Given f : R^3->R^3, ?×f : R^n->R^n = <?f_z/?y-?f_y/?z, ?f_x/?z-?f_z/?x, ?f_y/?x-?f_x/?y>
where f_x is the x component of f etc.

Now, if you don't worry too much about what it "means" to have a vector of partial differentiation operators, you just need to remember that ?=<?/?x, ?/?y, ?/?z, ...>, and then you can easily remember how the actual operators are defined. Just substitute the components of that vector and the components of f into the expressions for dot and cross product with juxtaposition indicating application rather than multiplication.

Anonymous

View Same Google iqdb SauceNAO unnamed.png, 76KiB, 300x300

Anonymous Mon 07 Sep 2020 11:10:01 No.12094472 Report

Quoted By: >>12094495

when seeing a circle, we're just seeing a 2d section of a sphere; when seeing a sphere, we're just seeing a 3d section of an hypersphere and so on, right? so this means that we're always just always seeing a section of an n-dimensional object, right? is there a name for the pure "sphere" that isn't a section of anything and has ""infinite"" dimensions?

Anonymous

Anonymous Mon 07 Sep 2020 11:14:39 No.12094477 Report

Quoted By: >>12094508

>>12093089
If I wanted to make my own 2d game engine to learn programming, how much math do I actually need? Surely not as much as it would take to make a 3d game, right? So I don't have to study all of calculus 3 and linear algebra as well as physics?

Anonymous

Anonymous Mon 07 Sep 2020 11:21:25 No.12094495 Report

Quoted By:

>>12094472
infinite dimensional spheres do exist but your logic is weird. a circle is a circle, it's independent of any higher dimensional objects. it's true that a cross section of a sphere is a circle, but that doesn't mean this is what circles *really are* in some fundamental way.

Anonymous

Anonymous Mon 07 Sep 2020 11:27:52 No.12094508 Report

Quoted By:

>>12094477
It depends. "2D" usually means axis-aligned rectangles and orthographic projection whereas "3D" means arbitrary triangles with rotations and a perspective projection. Which makes 2D much simpler.

Note that even 3D only requires the "basics of the basics" for linear algebra (no eigenvectors, decompositions, etc), and doesn't necessarily require any calculus (calculus is used mostly for determining surface normals for curved surfaces, and for physics).

Anonymous

Anonymous Mon 07 Sep 2020 12:39:10 No.12094620 Report

Quoted By: >>12094632

>>12093184
>>12093230

The nabla symbol is an operator because it's a differential operator. You can think of it as a vector filled with differential operators. Therefore, all vector arithmatic still aplies so you can take the dot product and the cross product between it and a vector.

vector arithmatic:
vector times scalar
$\vec v \alpha = \begin{pmatrix}\alpha v_1\\ \alpha v_2 \\ \alpha v_3 \end{pmatrix}$
vector dot product:
$\vec v \cdot \vec u = v_1 u_1 + v_2 u_2 + v_3 u_3$
vector cross product:
$\vec v \times \vec u = \begin{pmatrix}v_2 u_3 - v_3 u_2 \\ v_3 u_1 - v_1 u_3 \\ v_1 u_2 - v_2 u_1 \end{pmatrix}$

given some scalar function $f(x,y,z)$ and some vector function $\vec v(x,y,z)=\begin{pmatrix}v_x(x,y,z)\\ v_y(x,y,z)\\v_z(x,y,z)\\\end{pmatrix}$ and using the notation $\partial_x = \frac{\partial}{\partial x}$ while also using vector components x,y,z instead of 1,2,3 we get:

gradient (nabla times some scalar function of x,y,z)
$\nabla f(x, y, z) = \begin{pmatrix}\partial_x f(x,y,z)\\ \partial_y f(x,y,z) \\ \partial_z f(x,y,z) \end{pmatrix}$
divergence (dot product of nabla with some vector function of x,y,z)
$\nabla \cdot \vec v(x,y,z) = \partial_x v_x(x,y,z) + \partial_y v_y(x,y,z) + \partial_z v_z(x,y,z)$
curl (cross product of nabla with some vector function of x,y,z)
$\begin{pmatrix}\partial_y v_z - \partial_z v_y \\ \partial_z v_x - \partial_x v_z \\ \partial_x v_y - \partial_y v_x \end{pmatrix}$

Anonymous

Anonymous Mon 07 Sep 2020 12:42:43 No.12094632 Report

Quoted By:

>>12094620
Note, since it is an operator, not ALL arithmetic operations apply (BAC-CAB rule won't work for instance), but for these basic operations it does work.

Anonymous

Anonymous Mon 07 Sep 2020 12:56:19 No.12094670 Report

Quoted By: >>12094683

i want to calculate the increasing in a stock between the value i bought and the current value, will dividing the values do the trick?

Anonymous

Anonymous Mon 07 Sep 2020 12:59:19 No.12094680 Report

Quoted By:

>>12093089
Is there any actual validity to CBD for anxiety? Used to have quick bad anxiety related to my schizophrenia, was on antipsychotics and benzos for a while but now my anxiety seems much milder and more of an annoyance than a medical issue and I've heard CBD is good for mild anxiety and stress

Anonymous

Anonymous Mon 07 Sep 2020 13:00:42 No.12094683 Report

Quoted By: >>12094773

>>12094670
Percentage?
Divide the difference between the current value and the old value by the old value, then multiply by 100.

Anonymous

Anonymous Mon 07 Sep 2020 13:48:55 No.12094773 Report

Quoted By:

>>12094683
thanks this will do i was curious if my way of calculating was on the right path

Anonymous

View Same Google iqdb SauceNAO 1560462932178.jpg, 223KiB, 840x525

Anonymous Mon 07 Sep 2020 16:02:31 No.12095000 Report

Quoted By: >>12095186 >>12095309

Let d20 denote a die with 20 faces numbered from 1 to 20. Assume that, when thrown, a d20 has the same probability of landing in any face.
If someone throws 2d20 and pick the highest value, what is the new probability disdistribution.
How do I approach this problem?

Anonymous

Anonymous Mon 07 Sep 2020 16:47:22 No.12095098 Report

Quoted By: >>12095101 >>12095106 >>12095174 >>12095180

how?
would cos(t) * -sin(t) not be -sin(2t)/2 ?
then when you integrate that you would get cos(2t)/4 right???

Anonymous

View Same Google iqdb SauceNAO uhhh.png, 3KiB, 285x74

Anonymous Mon 07 Sep 2020 16:49:19 No.12095101 Report

Quoted By: >>12095106 >>12095180

>>12095098
forgot pic

Anonymous

Anonymous Mon 07 Sep 2020 16:50:58 No.12095106 Report

Quoted By:

>>12095098
>>12095101
also I realize they used u-sub but shouldnt the use of trig identities give the same result?

Anonymous

Anonymous Mon 07 Sep 2020 17:00:25 No.12095136 Report

Quoted By: >>12095143

How do I select the most important things in A textbook? Like brah, how the chapter is 30 pages long, each filled with Boldface and Illustrations that have like 15 parts But the Sumary is only 1.5 pages long, makes no sence.
I'm studying campbell Bio btw

Anonymous

View Same Google iqdb SauceNAO clownworld.png, 602KiB, 640x624

Anonymous Mon 07 Sep 2020 17:03:28 No.12095143 Report

Quoted By:

>>12095136
>sense
I'm retarded

Anonymous

Anonymous Mon 07 Sep 2020 17:16:06 No.12095174 Report

Quoted By:

>>12095098
>would cos(t) * -sin(t) not be -sin(2t)/2 ?
They're the same thing.

Anonymous

Anonymous Mon 07 Sep 2020 17:18:36 No.12095180 Report

Quoted By:

>>12095101
>>12095098
>you would get cos(2t)/4 right???

They're the same thing bud. You can check using the trig identities

Anonymous

Anonymous Mon 07 Sep 2020 17:20:20 No.12095186 Report

Quoted By:

>>12095000
Calculate the probability for each possible outcome.

Anonymous

Anonymous Mon 07 Sep 2020 17:27:16 No.12095209 Report

Quoted By:

Why the fuck do I need to learn about titrations and shit when I'm just going to be developing stock exchange algorithms for the next 30 years?

Anonymous

View Same Google iqdb SauceNAO smiling British Pepe.png, 27KiB, 700x467

Anonymous Mon 07 Sep 2020 18:01:01 No.12095309 Report

Quoted By: >>12095381 >>12095982

>>12095000
You need to figure out how many rolls yield a given value $k$ and divide this by the total number of possible rolls ( $400$ in this case, which I hope is obvious).

When trying to calculate the number of rolls which output a given value, start small. Clearly, $(1,1)$ is the only roll which will yield $1$ . Then $(1,2)$ , $(2,1)$ and $(2,2)$ will output $2$ . If you imagine the problem visually (as a $20 × 20$ grid), a pattern is already forming. $k=1$ gave a $1 × 1$ square, then $k=2$ extended this to a $2 × 2$ square. As we increase $k$ we just keep adding L-shapes to extend this square. For any value of $k$ , this L-shape consists of $2k - 1$ outcomes (I'll let you verify this yourself). This gives us a probability distribution defined by $P(Y = k) = \frac{2k - 1}{400}$

Anonymous

Anonymous Mon 07 Sep 2020 18:26:33 No.12095381 Report

Quoted By:

>>12095309
Based statspepeposter.

Anonymous

Anonymous Mon 07 Sep 2020 18:32:11 No.12095395 Report

Quoted By:

>>12094021
energy is conserved in every reference frame
between two different reference frames, it is not. if you had an electron traveling at .999c, all light would appear like it was super blueshifted and there would be a huge apparent increase of energy in the universe (if what you're saying is the case). this would not be explained by the motion of the electron.

think of it this way too: if you have one laser, and you're running towards it, it is blueshifted so there is an apparent increase in energy. if you add a second laser and run towards it, they're both blueshifted the same amount, so there is DOUBLE the apparent increase of energy. so by your logic the mass would be transferring extra energy to the lasers, but the mass didn't move any faster/have any extra energy?
but you're not adding any extra energy into the system, you're just adding a second laser. you could repeat this process for 500 lasers and the apparent increase in energy in the moving frame would be even higher without there being any added energy.

now you can (hopefully) start to see that energy is frame-dependent. that's why I mentioned the invariant $E^2-(pc)^2$ , because this quantity IS conserved between frames.

Anonymous

Anonymous Mon 07 Sep 2020 18:33:44 No.12095405 Report

Quoted By: >>12095423

>>12093217
Why would the far side of the moon be thicker? Wouldn't earth's gravity, which locks the orbit so the same face is always facing earth, pull the near side more?

Anonymous

Anonymous Mon 07 Sep 2020 18:39:24 No.12095423 Report

Quoted By:

>>12095405
I just spent some time reading this
basically we don't know for sure. but one promising theory seems to be that when the moon was formed from the earth, and they were both very hot and a lot closer together, the heat from the 2500C earth led to the denser moon material migrating to the opposite, cooler side. and then when it cooled it locked these materials into place.

Anonymous

Anonymous Mon 07 Sep 2020 18:44:50 No.12095448 Report

Quoted By:

>>12093348
The radius of the observable universe is 46.5 billion ly.

Anonymous

View Same Google iqdb SauceNAO syjbcujv.jpg, 4KiB, 118x53

Anonymous Mon 07 Sep 2020 19:02:03 No.12095496 Report

Quoted By: >>12095504 >>12097704

first time using einstein notation and the problem is just to convert from einstein to vector notation. im confident i got the other problems correct but pic related im not sure of.
i think it would be just dot product of the three vectors
$\mathbf{V•B•A}$

Anonymous

Anonymous Mon 07 Sep 2020 19:05:45 No.12095504 Report

Quoted By: >>12095755 >>12097704

>>12095496
look for repeated indices.
V and B share an index, so it's like a dot product, which produces a scalar. this number just multiplies any following terms.
A and the unit vectors share an index, so it's like A is a vector

$(V \cdot B) \overrightarrow{A}$

Anonymous

View Same Google iqdb SauceNAO 1594099316870.png, 37KiB, 597x433

Anonymous Mon 07 Sep 2020 20:00:41 No.12095675 Report

Quoted By: >>12095703

Where the fuck did (7) come from?

Anonymous

Anonymous Mon 07 Sep 2020 20:11:59 No.12095703 Report

Quoted By: >>12095708 >>12095778

>>12095675
square 5, 6, plug them into P(Y), P(Z), and then set P(Z)=P(Y)
what you're probably looking for is this relation:
$\mathfrac{R} [e^{i \phi}] = \text{cos} \phi$

Anonymous

Anonymous Mon 07 Sep 2020 20:13:02 No.12095708 Report

Quoted By: >>12095739

>>12095703
should read
$\mathfrak{R} [e^{i \phi}] = \text{cos} \phi$

Anonymous

Anonymous Mon 07 Sep 2020 20:22:15 No.12095739 Report

Quoted By: >>12095772 >>12095825

>>12095708
How do I get the fancy R? I only know how to do $\mathcal{R}$ .

Anonymous

Anonymous Mon 07 Sep 2020 20:27:35 No.12095755 Report

Quoted By:

>>12095504
Ah okay that makes more sense. thanks for the help

Anonymous

Anonymous Mon 07 Sep 2020 20:33:00 No.12095772 Report

Quoted By:

>>12095739
\mathbb{R}

Anonymous

Anonymous Mon 07 Sep 2020 20:34:32 No.12095778 Report

Quoted By: >>12095825

>>12095703
but why is it [1 + cos phi]? If we're after the real part of A multiplied by its complex conjugate, isn't it just cos phi?

Anonymous

Anonymous Mon 07 Sep 2020 20:53:55 No.12095825 Report

Quoted By: >>12095862

>>12095739
mathfrak{R}
>>12095778
the 1 comes from the P(Y)+P(Z)=2P(Y)

Anonymous

Anonymous Mon 07 Sep 2020 21:08:22 No.12095862 Report

Quoted By:

>>12095825
>the 1 comes from the P(Y)+P(Z)=2P(Y)
Christ I'm retarded. Thanks for spelling it out for me.

Anonymous

View Same Google iqdb SauceNAO monk.jpg, 21KiB, 480x360

Anonymous Mon 07 Sep 2020 21:22:36 No.12095900 Report

Quoted By: >>12095947

What happens if i set an alarm every hour,for 24 hours(this would include sleep hours)daily for a year?
BONUS question:i do this while remaining upright and not lying down.

Anonymous

Anonymous Mon 07 Sep 2020 21:40:06 No.12095947 Report

Quoted By: >>12095995 >>12096186

>>12095900
you would eventually reach a point where you sleep through it because you need sleep

Anonymous

Anonymous Mon 07 Sep 2020 21:55:20 No.12095982 Report

Quoted By:

>>12095309
thanks my man

Anonymous

Anonymous Mon 07 Sep 2020 22:01:25 No.12095995 Report

Quoted By: >>12096186

>>12095947
i REJECT your reply

Anonymous

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Anonymous Mon 07 Sep 2020 22:17:53 No.12096042 Report

Quoted By:

Regular right angle prisms are coated on one side, light comes and does a 90 left on pic related.

Is there a specific name for pic on the right? Where 2 sides are coated so the image is split in half. This is different from a beam splitter.

Anonymous

View Same Google iqdb SauceNAO closed integral.png, 17KiB, 527x198

Anonymous Mon 07 Sep 2020 22:40:19 No.12096095 Report

Quoted By: >>12096108 >>12096114

can someone explain how I'm supposed to start this problem

Anonymous

Anonymous Mon 07 Sep 2020 22:42:48 No.12096104 Report

Quoted By:

my sister is a retarded whiney faggot, I want to bash her skull in with a hammer

Anonymous

Anonymous Mon 07 Sep 2020 22:45:12 No.12096108 Report

Quoted By: >>12096144

>>12096095
need to split the path up into 2, the line integral and the curve
figure out how to parameterize the curve, might be easier to go to polar coords

Anonymous

Anonymous Mon 07 Sep 2020 22:46:53 No.12096114 Report

Quoted By: >>12096144

>>12096095
You know how to apply Green's theorem, right? You need to make a parametrization for the path. In this instance, you'll need to break it up into two paths.

Anonymous

Anonymous Mon 07 Sep 2020 22:57:22 No.12096143 Report

Quoted By:

If I disconnect the grounding rod from my house panel or from the meters on an apartment building, is the voltage now floating or would ground to line voltage remain the same? I believe the transformer is grounded at the center tap as well, but if that’s the case why do we even need ground rods? Why can’t the transformer provide the ground?

Anonymous

View Same Google iqdb SauceNAO IMG_20200907_185551.jpg, 4MiB, 3746x3472

Anonymous Mon 07 Sep 2020 22:57:20 No.12096144 Report

Quoted By: >>12096149 >>12096189

>>12096114
I have no idea what greens theorem is
>>12096108
here's what Ive done so far
I dont know how to advance from here and Im pretty sure what Ive done so far for C2 is wrong anyway

Anonymous

Anonymous Mon 07 Sep 2020 22:58:53 No.12096149 Report

Quoted By:

>>12096144
actually nevermind it is right, I just forgot how to evaluate the integral properly because it's been almost 2 years since my last math course

Anonymous

Anonymous Mon 07 Sep 2020 23:12:14 No.12096186 Report

Quoted By:

>>12095947
>>12095995
Your body WILL just eventually take the rest it needs in the form of micro sleep. You can’t just will yourself through it. What can be done is to minimize how long these last in some way. I remember an experiment with rats, for example, where they were forced to balance on a plate and would fall in water if they lost consciousness. Don’t remember what the point of the experiment was, possibly to test the limits of their university’s ethics committee. Either way, they all died in like 2 weeks. Only being woken every hour would allow more than enough sleep, but it is fatal if you force constant wakefulness.

Anonymous

Anonymous Mon 07 Sep 2020 23:13:46 No.12096189 Report

Quoted By: >>12096198

>>12096144
did you forget to simplify sin^2+cos^2=1?

Anonymous

Anonymous Mon 07 Sep 2020 23:18:29 No.12096196 Report

Quoted By: >>12096291

Can I prove that a group is Abelian if $a^{-1}b^{-1}=b^{-1}a^{-1}$ ?

Anonymous

Anonymous Mon 07 Sep 2020 23:19:03 No.12096198 Report

Quoted By:

>>12096189
no I just turned that into 4 right away and multiplied the 4 with with the -2sin(t)dt, hence the -8sin(t)dt in the first term

Anonymous

Anonymous Mon 07 Sep 2020 23:46:33 No.12096291 Report

Quoted By:

>>12096196
yes

Anonymous

Anonymous Tue 08 Sep 2020 00:15:01 No.12096347 Report

Quoted By: >>12096351

kinematics
when integrating a given linear acceleration function from 0->t, is the added constant term v initial?
a = 2t
v = 2t^2/2 + v0

Anonymous

Anonymous Tue 08 Sep 2020 00:17:27 No.12096351 Report

Quoted By:

>>12096347
It must verify $v(t=0) = v_0$ so yeah.

Anonymous

Anonymous Tue 08 Sep 2020 00:58:20 No.12096428 Report

Quoted By: >>12100189

What is the functional difference between resistance and reactance?

Anonymous

Anonymous Tue 08 Sep 2020 01:17:34 No.12096463 Report

Quoted By: >>12096586

Could someone help me with this math question?
Find the equation of the tangent plane at the point P_0(4,3,0) on the surface -5cos(pi*x)+(x^2)*y+4e^(xz)+5yz=47?
My answer is 24x+21y+16z=159 but the system doesn't accept my answer for some reason.
Using the tangent plane equation, the partial derivatives of each component is:
F_x = 5pi*sin(pi*x) + 2xy + 4ze^(xz)
F_y = x^2 + 5
F_z = 4xe^(xz)
After plugging in x,y, and z values they become:
F_x = 24
F_y = 21
F_z = 16
Then putting them into the equation, it becomes:
24(x-4)+21(y-3)+16(z-0)=0
Which should become
24x + 21y + 16z - 96 - 63 = 0
Right? I don't know where I did an error.

Anonymous

View Same Google iqdb SauceNAO IMG_20200907_211353_1.jpg, 2MiB, 3300x4394

Anonymous Tue 08 Sep 2020 01:17:43 No.12096464 Report

Quoted By: >>12097551 >>12097560

I have to find the work done by the force acting counterclockwise once around a triangle with vertices (1,1), (3,1) and (3,2)
the force is F = (x + 2y)i + (6y - 2x)j
the answer is apparently -4 but I really don't see what I did wrong, pic related is my attempt

Anonymous

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Anonymous Tue 08 Sep 2020 01:20:38 No.12096470 Report

Quoted By: >>12096480 >>12100414 >>12104291

How toxic exactly can a non-food grade substance be? It's potassium chloride, which is a pretty safe chemical as far as I know. I made a mistake and bought non-food grade KCl even though I intended on consuming a little bit of it.

Anonymous

View Same Google iqdb SauceNAO file.png, 229KiB, 332x492

Anonymous Tue 08 Sep 2020 01:23:17 No.12096480 Report

Quoted By:

>>12096470
This is the stuff by the way. I realized I fucked up when there was no nutrient label, but everyone says it "should be" safe.

Anonymous

Anonymous Tue 08 Sep 2020 02:09:30 No.12096586 Report

Quoted By:

>>12096463
OK it took me a bit to figure out but I actually miscopied my question onto paper and missed an z which is why I kept on getting it wrong.

Anonymous

Anonymous Tue 08 Sep 2020 11:10:43 No.12097460 Report

Quoted By: >>12097513

Help me with this problem.
Do this problem for me.

I don't understand resonant frequencies. I was reading some shit on resonant frequencies on a spring-mass system and some engineer says frequencies either below (I think, maybe higher) the resonant frequency can't cause vibration at resonant frequencies,with some engineering handwave sounding explanation. When I google, I see two examples, the swing example and the string instrument example.

In the swing example you push at the resonant frequency, or some unit fraction of the frequency (1Hz, 1/2Hz, 1/3Hz) and that corresponds to 1 push every swing, 1 push every 2 swings and so on. On the other hand, 2Hz will fuck the swing up because you'll be stopping it when it comes back.

In the string example, there are harmonics of the fundamental resonant frequency which are multiples, and the fundamental resonant frequency is supposed to be the lowest possible resonant frequency.

So what causes things to vibrate at resonant frequency besides the frequency itself? Multiples of the resonant frequency or unit fractions of the resonant frequency? Not actually homework, it's just been many years since I've done physics and I've always been bad with waves and my googling doesn't seem to be up to par.

Anonymous

Anonymous Tue 08 Sep 2020 11:27:11 No.12097480 Report

Quoted By: >>12100189

Are there any alternatives to ozon layer? Can we deploy any other gases on high altitudes which can block UV radiation, if yes what gases have such properties.

Anonymous

Anonymous Tue 08 Sep 2020 11:49:33 No.12097513 Report

Quoted By: >>12097563

>>12097460
>So what causes things to vibrate at resonant frequency besides the frequency itself?
Resonance only makes sense when you have a driven oscillation. If that driving frequency is equal to the resonance frequency the amplitude increases dramatically.
The resonance frequency depends on the geometry of the object.
Is that what you were asking?

Anonymous

Anonymous Tue 08 Sep 2020 12:18:54 No.12097551 Report

Quoted By:

>>12096464
bump

Anonymous

Anonymous Tue 08 Sep 2020 12:28:42 No.12097560 Report

Quoted By: >>12099399

>>12096464
The parametrization looks weird
r1(t) = (4t-1,2t-1) for t in [0,1]
r1(0) = (-1,-1) ?

Anonymous

Anonymous Tue 08 Sep 2020 12:33:37 No.12097563 Report

Quoted By: >>12097588

>>12097513
I mean what other frequencies besides resonant frequencies cause oscillation associated with resonant frequencies. So driving frequencies not equal to "the" resonant frequency.
With a swing or a trampoline or something I know that a unit fraction of the frequency will cause oscillation if damping doesn't kill it before the next push.
I don't really understand what harmonics (multiples of unit frequency) have to do with unit frequency but I guess they do because they're mentioned in texts alongside resonant frequencies.

Anonymous

View Same Google iqdb SauceNAO Mplwp_resonance_zeta_envelope.svg.png, 172KiB, 1920x1280

Anonymous Tue 08 Sep 2020 12:47:54 No.12097588 Report

Quoted By: >>12098358

>>12097563
Are you confusing resonance of an oscillator with standing waves/resonance in cavities?
The former is the spring driven by a certain frequency. It's resonance curve looks like pic related.
The latter happens when you have waves trapped in a cavity and the waves reflected at the boundaries interfere constructively.

Anonymous

Anonymous Tue 08 Sep 2020 14:00:16 No.12097704 Report

Quoted By:

>>12095496 >>12095504

huh einstein notation involves upper indices for summations

Anonymous

Anonymous Tue 08 Sep 2020 14:24:45 No.12097774 Report

Quoted By: >>12097800 >>12097856

So suppose you have to determine weather if a series of one of zeros are determined by a coin toss or picked by a human:
A sequence like 101010101010101010101010101010101010101010101010 would very obviously have been produced by a human, but how would you prove so mathematically?
What tools other than the mean can you use to determine that the patterns like these are not random?

Anonymous

Anonymous Tue 08 Sep 2020 14:37:16 No.12097800 Report

Quoted By: >>12097807

>>12097774
One approach is to look at the Kolmogorov complexity of the series -- the size of the smallest program that would deterministically generate the series. That's a pain to compute in general, but easy in this case. The smaller the program required, the more likely it is that the series was generated deterministically.
Judging whether a sequence was produced by a true randomizer or by a human trying to emulate one without any tools is a separate question, and I think it involves questions of psychology.

Anonymous

Anonymous Tue 08 Sep 2020 14:40:14 No.12097807 Report

Quoted By:

>>12097800
I will add that, in the case of coin tosses, all sequences are equally likely under the hypothesis of iid Bernoulli randomness. The real question is which sequences are more likely under the hypothesis of human generation.

Anonymous

Anonymous Tue 08 Sep 2020 14:47:17 No.12097824 Report

Quoted By: >>12097848

Do photons have mass? If they do how they reach such speed and don't destroy everything on their path?

Anonymous

Anonymous Tue 08 Sep 2020 14:53:16 No.12097836 Report

Quoted By: >>12098319

Can you make a particle decay faster somehow?

I just read that the average time for neutron decay when it's alone is like 14 minutes. Is there something you can do to lone neutrons that could speed that up?

Anonymous

Anonymous Tue 08 Sep 2020 14:59:33 No.12097848 Report

Quoted By: >>12097860 >>12097865

>>12097824
They travel at the speed of light because they have zero mass. This also means they don't experience time at all.

Anonymous

Anonymous Tue 08 Sep 2020 15:01:37 No.12097856 Report

Quoted By:

>>12097774
In this case you can just look at the autocorrelation function and see that it's +-1 at every lag when for a random sequence you expect them to approach zero.

Kolmogorov complexity holy yikes.

Anonymous

Anonymous Tue 08 Sep 2020 15:03:48 No.12097860 Report

Quoted By: >>12098349

>>12097848
how does a timeless thing move?

Anonymous

Anonymous Tue 08 Sep 2020 15:04:44 No.12097865 Report

Quoted By: >>12098349

>>12097848
But how can something have zero mass?

Anonymous

Anonymous Tue 08 Sep 2020 17:41:27 No.12098319 Report

Quoted By:

>>12097836
if you wanted to speed it up you'd need to put it in some sort of energetically-unfavorable position. it's much much easier to put them in a position where they decay slower than normal (or not at all, as seen when neutrons are bound to atoms).

here's a discussion where it was done (for atoms) and notice how difficult it is: https://www.nature.com/articles/news040913-24
my intuition is telling me that in order to speed up free-neutron decay, you would want to have them extremely close to something that really really wants to capture the emitted electrons. I have no idea how this would be done.

Anonymous

Anonymous Tue 08 Sep 2020 17:48:36 No.12098349 Report

Quoted By:

>>12097860
"photons experiencing no time" is more of a consequence of the equations of special relativity.
since they have zero mass, they cannot be at rest. to a photon, everything is moving around them at the speed of light, meaning that lengths would be length contracted to 0 and time would be time dilated to infinity (meaning they "experience" getting from point A to point B instantaneously).

>>12097865
>But how can something have zero mass?
photons are the mediators of the electromagnetic force. this means that in order for things to interact electromagnetically, there must be an exchange of photons between the two objects.
now, since we know the electromagnetic force has infinite range (the strength drops off as 1/r^2), the photon must be massless because: if it was massive, the strength of the force would go to 0 much quicker, and the EM force would be extremely short range.

Anonymous

Anonymous Tue 08 Sep 2020 17:49:47 No.12098351 Report

Quoted By: >>12098353 >>12098360

>>12093089
How do I find the area under an entire function?
It's the integral from negative infinity to infinity right?
I don't remember how to do this from calc 1 and my calc 2 professor didn't explain it at all, yet it's on HW

Anonymous

Anonymous Tue 08 Sep 2020 17:50:35 No.12098353 Report

Quoted By: >>12098360 >>12098388

>>12098351
Can you post the question?

Anonymous

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Anonymous Tue 08 Sep 2020 17:51:17 No.12098358 Report

Quoted By: >>12098366

>>12097588
No I mean like pic related, frequencies other than the singular natural frequency that cause resonance.

Anonymous

Anonymous Tue 08 Sep 2020 17:51:50 No.12098360 Report

Quoted By: >>12098388

>>12098351
in general, the area under an entire function would be the integral over its entire domain. but >>12098353 is right as well it might be different.

Anonymous

Anonymous Tue 08 Sep 2020 17:54:14 No.12098366 Report

Quoted By: >>12098382

>>12098358
harmonics are geometry-dependent, so there
so no general answer without knowing your system. for a fundamental frequency f and integer n, in general they will be things like n*f, or (n/2)*f, or (n+1/2)*f, or 2n*f

Anonymous

Anonymous Tue 08 Sep 2020 17:58:39 No.12098382 Report

Quoted By: >>12098424

>>12098366
Wait, so is it related to the natural frequency and resonance or is that just the person writing articles not knowing what they're talking about. I've seen similar stuff come up for articles about suspension too, but obviously I have a hard time understanding what they're saying if they're not even using terminology right.

Anonymous

Anonymous Tue 08 Sep 2020 18:01:44 No.12098388 Report

Quoted By: >>12098406 >>12098413

>>12098353
>>12098360
Find the area between the x axis and the graph x^2+8x +7
I know how to get the antiderivative but I don't know what to do with it

Anonymous

Anonymous Tue 08 Sep 2020 18:08:39 No.12098406 Report

Quoted By: >>12098459

>>12098388
You're not asked to find the area under the whole function, that would be impossible considering it is infinite. What the question implictly means is that you need to find the area that's completely enclosed by the curve and the x axis. So you need to find the zeros of the polynomial (so the points where it intersects the x axis), and find the area that's between that parabola and the x axis in that particular region. That's just a regular definite integral over a bounded interval.

Anonymous

Anonymous Tue 08 Sep 2020 18:11:49 No.12098413 Report

Quoted By: >>12098459

>>12098388
Find the roots of $f(x)$ and then integrate the function over $r_1, r_2$ .

Anonymous

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Anonymous Tue 08 Sep 2020 18:12:14 No.12098416 Report

Quoted By: >>12098427

I get how you can the Variance of a Binomial distribution if you add the Variance of each part together, but why can you not just get it from the whole thing?
I.e. E(X^2)-E(X)^2=np-(np)^2 != npq

Anonymous

Anonymous Tue 08 Sep 2020 18:14:18 No.12098424 Report

Quoted By: >>12098449

>>12098382
so I haven't been following along with what you posted but just read your initial question.
your two systems are different in that you're conflating two different things: driving frequency and oscillation frequency.
for the swing, your driving frequency is fractions of your fundamental frequency. this works because you're delivering a "step" impulse to the swing. if you were to instead drive it with a sinusoidal frequency, anything except the frequency of the swing would cause its motion to get fucked up. think about it as if you're pushing the swing along its motion, forward when it's going forward and backwards when it's going back. even if you do half the frequency here, you're pushing forward when the swing has started going back, so it gets fucked up.
basically, in the driving frequency case what matters is the type of drive you're providing. for a step-impulse, you can do fractional multiples of the resonant. for a sinusoidal impulse, it has to match the resonance frequency.

for the string, your frequencies are the allowed modes of oscillation of the system. your fundamental is the lowest mode, corresponding to one-half wavelength across the whole string (think of holding a slinky fixed in both hands and plucking the middle. unless you pluck it really fast and far it'll just have one big peak of oscillation). you also have a 1 wavelength mode, which corresponds to two oscillation peaks. clearly in this system there's no way to have a lower frequency than the fundamental frequency, because that would correspond to "less than one oscillation peak."

Anonymous

Anonymous Tue 08 Sep 2020 18:15:21 No.12098427 Report

Quoted By: >>12098460

>>12098416
you can? unless I'm misunderstanding your question
>add the variance of each part together
each part of what?

Anonymous

Anonymous Tue 08 Sep 2020 18:20:30 No.12098449 Report

Quoted By: >>12098521 >>12098592

>>12098424
I guess what I really want to know about is a basic beam or spring (like a spring-mass system) subjected to arbitrary or random vibrations. Like what causes resonance in an dampened spring suspension under certain road conditions, or what causes a machine to vibrate more at certain frequencies, and the relation to the natural frequency if any. I'm not even sure what to try reading so explanations of harmonic(?) phenomenon don't completely go over my head.

Anonymous

Anonymous Tue 08 Sep 2020 18:22:11 No.12098459 Report

Quoted By:

>>12098406
>>12098413
thanks lads, I am dumb

Anonymous

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Anonymous Tue 08 Sep 2020 18:22:25 No.12098460 Report

Quoted By: >>12098490 >>12098505

>>12098427
>you can?
But wouldn't it result in np(1-np) as posted above? There's got to be an error in my thinking there, but I cannot find it

>each part of what?
Like in the picture, splitting the X in each of its n attempts and then adding their variance together

Anonymous

Anonymous Tue 08 Sep 2020 18:31:20 No.12098490 Report

Quoted By: >>12098505

>>12098460
you should be able to calculate the variance of a binomial distribution from the binomial pdf. I've done it before in a stats class, so my best guess is you're calculating the expectation value of x^2 incorrectly

Anonymous

Anonymous Tue 08 Sep 2020 18:34:43 No.12098505 Report

Quoted By: >>12098533

>>12098460
>error in my thinking
Or wait, I think I got it?:
Only for the singular X case the function would be E=1*p. The one with all of them combined must use a different one, which makes E(X^2) have a different value
>>12098490
I think that's it, thanks! No clue how to get it though, will have to think this one through more

Anonymous

Anonymous Tue 08 Sep 2020 18:38:50 No.12098521 Report

Quoted By:

>>12098449
okay, you seem to first be asking about step-driven systems, like the swing. in that case, your systems are exactly analogous, where the cars can be treated as swing pushes.
for machine vibrations, I don't know as much, but here's my guess: your machine has a "fundamental frequency" at which it can vibrate. so it is more like the string, and certain frequencies of operation correspond with higher harmonics of vibration in the machine.

it's hard because the cause of the things you're asking depends on the system and is different even in the two examples you gave. for an analogy for the machine example, I would look up "pipe harmonics" but instead of reading into it as air waves in a pipe, think about them as vibration waves inside the machine.
for the step-driven case, I think the swing example is sufficient. different systems will have different periods of oscillation (much like the oscillation of a swing depending on its length), but the mechanism is the same - if you hit the oscillator at the same point in its motion with an instantaneous kick, you will add to its oscillation.

Anonymous

Anonymous Tue 08 Sep 2020 18:42:20 No.12098533 Report

Quoted By: >>12098644

>>12098505
do you know the binomial probability distribution function B(n,p)?
the expectation value of x^2 is: $\sum_{n=0}^\infty \sum_{x=0}^n x^2 B(n,p,x)$
my assumption is, for your level, it's probably easier to calculate the variance of a singular X and just add them (hint: it's probably p(1-p) for one X)

Anonymous

Anonymous Tue 08 Sep 2020 18:56:45 No.12098592 Report

Quoted By:

>>12098449
Warning I'm talking a bit out of my ass here, but this is what I imagine is going on. I didn't do the calculations and may have misunderstood some things myself.
>I guess what I really want to know about is a basic beam or spring (like a spring-mass system) subjected to arbitrary or random vibrations
Use fourier series expansion for the driving force. If you really want to have a quantitative answer.
> Like what causes resonance in an dampened spring suspension under certain road conditions, or what causes a machine to vibrate more at certain frequencies
The geometry of your car/machine determines the frequency. The wave travels through it and is reflected on the other side. The reflected wave then interferes with the incoming wave. If the frequency is just right, it will interfere constructively.
If you have a random incoming wave composed of different frequencies you can imagine a wave for every frequency that gets reflected and interferes with itself. Afterwards you add the different waves together.
For example if you have a wave with two frequencies, the resonance frequency and 1.2 times resonance frequency. The first wave interferes constructively, the other doesn't (The reflected wave has a different phase depending on the material, so it's a bit complicated).
>and the relation to the natural frequency if any
Waves with the natural frequency are the ones that interfere constructively. So do waves with multiples of the frequency.

Anonymous

Anonymous Tue 08 Sep 2020 19:13:18 No.12098644 Report

Quoted By:

>>12098533
I finally got it, thank you very much!
It's $\sum_{k=1}^{n} k{\binom {n}{k}}p^{k}(1-p)^{n-k}$ for E(X) and $\sum_{k=1}^{n} k^2{\binom {n}{k}}p^{k}(1-p)^{n-k}$ for E(X^2)
Though painful to calculate it out if p isn't 0.5, so I guess best to stick with doing them one by one

Anonymous

Anonymous Tue 08 Sep 2020 19:23:16 No.12098676 Report

Quoted By: >>12098682 >>12098869

How can a narcissistic person sleep? seriosly how can he allow the awesomeness of his coniuosness no go away? I suffer from that condition and I can't sleep, what to do if u were me?

Anonymous

Anonymous Tue 08 Sep 2020 19:25:26 No.12098682 Report

Quoted By:

>>12098676
*consciousness

Anonymous

Anonymous Tue 08 Sep 2020 20:21:36 No.12098869 Report

Quoted By:

>>12098676
benadryl/melatonin

Anonymous

Anonymous Tue 08 Sep 2020 20:58:54 No.12098992 Report

Quoted By: >>12100186 >>12101706

>>12093089
Quick question about notation correctness.

Suppose you have a function $f$ defined over whatever metric space $X$ of your choosing.

Suppose also you have a transform $T$ that takes your function $f$ and produces a function $F = T\{ f \}$ that's defined over another metric space $Y$ (correct me if I'm wrong , this is how I understand transforms to work)

Then, what's the correct notation to use for how the function $F$ is defined? Is it:
$F(y) = T \{ f(x) \} (y)$
Where $x \in X$ and $y \in Y$ ? Or:
$F(y) = T \{ f \} (y)$ ?
I ask because I feel like $T \{ f \}$ should produce the set $F$ not the element $F(y)$ , but I usually see it written like $F(y) = T \{ f \}$ and that just seems incongruent.

Anonymous

Anonymous Tue 08 Sep 2020 22:48:21 No.12099399 Report

Quoted By:

>>12097560
I was using (t-1) rather than (1-t) for my parametrization. I cant believe I was just using the wrong equation this whole time lol.
Thank you.

Anonymous

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Anonymous Tue 08 Sep 2020 23:30:47 No.12099543 Report

Quoted By: >>12099553

Where does the 1 in 1+e denominator come from?

Anonymous

Anonymous Tue 08 Sep 2020 23:34:58 No.12099553 Report

Quoted By: >>12099558

>>12099543
algebra
$V_{ \text{voids} } = e V_{ \text{grains} } \rightarrow V_{ \text{total} }=V_{ \text{grains} }(1+e) \rightarrow V_{ \text{grains} }= \frac{V_{ \text{total}}}{1+e}$

Anonymous

Anonymous Tue 08 Sep 2020 23:37:19 No.12099558 Report

Quoted By:

>>12099553
Thank you I'm a dummy

Anonymous

Anonymous Wed 09 Sep 2020 01:08:14 No.12099856 Report

Quoted By: >>12099861

I understand why diodes don't work with AC current, but wouldn't they work when the current is in its positive phase? Or, I guess an easier way to put it would be when the current is in the direction of the forward-biased diode?

Anonymous

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Anonymous Wed 09 Sep 2020 01:09:06 No.12099859 Report

Quoted By: >>12099899 >>12099906

Is what I wrote on the screen correct? As in I_3 is equal to 0.4*I_1? My professor completely skipped this so everything is up to me to read off the textbook which is pretty confusing admittedly.

Anonymous

Anonymous Wed 09 Sep 2020 01:09:22 No.12099861 Report

Quoted By:

>>12099856
during half of a cycle, the diode would conduct and during the other half it would insulate, depending on the direction of current

Anonymous

Anonymous Wed 09 Sep 2020 01:21:19 No.12099899 Report

Quoted By:

>>12099859
$I_1 + I_3 = I_2$

Anonymous

Anonymous Wed 09 Sep 2020 01:22:59 No.12099906 Report

Quoted By: >>12099943

>>12099859
$I_1 + I_3 = I_2$ so yes you are correct.

Anonymous

Anonymous Wed 09 Sep 2020 01:25:23 No.12099911 Report

Quoted By:

I am writing some code to run a couple simulations. I was doing version control manually (writing what was added/removed of my program on a log) and keeping a copy of every single version of my program.

Then I learned that I can use git/github to do the version control for me. Can I just put my project on github and not worry about backups? Is there any advise to someone starting to do computational physics?

Anonymous

Anonymous Wed 09 Sep 2020 01:26:13 No.12099913 Report

Quoted By: >>12099917

>tfw housefly won't fuck off and I have no Raid
How do I get rid of them?

Anonymous

Anonymous Wed 09 Sep 2020 01:27:31 No.12099917 Report

Quoted By:

>>12099913
pour some beer into a bunch of cups, cover the cup with plastic/metal with holes punched in it for them to fit through

Anonymous

Anonymous Wed 09 Sep 2020 01:34:59 No.12099943 Report

Quoted By: >>12099985

>>12099906
OOOoooh I didn't know that, so if two of these currents are both going in the same direction into another current (I2), they 'merge'?

Anonymous

Anonymous Wed 09 Sep 2020 01:49:50 No.12099983 Report

Quoted By: >>12100028

>>12093089
I feel like I'm going crazy here. wasn't the origin of the "Powerhouse of the Cell" meme a joke from a biology test that blatantly gives away the answer to it's question with very specific wording?
I can't find a trace of it anywhere, and everyone just seems to think the meme sprung up out of nowhere.

Anonymous

Anonymous Wed 09 Sep 2020 01:50:20 No.12099985 Report

Quoted By: >>12099997

>>12099943
yes, you should look up the kirchoff rules

Anonymous

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Anonymous Wed 09 Sep 2020 01:55:04 No.12099994 Report

Quoted By: >>12100189

The homework is asking me for the power absorbed at the current source (the left side one) but how do I figure that out? There's no voltage description on it. Prior to this question, we had to calculate for I which was -7A.

Anonymous

Anonymous Wed 09 Sep 2020 01:56:29 No.12099997 Report

Quoted By:

>>12099985
I will, thank you. This professor didn't go over anything and just told us to read the textbook, and the textbook didn't go over this either (at least right now) which is very frustrating.

Anonymous

Anonymous Wed 09 Sep 2020 02:03:25 No.12100028 Report

Quoted By:

>>12099983
>wasn't the origin of the "Powerhouse of the Cell" meme a joke from a biology test that blatantly gives away the answer to it's question with very specific wording?
No.

Anonymous

Anonymous Wed 09 Sep 2020 02:59:41 No.12100154 Report

Quoted By: >>12100162 >>12100172 >>12100189

MATLAB brainlet here.
How do I compute the product of two elements from a column vector?

Anonymous

Anonymous Wed 09 Sep 2020 03:03:42 No.12100162 Report

Quoted By: >>12100179

>>12100154
I dont know matlab but wouldnt it ve something like a(n1)*b(n2) where n1 and n2 are the positions of the desired elements in the vector?

Anonymous

Anonymous Wed 09 Sep 2020 03:11:26 No.12100172 Report

Quoted By: >>12100176

>>12100154
your question is too vague

Anonymous

Anonymous Wed 09 Sep 2020 03:14:03 No.12100176 Report

Quoted By: >>12100177

>>12100172
I have a column vector, $v_2$ , with 100 elements and I want to assign a new variable to the product of the 45th and 87th elements from $v_2$ . So, basically I want $x=v_{45,1} * v_{87,1}$ .

Anonymous

Anonymous Wed 09 Sep 2020 03:17:38 No.12100177 Report

Quoted By: >>12100179

>>12100176
does x=v2(45)*v2(87) not work?

Anonymous

Anonymous Wed 09 Sep 2020 03:19:12 No.12100179 Report

Quoted By:

>>12100162
>>12100177
Wow, I didn't think it was that simple. I feel like an idiot now. Thanks.

Anonymous

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Anonymous Wed 09 Sep 2020 03:23:16 No.12100184 Report

Quoted By:

How is this not /sci/'s sticky yet?

Anonymous

Anonymous Wed 09 Sep 2020 03:24:59 No.12100186 Report

Quoted By: >>12101706

>>12098992
Someone pls

Anonymous

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Anonymous Wed 09 Sep 2020 03:27:00 No.12100189 Report

Quoted By:

>>12099994
The potential over the current source is 15 V, just like with the stuff in parallel
>>12100154
if A is a column or row vector, A(i) is the ith component. A(i)*B(j) for example. To multiply equal sized vectors componentwise, it's A.*B
>>12097480
We probably can, but it sounds a lot easier to just to keep O3 as it is.
>>12096428
Resistance is the real part of impedance and reactance is the imaginary portion. Practically, resistance is something that disperses energy as heat and reactance measures energy lost to changing EM fields. Electric fields changing in a circuit contribute to negative reactance and changing magnetic contribute to positive.

Anonymous

Anonymous Wed 09 Sep 2020 04:48:24 No.12100347 Report

Quoted By: >>12100395

How does ambient temperature affect rate of cooling on a constant heat source?
Obviously colder wind will cool the heat source better, but why, and what are the equations for it?

Anonymous

Anonymous Wed 09 Sep 2020 05:00:20 No.12100395 Report

Quoted By:

>>12100347
ODE heat equation

Anonymous

Anonymous Wed 09 Sep 2020 05:05:45 No.12100414 Report

Quoted By:

>>12096470
>a little bit of it
can mean literally anything. A tsp? tablespoon? a cup? one time, or every day for breakfast?
>How toxic
supertoxins are rare, but whatever they're using may cause things like indigestion, nausea, or be potentially carcinogenic

Anonymous

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Anonymous Wed 09 Sep 2020 05:27:02 No.12100470 Report

Quoted By: >>12100483 >>12100607 >>12100653 >>12100863 >>12100987

What was wrong with my approach?

Anonymous

Anonymous Wed 09 Sep 2020 05:32:37 No.12100483 Report

Quoted By: >>12100487

>>12100470
literally we have no idea what the question is

Anonymous

Anonymous Wed 09 Sep 2020 05:35:32 No.12100487 Report

Quoted By: >>12100533 >>12100987

>>12100483
Find final velocity and angle below positive x of a ball launched at 100m/sec at 30 degrees. final position is 10m below starting

Anonymous

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Anonymous Wed 09 Sep 2020 05:44:57 No.12100501 Report

Quoted By: >>12100511 >>12100512

I'm taking a course on EM based on jackson and never took a class/read about about differential equations (lmao, don't ask, I learned what I had to as I went along). I'm good at pure math at a graduate level. Tell me a good resource to learn all the different cookie cutter techniques for solving differential equations. No 800 page shitty monstrosities with thousands of pointless problems for brainlets. I don't have time for any of that nonsense, desu.

Anonymous

Anonymous Wed 09 Sep 2020 05:48:25 No.12100511 Report

Quoted By: >>12100525

>>12100501
Tenenbaum/Pollard
It's Dover, so it's exceedingly cheap too.

Anonymous

Anonymous Wed 09 Sep 2020 05:48:36 No.12100512 Report

Quoted By:

>>12100501
>never took a class/read about about differential equations (lmao, don't ask, I learned what I had to as I went along)
by this I mean the standard undergrad cookie cutter class, I have some familiarity with the material from a need-to-know basis in some physics courses

>I don't have time for any of that nonsense, desu.
I also don't want to learn the richer theory, even though I've taken a grad class in topology.

Anonymous

Anonymous Wed 09 Sep 2020 05:51:38 No.12100524 Report

Quoted By:

does sfw furry count as furry in the report box, or does that get absorbing into mlp

Anonymous

Anonymous Wed 09 Sep 2020 05:51:39 No.12100525 Report

Quoted By: >>12100535

>>12100511
I have a copy sitting on my shelf. That book is a monstrosity. I need to get up to speed on the material extremely quickly.

Anonymous

Anonymous Wed 09 Sep 2020 05:55:45 No.12100533 Report

Quoted By: >>12100555

>>12100487
first of all it's incredibly hard to follow your work. you should organize your steps better
I'll look at it

Anonymous

Anonymous Wed 09 Sep 2020 05:55:46 No.12100535 Report

Quoted By: >>12100551

>>12100525
It is, but as far as applied/computational ODEs are concerned, it's definitely the best.

Anonymous

Anonymous Wed 09 Sep 2020 06:02:09 No.12100551 Report

Quoted By: >>12100597

>>12100535
What about Coddington intro to ODE?

Anonymous

Anonymous Wed 09 Sep 2020 06:03:56 No.12100555 Report

Quoted By: >>12100681

>>12100533
I solved a quadratic for t at y= -10
dy = v0t + at^2
-10 = v0sint + 1/2 gt

And then used vf = v0 + at for the final y
And then solved the Pythag for the resultant

Anonymous

Anonymous Wed 09 Sep 2020 06:16:52 No.12100597 Report

Quoted By:

>>12100551
Coddington is theory based. It's an excellent text (and what I would recommend if someone wants to get into the underlying analysis of ODEs), but not comparable to Tenenbaum/Pollard

Anonymous

Anonymous Wed 09 Sep 2020 06:19:24 No.12100607 Report

Quoted By: >>12100631 >>12100632

>>12100470
isnt this year 11 physics?

Anonymous

Anonymous Wed 09 Sep 2020 06:27:08 No.12100631 Report

Quoted By:

>>12100607
It would seem so.

Anonymous

Anonymous Wed 09 Sep 2020 06:27:12 No.12100632 Report

Quoted By:

>>12100607
Thats not the point
the point is I got it right and was given 3/10

Anonymous

Anonymous Wed 09 Sep 2020 06:35:07 No.12100653 Report

Quoted By:

>>12100470

Why do you use a quadratic to find the final time? Just solve $50 - 9.8t = -10$

Anonymous

Anonymous Wed 09 Sep 2020 06:46:18 No.12100681 Report

Quoted By: >>12100777

>>12100555
okay I'm back (nobody else since my last reply was me)
think about it for a second: how could you have the same incident angle and the same vertical velocity when you're 10m below the horizon? your vertical velocity can't be the same as when you started since it should equal your starting velocity at y=0
assuming you calculated the time correctly (which seems correct) your final vertical velocity would be -51.92, not -50

not sure about "wrong approach" maybe it's possible they just couldn't fucking follow your work

Anonymous

Anonymous Wed 09 Sep 2020 07:21:24 No.12100777 Report

Quoted By:

>>12100681
Jfc

Anonymous

Anonymous Wed 09 Sep 2020 08:02:58 No.12100863 Report

Quoted By:

>>12100470
If im not wrong
final v = 69.31m/s
final theta = -30.94

Anonymous

Anonymous Wed 09 Sep 2020 09:00:04 No.12100970 Report

Quoted By: >>12101006

Why can all complex numbers be written as $e^i\theta$ ?

If you have a complex number like $5 + 14i$ how would you translate?

Anonymous

Anonymous Wed 09 Sep 2020 09:09:04 No.12100987 Report

Quoted By: >>12101003 >>12101011 >>12102229

>>12100470
>>12100487
>What was wrong with my approach?
You calculate t then don't use it. By "final angle", are you referring to the position relative to the start point or the direction of the final velocity?

When the ball is 10m below the starting height, the position is [900.69,-10] (distance = 900.75 m, angle = -0.64°) and the velocity is [86.60,-51.92] (magnitude = 100.975 m/s, angle = -30.95°).

Clearly the final velocity isn't just the starting velocity reflected in the x axis, as that occurs when the height is zero.

Anonymous

Anonymous Wed 09 Sep 2020 09:13:45 No.12101003 Report

Quoted By: >>12101012

>>12100987
>velocity is [86.60,-51.92] (magnitude = 100.975 m/s
i think you got this wrong

Anonymous

Anonymous Wed 09 Sep 2020 09:14:44 No.12101006 Report

Quoted By:

>>12100970
>Why can all complex numbers be written as e^i??
They can't; only complex numbers with unit magnitude can be written that way. But all complex numbers can be written as r*e^i? where r is a non-negative real. That's just polar coordinates.
r*e^i? = r*cos?+i*r*sin? = a+bi where a=r*cos?, b=r*sin?
=> a^2+b^2=r^2 => r=?(a^2+b^2)
=> b/a = tan? => ?=atan2(b,a) (atan2(b,a)=atan(b/a), except it gets the quadrant correct for a<0).

Anonymous

Anonymous Wed 09 Sep 2020 09:19:43 No.12101011 Report

Quoted By: >>12101018

>>12100987
He used it to calculate v_y
And sqrt(50^2+86^2) is approx. 100

Anonymous

Anonymous Wed 09 Sep 2020 09:19:54 No.12101012 Report

Quoted By: >>12101023

>>12101003
Why? y=0 occurs at t=10.2, y=-10 at t=10.4, so the state at y=-10 is going to be very close to the initial state (v=[86.6,50], |v|=100) except with the vertical component of the velocity negated. Note that I'm using g=9.8 m/s^2 which is what's in the original photo.

Anonymous

Anonymous Wed 09 Sep 2020 09:24:15 No.12101018 Report

Quoted By: >>12101029

>>12101011
> He used it to calculate v_y
Where? Are we looking at the same photo? I see t=10.4 calculated then that value used nowhere.

The thing is, the difference between y=0 => t=10.2 and y=-10 => t=10.4 is small enough that one decimal place isn't really going to cut it. The calculations on the paper look very much like the symmetrical case (y=0) is being assumed.

Anonymous

Anonymous Wed 09 Sep 2020 09:26:20 No.12101023 Report

Quoted By: >>12101029

>>12101012
isnt the final velocity given by sqrt 86.6^2 + -51.92^2?

Anonymous

Anonymous Wed 09 Sep 2020 09:31:28 No.12101029 Report

Quoted By: >>12101043

>>12101018
Well, I just assumed he used it in
>50+gt
>50-100=-50m/s=v_y
But I may be too lenient when it comes to rounding errors.
I mean who gives a shit about accuracy in homework.
>>12101023
gotta square the -

Anonymous

Anonymous Wed 09 Sep 2020 09:38:08 No.12101043 Report

Quoted By:

>>12101029
lmao i hate my calculator, but yeah i should have checked my own answer
-2^2 = -4 apparently

Anonymous

Anonymous Wed 09 Sep 2020 13:09:28 No.12101408 Report

Quoted By:

>>12101390
this is a good idea for a general.
>prove me wrong

Anonymous

Anonymous Wed 09 Sep 2020 13:12:56 No.12101415 Report

Quoted By: >>12101438

I still don't understand how fourth dimension works, how would things look like on four dimensions? And speaking of fourth dimension, how is Kleine Bottle supposed to works/looks in 4D since they said the 3D representation isn't exactly right because of the intersection.

Anonymous

Anonymous Wed 09 Sep 2020 13:18:36 No.12101424 Report

Quoted By: >>12101554 >>12101558

In dire need of help here...

$ Let M = \begin{pmatrix} \cos \theta & \sin \theta \\ \sin \theta & - \cos \theta \end{pmatrix}$
and

$ |L\rangle = \begin{pmatrix} \cos x \\ \sin x \end{pmatrix}$

$ M |L\rangle = \begin{pmatrix} \cos \theta \cos x + \sin \theta \sin x \\ \sin \theta \cos x - \cos \theta \sin x \end{pmatrix}$

If $|L\rangle$ is an Eigenvector of M, then

$\cos \theta \cos x + \sin \theta \sin x = L \cos x$

$\sin \theta \cos x - \cos \theta \sin x = L \sin x$

Solve for x in terms of $\theta$ .

Any hints?

Anonymous

Anonymous Wed 09 Sep 2020 13:27:08 No.12101438 Report

Quoted By: >>12101451

>>12101415
it looks like the tessaract. looking at 3d is a two dimensional shape which changes profile as you rotate it. 4d is then a change in 3d shape as you "rotate" it. imagine it as being able to jump over a hurdle in 3d where as in 2d that would not be possible. the 4th dimension is another direction to move over that hurdle.

Anonymous

Anonymous Wed 09 Sep 2020 13:34:12 No.12101451 Report

Quoted By: >>12101459

>>12101438
>imagine it as being able to jump over a hurdle in 3d where as in 2d that would not be possible
Why is it impossible in 2d? I think i misunderstood something here because i imagined it like some 2d game where you move forward and jump over the hurdle

Anonymous

Anonymous Wed 09 Sep 2020 13:39:06 No.12101459 Report

Quoted By:

>>12101451
even if the game is in 2d the fact the guy can jump the hurdle implies there is a 3rd dimension.

4 dimensions would be like a guy being able to escape from a seeming 3d solid container by "rotating" it until there was an opening for him to escape.

Anonymous

Anonymous Wed 09 Sep 2020 14:23:10 No.12101554 Report

Quoted By: >>12101703 >>12101859

>>12101424
$ \sin \theta \sin x = (L -\cos \theta) \cos x\\ \sin \theta \cos x = (L +\cos \theta) \sin x\\ $
etc

Anonymous

Anonymous Wed 09 Sep 2020 14:23:53 No.12101558 Report

Quoted By: >>12101703

>>12101424
if you divide i) by cos(x) and ii) by sin(x) you get L = L and then you rearrange it to get all the x on one side and all the theta on the other, which gives you cot(x) - tan(x) = 2 tan(theta).
plugging that into wolfram gave me x = arc-cot(tan(theta) - sqrt(tan^2(theta) + 1)). thats the best i can do but it makes sense to me. simple solution by equation.

Anonymous

Anonymous Wed 09 Sep 2020 14:40:03 No.12101593 Report

Quoted By:

whats the best branch of stem/applied math for getting rich quick?

Anonymous

Anonymous Wed 09 Sep 2020 15:22:47 No.12101703 Report

Quoted By: >>12101726 >>12101857

>>12101554
Bro you're a genius.

>>12101558
Thanks but there's a simpler method. The answer is $x = \frac{\theta}{2}$

Anonymous

Anonymous Wed 09 Sep 2020 15:23:25 No.12101706 Report

Quoted By:

>>12100186
>>12098992
your T looks like a functor or natural transformation in category theory. you really should look up this.

f: X->X
T:X^X->Y^Y
T(f):Y->Y

you can write T_f if you want to, but T(f)(y) is fine

Anonymous

Anonymous Wed 09 Sep 2020 15:31:41 No.12101726 Report

Quoted By: >>12101859

>>12101703
ok thats interesting. i wonder if i went wrong somewhere but i did check the answer on wolfram again and it was right. care to go step by step? im guessing its something relating to half angle identities?

Anonymous

Anonymous Wed 09 Sep 2020 16:12:58 No.12101857 Report

Quoted By:

>>12101703
seriously can you show me how you got that? i got way too invested in your question.

Anonymous

Anonymous Wed 09 Sep 2020 16:14:17 No.12101859 Report

Quoted By: >>12101896 >>12101897

>>12101726
Subtract both equations in >>12101554
to get rid of the L, then
$ \sin\theta\sin^2 x -sin\theta\cos^2x = (L-\cos\theta)\cos x \sin x- (L+\cos\theta)\cos x \sin x\\ -\cos(2x)\sin \theta = -\cos\theta \cos x \sin x - \cos\theta\cos x\sin x = -2 \cos\theta\cos x\sin x \\ \tan \theta = 2\cos x\sin x/cos(2x)=\sin(2x)/\cos(2x)= \tan(2x)\\ x=\theta/2 $
Seems a bit ugly, there's probably a better way

Anonymous

Anonymous Wed 09 Sep 2020 16:26:42 No.12101896 Report

Quoted By: >>12101899

>>12101859
yeah thats great work. nice one anon. i need to work on re learing my identities. too long out the field.

Anonymous

Anonymous Wed 09 Sep 2020 16:27:58 No.12101897 Report

Quoted By:

>>12101859
but you forgot to mention to multiply i) by sin(x) and ii) by cos(x) in order to properly be able to eliminate L. once i did that the double angle formulas came out and nice. again, good work.

Anonymous

Anonymous Wed 09 Sep 2020 16:29:06 No.12101899 Report

Quoted By: >>12101928

>>12101896
That's what the wiki article is for anon
Nobody really remembers that shit

Anonymous

Anonymous Wed 09 Sep 2020 16:45:58 No.12101928 Report

Quoted By:

>>12101899
yeah true. the fact i didnt open it up immediately shows how rusty i am.

Anonymous

Anonymous Wed 09 Sep 2020 17:01:56 No.12101982 Report

Quoted By: >>12101993 >>12102002

I'm wondering how you would go about this question.

A function $f(x)$ defined for $x > a$ where $a$ is a constant, and a quartic function $g(x)$ whose leading coefficient is $-1$ satisfies the following three properties:

1. $\forall x \in \mathbb{R}$ such that $x > a, \ (a-x)f(x) = g(x)$

2. For $\alpha, \beta \in \mathbb{R}$ with $\alpha \neq \beta, f(x)$ obtains the same local maximum value $M$ at $x = \alpha$ and $x = \beta. (M > 0)$

3. $f(x)$ has more local extrema than $g(x)$ does.

$\beta - \alpha = 6 \sqrt{3}$ . Find the minimum of $M$ .

Anonymous

Anonymous Wed 09 Sep 2020 17:08:45 No.12101993 Report

Quoted By: >>12102023

>>12101982
Who the fuck invents these kind of questions?
Jesus

Anonymous

Anonymous Wed 09 Sep 2020 17:11:36 No.12102002 Report

Quoted By: >>12102023

>>12101982
are we assuming alpha and beta are more than a?

Anonymous

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Anonymous Wed 09 Sep 2020 17:13:02 No.12102008 Report

Quoted By:

Can /sci/ identify the font used in these equations? It's not your run-of-the-mill Latin Modern. It looks so smooth :3

Anonymous

Anonymous Wed 09 Sep 2020 17:18:15 No.12102023 Report

Quoted By:

>>12101993
It's from the Korean CSAT.

>>12102002
It doesn't specify one way or the other.

Anonymous

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Anonymous Wed 09 Sep 2020 17:20:02 No.12102030 Report

Quoted By: >>12102036 >>12102141

*kisses u*

Anonymous

Anonymous Wed 09 Sep 2020 17:21:21 No.12102036 Report

Quoted By: >>12102293

>>12102030
Not math or science related.

Anonymous

Anonymous Wed 09 Sep 2020 17:51:55 No.12102141 Report

Quoted By:

>>12102030
are you cute?

Anonymous

Anonymous Wed 09 Sep 2020 18:25:30 No.12102229 Report

Quoted By: >>12102244

>>12100987
the issue was I multiplied the t value, 10.4, by g, 10, but i performed 10x10 = 100 instead of 10.4x10 = 104
I suppose he docked me hard for lacking insight as to the impossibility of it vf=v0 but I was under time pressure
And So he gouges a gives me an F For an arithmetic error on the 2nd to last step
I’m pretty fuckin pissed, this guy needs to retire

Anonymous

Anonymous Wed 09 Sep 2020 18:29:36 No.12102244 Report

Quoted By: >>12102261

>>12102229
For fucked up notation, missing units and making me work to understand what you did I'd have given you 5/10 as well.

Anonymous

Anonymous Wed 09 Sep 2020 18:36:04 No.12102261 Report

Quoted By: >>12102307 >>12102356 >>12102367

>>12102244
Well he gave me a 3, and what your autistic ass wants me to carry units through the algebra? Are you retarded?

Anonymous

Anonymous Wed 09 Sep 2020 18:40:38 No.12102280 Report

Quoted By:

God I wish I had a cute boy to pin down and dominate so god damn much.

Anyways.

At what percentage do alcoholic beverages dehydrate you more than they hydrate?
Asking so I can optimize my sauna bathing.

Anonymous

Anonymous Wed 09 Sep 2020 18:44:07 No.12102293 Report

Quoted By:

>>12102036
t. undergrad

Anonymous

Anonymous Wed 09 Sep 2020 18:49:00 No.12102307 Report

Quoted By: >>12102366

>>12102261
>Are you retarded?
I'm not the one who failed his homework
And yes, carry the fucking units through the algebra.
You will notice faster when you fuck something up and you won't waste your and your tutor's time with useless calculations because you don't want to write the units again.
Keeps everything short, clean and you just insert the numbers when necessary.

Anonymous

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Anonymous Wed 09 Sep 2020 19:09:14 No.12102356 Report

Quoted By:

>>12102261
>Are you retarded?

Anonymous

Anonymous Wed 09 Sep 2020 19:12:40 No.12102362 Report

Quoted By:

Is there a material that dirt and bacteria cannot cling to? I have an idea for a fork for outdoor use that never needs to be cleaned and is always sanitary to eat with.

Anonymous

Anonymous Wed 09 Sep 2020 19:14:27 No.12102366 Report

Quoted By:

>>12102307
Yes ofc
7 questions 1 hour no time to check or rewrite anything
No real instruction
Just me and my arithmetic errors getting Fs and being laughed at for making gougable errors by a sadistic professor and his army of autismal midwits

Anonymous

Anonymous Wed 09 Sep 2020 19:14:32 No.12102367 Report

Quoted By: >>12102432

>>12102261
I'm the one who initially showed where you were wrong
>carrying the units
not important for this, unless your prof is autistic and wants it done
>organizing better
absolutely. your work looks like a stream-of-consciousness. at least try to make lines flow from one to another instead of having me guess where you're going with everything.
even if you box things and draw arrows from place to place that would be more helpful. or just write "get final y velocity" above your calculation for the final y velocity so I know what you're thinking of doing.

you can get easy partial credit by doing stuff like this, even when you get the answer wrong. because you're showing that you know what steps to be doing, which is really all they care about anyways.

Anonymous

Anonymous Wed 09 Sep 2020 19:26:37 No.12102404 Report

Quoted By:

>>12093348
>We can see about 14.5 billion light years in all directions
Wrong.

Anonymous

Anonymous Wed 09 Sep 2020 19:37:32 No.12102432 Report

Quoted By: >>12102443

>>12102367
it is. Its only there for me to keep track of things. If I had more time I could rewrite but I don't. Ive failed both quizzes now due to the time factor alone, and i work quickly. These weekly quizzes are 43% of the grade and they're organized st u need to have mastered the material to get an A. Theyre some of the hardest questions you could ask on the material, and he has fucking gotchas and tries to trick you, which wow is really easy to do under time pressure. I'm likely to drop and take this from someone who is a bit younger, a bit more professional, and doesn't care about anything but students doing the work and getting it, not being precisely like the professor himself. I'm curious what justifications people can cook up for this teaching style, because it's only idiots who would do similarly if in a tenured position
He fooled me and made me think this weeks quiz was on free body diagrams and friction not 2d motion. This situation is severely depressing, nobody can justify that 3 as reflective of performance, but that 3 isn't illegal, and nobody exists to hold him accountable anyway
I mean look at the feedback I got, "this is wrong". Say what u will about my writing, but he didn't say anything about my work. He just said its wrong. Wtf kind of person am I dealing with here? Someone whose career summitted at teaching highschool burnouts high-school algebra in a weedout course and he's gonna be a demon. Its 2020 i can take this remotely from anyone else in the state
I don't expect anyome to read this I m just venting its a very frustrating position to be in

Anonymous

Anonymous Wed 09 Sep 2020 19:39:24 No.12102443 Report

Quoted By:

>>12102432
I agree that the prof is a twat, courses organized like this generally aren't worth the headache.

Anonymous

Anonymous Wed 09 Sep 2020 19:41:45 No.12102455 Report

Quoted By: >>12102459

If you have an unknown substance how do you find out what it is?

Anonymous

Anonymous Wed 09 Sep 2020 19:42:12 No.12102459 Report

Quoted By: >>12102467

>>12102455
taste it

Anonymous

Anonymous Wed 09 Sep 2020 19:44:01 No.12102467 Report

Quoted By: >>12102469

>>12102459
tastes like nothing

Anonymous

Anonymous Wed 09 Sep 2020 19:44:46 No.12102469 Report

Quoted By: >>12102497

>>12102467
have you considered it might be nothing then?

Anonymous

Anonymous Wed 09 Sep 2020 19:49:32 No.12102497 Report

Quoted By: >>12102512

>>12102469
it is gray stuff though

Anonymous

Anonymous Wed 09 Sep 2020 19:51:58 No.12102512 Report

Quoted By: >>12102524 >>12102530

>>12102497
Is it flammable?

Anonymous

Anonymous Wed 09 Sep 2020 19:55:08 No.12102524 Report

Quoted By:

>>12102512
not with a lighter

Anonymous

Anonymous Wed 09 Sep 2020 19:56:10 No.12102530 Report

Quoted By: >>12102541

>>12102512
how do you do it in generel?
like in a lab

Anonymous

Anonymous Wed 09 Sep 2020 19:58:58 No.12102541 Report

Quoted By: >>12102552

>>12102530
With a flame

Anonymous

Anonymous Wed 09 Sep 2020 20:02:18 No.12102552 Report

Quoted By: >>12102582

>>12102541
there are like a hundred elements and putting a flame to it tells you what it is?

Anonymous

Anonymous Wed 09 Sep 2020 20:12:06 No.12102582 Report

Quoted By: >>12102597

>>12102552
if you're not trolling, there's no general process to determine what something is. you have to use a baseline level of inference, but you start with stuff like weighing it, getting the density, doing spectroscopy. stuff that doesn't destroy the sample or cause a potentially dangerous reaction.

Anonymous

Anonymous Wed 09 Sep 2020 20:17:07 No.12102597 Report

Quoted By: >>12102600 >>12102602

>>12102582
So I need to do a shitton of tests and narrow this down?
This sucks.

Anonymous

Anonymous Wed 09 Sep 2020 20:18:30 No.12102600 Report

Quoted By: >>12102613

>>12102597
what are you expecting? unknown compound #598234 can be entirely determined from just looking at it? come on dude

Anonymous

Anonymous Wed 09 Sep 2020 20:19:12 No.12102602 Report

Quoted By: >>12102613

>>12102597
If it doesn't explode and it's not poisonous it's probably boring anyway

Anonymous

Anonymous Wed 09 Sep 2020 20:23:01 No.12102613 Report

Quoted By:

>>12102600
I just hoped there was a run of the mill method to get some results in medium amount of time.

>>12102602
Probably.

Anonymous

Anonymous Wed 09 Sep 2020 20:25:52 No.12102621 Report

Quoted By: >>12102625

I forgot question I wanted to ask. Can someone travel back in time and remind me what question I wanted to ask? It was really important or I wouldn't have thought about it!

Anonymous

Anonymous Wed 09 Sep 2020 20:27:29 No.12102625 Report

Quoted By:

>>12102621
You wanted to know if there was any scientific knowledge about memory improvement.

Anonymous

Anonymous Wed 09 Sep 2020 20:44:08 No.12102666 Report

Quoted By: >>12102679

How do i tell how much sugar is in a liquid by volume?

Anonymous

Anonymous Wed 09 Sep 2020 20:48:23 No.12102679 Report

Quoted By: >>12102690

>>12102666
You take the sugar per volume and multiply it by volume

Anonymous

Anonymous Wed 09 Sep 2020 20:52:15 No.12102690 Report

Quoted By: >>12102693

>>12102679
idk how much sugar is in it period
what im asking is if there is some kind of test i can do to see what % of a liquid is sugar

Anonymous

Anonymous Wed 09 Sep 2020 20:52:51 No.12102693 Report

Quoted By: >>12102695

>>12102690
dry out a part of the liquid and weigh the sugar

Anonymous

Anonymous Wed 09 Sep 2020 20:53:37 No.12102695 Report

Quoted By: >>12102703 >>12102705

>>12102693
there wont be non sugar solids left over?

Anonymous

Anonymous Wed 09 Sep 2020 20:56:13 No.12102703 Report

Quoted By:

>>12102695
dude if you have a generic mixture there's no fucking way to tell what's in it specifically without running a bunch of tests

Anonymous

Anonymous Wed 09 Sep 2020 20:56:28 No.12102705 Report

Quoted By:

>>12102695
Depends on the liquid obviously

Anonymous

Anonymous Wed 09 Sep 2020 21:00:33 No.12102720 Report

Quoted By:

Does ammonium destroy DNA samples?

Anonymous

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Anonymous Wed 09 Sep 2020 21:02:14 No.12102728 Report

Quoted By:

given a refracting surface I have to show that to produce a perfect image that the surface must satisfy the general equation of a bivariate quadratic. I can understand the reasoning behind it as the light rays further from the middle must be compensated for their vertical dimension to have the same optical path length of the middle rays, but Im not exactly sure how I would take this and get to an equation exactly.

would i just set the optical path lengths equal to each other and it will get to that equation?

Anonymous

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Anonymous Wed 09 Sep 2020 21:10:06 No.12102747 Report

Quoted By: >>12102768

Is this notation for the slope acceptable?

Another question, clearly the slope is negative, but should I put the negative sign on either A or B or is it understood?

Anonymous

Anonymous Wed 09 Sep 2020 21:16:23 No.12102766 Report

Quoted By:

>>12093136
Even as a layman I think the stuff coming out of this place is super super amazing

Anonymous

Anonymous Wed 09 Sep 2020 21:17:35 No.12102768 Report

Quoted By:

>>12102747
I'd call it $\Delta x,\Delta y$ or dx,dy or something, but it should be alright
You can write A/B<0 if you want, but unless the picture is meant for children your audience should understand it.

Anonymous

Anonymous Wed 09 Sep 2020 23:30:08 No.12103247 Report

Quoted By: >>12103256

how to stop being so horny all the time?

Anonymous

Anonymous Wed 09 Sep 2020 23:31:44 No.12103256 Report

Quoted By: >>12103292

>>12103247
cut off porn stop masturbating
stick to this for 2 months

Anonymous

Anonymous Wed 09 Sep 2020 23:36:08 No.12103274 Report

Quoted By:

Anyone familiar with writing exercises in an interview?
I have an interview for an engineering assistant position and they said there will be a writing exercise after the interview. What should I expect?

Anonymous

Anonymous Wed 09 Sep 2020 23:39:48 No.12103292 Report

Quoted By: >>12103300

>>12103256
Ive actually had several spells where I stopped masturbating and watching porn for 5-7 months and if was awful for my productivity.
it actually only made things worse because I got very pent up and had crazy boners while trying to work.
at least when Im jacking off with consistency I can save my horniness for when Im done with my tasks

Anonymous

Anonymous Wed 09 Sep 2020 23:41:27 No.12103300 Report

Quoted By: >>12103314 >>12103321

>>12103292
idk go on antidepressants, those killed my urge to coom for a year

Anonymous

Anonymous Wed 09 Sep 2020 23:46:21 No.12103314 Report

Quoted By:

>>12103300
eh, I'd rather not take any mind-altering drugs. I'll stick with being horny. I was only concerned because I'd spend 40 minutes a day jacking off when I could be doing more productive things but Id take that over the takepills-pill

Anonymous

Anonymous Wed 09 Sep 2020 23:49:10 No.12103321 Report

Quoted By: >>12103337

>>12103300
That’s not good. You’re a fucking human, you’re supposed to be horny

Anonymous

Anonymous Wed 09 Sep 2020 23:53:01 No.12103337 Report

Quoted By: >>12103352

>>12103321
yeah well I'd take not being horny over my ability to be able to actually get up and go do things any day

Anonymous

Anonymous Wed 09 Sep 2020 23:58:05 No.12103352 Report

Quoted By: >>12103355

>>12103337
That’s a you problem. Poor self control and addicted to porn. Don’t blame human nature to your own problems.

Anonymous

Anonymous Wed 09 Sep 2020 23:59:35 No.12103355 Report

Quoted By:

>>12103352
I'm not the person who initially asked. I said this in the context of taking antidepressants being preferable to depression if all I have to give up is jerking off each day

Anonymous

Anonymous Thu 10 Sep 2020 00:05:39 No.12103370 Report

Quoted By: >>12103392

>If you start with two sinusoidal waves of the same amplitude traveling in phase on a string and then somehow phaseshift one of them by 5.4 wavelengths, what type of interference will occur on the string?
The answer was "Intermediate (closer to fully destructive)," Could someone explain to me what does "intermediate" mean? And how come it was fully destructive? I thought if they were both travelling in phase with each other, they would add up and become constructive wouldn't it?

Anonymous

Anonymous Thu 10 Sep 2020 00:14:58 No.12103392 Report

Quoted By: >>12103408

>>12103370
translating one wavelength (or any multiple of) will yield constructive interference, since they overlap
translating one half-wavelength (or any n+1/2) will yield destructive interference.
5.4 is close to 5.5 which would be fully destructive, meaning the waves perfectly cancel out at every point.
>I thought if they were both travelling in phase with each other, they would add up and become constructive wouldn't it?
this is true, but then you shift the peak of one by 5.4 wavelengths, so they're no longer in phase.

Anonymous

Anonymous Thu 10 Sep 2020 00:18:52 No.12103408 Report

Quoted By:

>>12103392
Aaaaaaah, that makes so much more sense. Thank you so much anon, I'll write this down on paper and then review it again tomorrow!

Anonymous

Anonymous Thu 10 Sep 2020 00:33:26 No.12103459 Report

Quoted By:

new bread: >>12103457

Anonymous

Anonymous Thu 10 Sep 2020 06:20:50 No.12104291 Report

Quoted By:

>>12096470
You're OK, especially if you already smoke, then it won't matter cancerwise either

Anonymous

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Anonymous Thu 10 Sep 2020 10:13:35 No.12104628 Report

Quoted By:

Am I a brainlet here? Surely 20% more reach than 42% is 62% right?

If the question was 20% bigger/larger then I do 42%*20%, but the question says 20% more.

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