solution to the frog problem: the possible combinations of the two frogs behind you are:
MM
MF
FM
FF
it cannot be FF, so we're left with
MM
MF
FM
now a mindless retard "i fucking love science" brainlet would look at this and say that the probability is 1/3, but anyone with a brain can see that either MF or FM would also be impossible. MF has a 50% chance of being a Possible combination and FM also has a 50% chance of being a possible combination, meaning that both of them have a 100% chance of being a possible combination. let's call both of them MF/FM, MM also has a 100% chance of being a possible combination, if we take into account the chance of each combination actually being possible, it is easy to see that the probability of MM is equal to the probability of MF/FM, so there is a 50% chance of a female frog being behind you